MATHEMATICS HIGH SCHOOL

Jonas is planning out his route for an upcoming race. He uses negative numbers to represent points beforethe finish line and positive numbers to represent points after the finish line.On Jonas's map, there is a bridge at -91= meters, and his wife is watching him at 14 meters.What does 0 meters represent?Choose 1 answer:Jonas's wifeB. The bridgeThe finish line​

Answers

Answer 1
Answer:

Answer:

(C)The finish line

Step-by-step explanation:

Points before the finish line are represented using negative numbers.

Points after the finish line are represented using positive numbers.

  • The bridge is at -91 meters ( before the finish line)
  • His wife is watching him at 14 meters. (after the finish line)

0 meters therefore represents the finish line from which Jonas takes his reading to be positive or negative.

The correct option is C.
Answer 2
Answer:

Final answer:

The 0 meters in Jonas's map represents the finish line in the race, where negative numbers represent points before the finish line and positive numbers represent points after the finish line.

Explanation:

In Jonas's case, he has defined the finish line as 0 meters. This is based on his system of defining the race route, where negative numbers represent points before the finish line and positive numbers represent points after the finish line. So, his wife watching him at 14 meters would be positioned 14 meters past the finish line, and the bridge at -91 meters would be 91 meters before the finish line. This is a useful way of tracking his position during the race and helps to structure his training and race strategy.

Learn more about Number Line here:

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Find the remainder when f(x) is divided by (x - k) f(x) = 5x4 + 8x3 + 4x2 - 5x + 67; k = 2

The area of the triangle is 56 m2. Find the length of the base.

Answers

 you need to know the formula to find out area first.

Area = (1/2)* base*height


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Use the function below to find f(-2)f(x)=5^x
A. 1/10
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C. -25
D. -10

Answers

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Suppose you choose a marble from a bag containing 3 red marbles, 3 white marbles, and 5 blue marbles. You return the first marble to the bag and then choose again. Find P(red and blue).

Answers

The answer is 15/121.

Since we have red AND blue, that means that both of these events occur, so we will use the multiplication rule and multiply these two probabilities:

- A probability of choosing a red marble: 3/11. (because there are 3 marbles out of total 11 marbles)
- A probability of choosing a blue marble after the red one: 5/11. (because there are 3 marbles out of total 11 marbles; there are 11 in total again because the first marble has been returned)

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There are white, red and blue cars in a parking lot. The number of each colour car is a factor of 36. There are twice as many white cars as red cars. The number of blue cars is twice that of black cars. The number of black cars is the product of two different prime numbers. The number of red cars is a square number that is not a multiple of 2. If there are 45 cars in the parking lot, calculate how many cars of each colour there are.

Answers

Black = 2*3 = 6 cars;
Blue = 2*2*3 = 12 cars;
Red = 3^(2) cars;
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black + blue + red + white = 45 cars.

Answer:

45 cars.

Step-by-step explanation:

For black, 2*3=6 cars.

For blue, 2*2*3=12 cars.

For red 3 to the power of 2= 6 cars;

For white, 2*9=18 cars;

The number of each color would be a factor of 36. This means that all the cars being added equals 42.

In general, when a number written in scientific notation includes a positive exponent, the absolute value of that number is __________.

Answers

In general, if a number is written in a scientific notation which includes an exponent that is positive, the absolute value of that number is positive. This is because if the number is bigger than 1 and it is in absolute value, then that means it is a positive number.
positive exponents are big numbers; so your number gets bigger

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Answers

f(x)=2x-6\n y=2x-6\n 2x=y+6\n x=(1)/(2)y+3\n f^(-1)(x)=(1)/(2)x+3\n f^(-1)(2)=(1)/(2)\cdot2+3\n f^(-1)(2)=1+3\n f^(-1)(2)=4
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y=2x-6\n \n x=2y-6\n \n 2y=x+6\n \n y=(x+6)/(2)\n \n \boxed{f^(-1)(x)=(x+6)/(2)}

b) Calculating f⁻¹(2)

\boxed{\boxed{f^(-1)(2)=(2+6)/(2)=(8)/(2)=4}}
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