(38x+61y)-(3x-11y) simplify this expression

Answers

Answer 1
Answer:

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▹ Answer

35x + 72y

▹ Step-by-Step Explanation

(38x + 61y) - (3x - 11y)

38x + 61y - (3x - 11y)

38x + 61 y - 3x + 11y

35x + 61y + 11y

35x + 72y

Hope this helps!

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A rectangular fish tank contains 3,240 cubic inches of water. The dimensions of the base of the fish tank are 12 inches x 18 inches. How tall is the fish tank?

Answers

Answer:

fish tank is 14.87 ≈ 15  inches tall.

Step-by-step explanation:

Given  : A rectangular fish tank contains 3,240 cubic inches of water. The dimensions of the base of the fish tank are 12 inches x 18 inches.

To find  :  How tall is the fish tank.

Solution : We have given  that volume of fish tank  = 3240 cubic inches.

                                               Length of tank = 12 inches.

                                               Width of tank =  18 inches .

Volume of rectangular tank = length * width * height

3240  = 12 * 18* height .

3240 =  216 * height.

On dividing both side by 216 and switching the sides .

Height = (3240)/(216) .

Height =  14.87 inches  

Therefore,  fish tank is 14.87 ≈ 15  inches tall.

Volume = length x Base x height

3240 = 18 x 12 x H

 3240 = 216 x H

H = 3240 / 216 = 15 inches

If (-2, y) lies on the graph of y =4^x, then y =

Answers

Simply plug in x= -2 in to y = 4^x, and solve for y.

y=4^(-2)\n\ny = (1)/(4^2)\n\n\boxed{\bf{y=(1)/(16)}}

So, the point (-2, ¹/₁₆) lies on the graph of y = 4^x.

Your final answer is y = ¹/₁₆.

Identify the absolute extrema of the function and the x-values where they occur. f(x)=6x+(24/x^sqr)+3, x>0

Answers

f(x)=6x+(24)/(x^2)+3\nf'(x)=6-(48)/(x^3)\n6-(48)/(x^3)=0\n6x^3-48=0\n6x^3=48\nx^3=8\nx=2\n

For x<2 \wedge x\not=0 the derivative is negative.
For x>2 the derivative is positive.
Therefore at x=2 there's a minimum.

f_(min)=6\cdot2+(24)/(2^2)+3=12+6+3=21

Divide.


8.64÷(−0.27)


Enter your answer in the box.

Answers

The answer is -2.3328

When an apple is dropped from a tower 256 feet high, the function h(t) =-167 +256 models the height of theapple, in feet, after t seconds. Determine, algebraically, the number of seconds it takes the apple to hit the ground.

Answers

The apple dropping on the ground is an illustration of free fall.

It takes the apple 1.53 seconds to hit the ground

Given

h(t) = -167t + 256

When the apple hits the ground, we have:

h(t) = 0

Substitute h(t) = 0 in h(t) = -167t + 256

0 = -167t + 256

Collect like terms

167t = 256

Solve for t

t = (256)/(167)

t = 1.53293413174

Approximate

t = 1.53

Hence, the apple hits the ground after 1.53 seconds

Read more about free falls at:

brainly.com/question/10579318

Answer:

around 1.5 sec

Step-by-step explanation:

basically you wanna figure out at what time is the height=0

since h(t) represents height, set it to 0 then solve for t

i believe you might have forgotten the t in the equation so i assumed it was -167t

0=-167t+256

-256=-167t

t=1.53293413174

around 1.5 seconds after it was dropped

alternatively, you could plug the equation into desmos, replacing h(t) with y and t with x and find the x intercept

Find five rational numbers between - 1⁄3 and 1⁄3 (both are fractions : negative one third and positive one third)

Answers

1/4,1/5,1/10,1/20,1/40