I need help on another one 17

Answers

Answer 1

Answer: the answer is 0.75 hope it helps

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Factor the polynomial 6b^2-17b+10

Answers

$6b ^ 2-17b +10 \n \n\Delta = b^(2)-4ac = (-17)^(2)-4*6*10=289-240=49\n \nx_(1)=(-b-√(\Delta ))/(2a) =(17- √(49))/(2*6)=(17-7)/(12)= (10)/(12)=(5)/(6)\n \nx_(2)=(-b+√(\Delta ))/(2a) =(17+ √(49))/(2*6)=(17+7)/(12)= (24)/(12)=2 \n \n Answer : \ x=(5)/(6) \ \ or \ \ x=2$

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 5 cos 5θ

Answers

Short answer. X axis. This is a teaching lesson intended to show you what the odd and even graphs look like.
Remark
You should always try to draw these kinds of questions using a graphing calculator or some sort of program on the internet that imitates a graphing calculator. Begin by looking at the diagram on the left. Are there any clues which one you should pick?

There are. Notice the "leaf" that's on the plus x axis. It looks the same on both sides of the x axis.

There are 4 other leaves. Do they confirm your suspicion? They should. The next leaf counter clockwise above the one on the x axis is the mirror image of the leaf that is next clockwise to the one symmetrical about the x axis. Those two are mirror images.

Comment
What would happen if you were give an even number of leaves? Try 4.
r = 5*cos(4 theta). Notice that 2n leaves are produced (2*4 = 8 in this case). Notice also that you have a symmetry for the origin.

Finally
If the topic interests you, go to desmos and try r = 5*sin(4*theta) and r = sin(5*theta). Are there any differences?

Remember to be working in polar coordinates in desmos.

Answer:

x-axis

Step-by-step explanation:

r=4 cos⁡5θ

∙Subsitute (r,-θ)in the given function

4 cos⁡〖5θ=4 cos⁡5(-θ) 〗,then r(θ)=r(π-θ)

∴Thus,it is symmetric about x-axis.

Since

4 cos⁡〖5θ≠-4 cos⁡5(π-θ) 〗

∴Thus,it is not symmetric about y-axis.

∙Since

4 cos⁡〖5θ≠-4 cos⁡5(π+θ) 〗

∴Thus,it is not symmetric about the origin

Solve by substitution. Show each step of your work.

2x + y = 7

3x + 5y = 14

Answers

Alright...simple...showing all steps.. ;)

You have the equations...

2x+y=7
and
3x+5y=14

To be able to even solve for any of the variables...multiply the equations by...2...and..3...

2x+y=7----*3--> 6x+3y=21
and
3x+5y=14-----*2--->6x+10y=28

Thus,

6x+3y=21
-
6x+10y=28

=========

-7y=-7

y=1

Now, plug y back into any of the original equations....we'll use 2x+y=7 in this case....

2x+(1)=7

2x+1=7
-1 -1

2x=6

x=3

Thus, the point of intersection for these two equations is (3,1)

Solve 3y + 20 = 3 +2y

Answers

3y + 20 = 3 + 2y

3y- 2y = 3-20

y = -17

3y+ 20= 3+ 2y
⇒ 3y -2y= 3 -20 (inverse operation)
⇒ y= -17

Final answer: y= -17.

What is the value of the expression -3x^2y + 4x when x=-4 and y=2

Answers

Answer:-785

Step-by-step explanation:

(4,?) is on the line 8x – 3y = -10. Find the other half of the coordinate

Answers

(4, ?) is on 8x - 3y = -10

The ? is the missing y coordinate. (4, y) satisfies 8x - 3y = -10

8x - 3y = -10. From point (4, y), we would replace x = 4 in the equation below. y remains the unknown.

8*4 - 3y = -10

32 - 3y = -10

-3y = -10 - 32

-3y = - 42

y = -42/-3

y = 14

We need to plug 4 in place of x into the equation of the line and find the y-value.

8x - 3y = -10
8(4) - 3y = -10
32 - 3y = -10

Add 3y on both sides.

32 = -10 + 3y

Add 10 on both sides.

42 = 3y

Divide 3 on both sides.

y = 14

The point is (4, 14).

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