3. A particle of charge +7.5 µC is released from rest at the point x = 60 cm on an x-axis. The particle begins to move due to the presence of a charge ???? that remains fixed at the origin. What is the kinetic energy of the particle at the instant it has moved 40 cm if a) ???? = +20 µC and b) ???? = −20 µC?

Answers

Answer 1

Answer:

Answer:

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Explanation:

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A block of mass m slides with a speed vo on a frictionless surface and collides with another mass M which is initially at rest. The two blocks stick together and move with a speed of vo /3. In terms of m, mass M is most nearly_____.
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Two workers are sliding 300 kg crate across the floor. One worker pushes forward on the crate with a force of 400 N while the other pulls in the same direction with a force of 290 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor
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A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.When it reaches the highest point of its trajectory, its speed is150 m/s. In a second trial with the same projectile, the initialspeed is the same but the angle is now 37 degree with thehorizontal. At its highest point in this trajectory, the velocityof the projectile would be what?

Answers

Answer:

v₂ = 176.24 m/s

Explanation:

given,

angle of projectile = 45°

speed = v₁ = 150 m/s

for second trail

speed = v₂ = ?

angle of projectile = 37°

maximum height attained formula,

$H_(max)= (v^2 sin^2(\theta))/(g)$

now,

$H_(max)= (v_1^2 sin^2(\theta_1))/(g)$

$H_(max)= (v_2^2 sin^2(\theta_2))/(g)$

now, equating both the equations

$(v_2^2)/(v_1^2)=(sin^2(\theta_1))/(sin^2(\theta_2))$

$(v_2^2)/(150^2)=(sin^2(45^0))/(sin^2(37^0))$

v₂² = 31061.79

v₂ = 176.24 m/s

velocity of projectile would be equal to v₂ = 176.24 m/s

If half the kinetic energy of the initially moving object (m1m1) is transferred to the other object (m2m2), what is the ratio of their masses? Express your answers using three significant figures separated by a comma.

Answers

Answer:

0.25( m1m1) , 0.75( m2m2)

Explanation:

Noted the formula for kinetic energy is 1/2(Mass × Velocity).

Therefore the original value of the mass is 0.5, giving half away makes it 0.25 to another mass which is primarily 0.5. This now makes the new mass 0.25+0.5=0.75.

Thank you.

The height of the upper falls at Yellowstone Falls is 33 m. When the water reaches the bottom of the falls, its speed is 26 m/s. Neglecting air resistance, what is the speed of the water at the top of the falls?

Answers

Answer:

Speed of water at the top of fall = 5.40 m/s

Explanation:

We have equation of motion

$v^2=u^2+2as$

Here final velocity, v = 26 m/s

a = acceleration due to gravity

$a=9.8m/s^2 \n$

displacement, s = 33 m

Substituting

$26^2=u^2+2* 9.8 * 33\n\nu^2=29.2\n\nu=5.40m/s \n$

Speed of water at the top of fall = 5.40 m/s

A 1.5m wire carries a 7 A current when a potential difference of 87 V is applied. What is the resistance of the wire?

Answers

Answer:

$R\approx12.43 \,\, \Omega$

Explanation:

We can use Ohm's Law to find the resistance R of a wire that carries a current I under a given potential difference:

$V=I\,\,R\nR = (V)/(I) \nR=(87)/(7) \nR\approx12.43 \,\, \Omega$

Answer:

Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.

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What operation do you apply to the position function of a particle to compute the particles velocity