Of the last 100 customers entering a computer shop, 25 have purchased a computer. If the relative frequency method for computing probability is used, the probability that the next customer will purchase a computer is

Answers

Answer 1

Answer:

Answer: 0.25

Step-by-step explanation:

The relative frequency of the customers that buy computers is equal to the number of customers that bought a computer divided the total number of customers that entered the shop.

p = 25/100 = 0.25

If we take this as the probability, then the probability that the next customer that enters the shop buys a computer is 0.25 or 25%

Answer 2

Answer:

Final answer:

The probability that the next customer will purchase a computer, computed using the relative frequency method, is 0.25 or 25%.

Explanation:

The subject at hand relates to the basic concept of probability, specifically the method of computing probability using the relative frequency approach. This is a common topic within high school Mathematics, specifically within statistical studies.

To calculate the relative frequency probability of an event, one divides the number of times the event occurred by the total number of trials. In this case, the event is a customer purchasing a computer from the shop. Given that the event has occurred 25 times out of the last 100 trials (customers entering the shop), the relative frequency probability can be computed as follows:

Probability = (Number of times event occurred) / (Total number of trials) = 25 / 100 = 0.25 (or 25% when expressed as a percentage).

Therefore, using the relative frequency method of computing probability, the probability that the next customer will purchase a computer is 0.25 or 25%.

Learn more about Probability here:

brainly.com/question/22962752

#SPJ3

Related Questions

hector works 12 hours a week at a part time job. His original pay rate was $8 per hour but he recently received a pay raise of x dollars an hour. his new total weekly pay, y, is represented by the equaiton y=12(8+x)
What’s the simplified fraction is equal to 0.17
PLZ HELP FAST looks easy
Is y = x/9 a direct variation
I need help urgently!!José writes this problem:675 divided by 1600Which expressions can be used to represent this problem?Select each correct answer.A) 675 ÷ 1600B) 1600 ÷ 675 C) 1600675 D) 6751600 E) 1600675 F) 6751600

Jacob made a banner for a sporting event in the shape of a parallelogram. The area of the banner is 127 1/2 square centimeters. The height of the banner is 4 1/4 centimeters. What is the base of the banner?

Answers

Answer:30

Step-by-step explanation: its 30 because you divide 127 1/2 or 127.5 by 4.25 or 4 1/4.

BRAINLIEST AND FIVE STARS TO CORRECT ANSWER

Answers

Note that the first function is f(x) = 4 for x less than 2 and for the second function f(x) = -1 for x greater than or equal to 2

So the limit as x approaches two from the left is 4 and the limit as x approaches 2 from the right is -1.

so looks like you would need the third choice: 4; -1

Please help me solve this!

Answers

Answer:

Step-by-step explanation:

a) AB=2AM

A__________M__________B

If M is the midpoint of AB, then AM = MB

Since AM=MB MB=2AM

Therefore AB=2AM

b)AM=1/2MB

sincs M is midpoint of AB.

then AM=BM....(1)

and also AM+BM=AB

AM+AM=AB from (1)..AM=BM

2AM=AB

AM=1/2AB

In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is . Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?

Answers

Completed question:

In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?

Answer:

0.557

Step-by-step explanation:

For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:

0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443

Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:

1 - 0.443

0.557

Paired t‐Test for Mean Comparison with Dependent Samples To study the effects of an advertising campaign at a supply chain, several stores are randomly selected with the following observed before‐ and after‐advertising monthly sales revenues: Store number 1 2 3 4 5
Old sales revenue (mil. $) 5.2 6.5 7.2 5.7 7.6
New sales revenue (mil. $) 6.4 7.8 6.8 6.5 8.2
Let μ₁ and μ₂ be the means of old and new sales revenues, both in millions of dollars per month.
(a) At α = 0.05, test H0: μ2 ≤ μ1 versus H1: μ2 > μ1. Sketch the test. Interpret your result.
(b)Sketch and find the p‐value of the test. Would you reject H0 if α = 0.01?

Answers

Answer:

a) $t=(\bar d -0)/((s_d)/(√(n)))=(0.7 -0)/((0.678)/(√(5)))=2.308$

$p_v =P(t_((4))>2.308) =0.0411$

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

b) The p value is illustrated on the figure attached.

If we select $\alpha=0.01$ we see that $p_v >\alpha$ so then we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Part a

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

1=test value old , 2 = test value new

1: 5.2 6.5 7.2 5.7 7.6

2: 6.4 7.8 6.8 6.5 8.2

The system of hypothesis for this case are:

Null hypothesis: $\mu_2- \mu_1 \leq 0$