Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is . For one performance, advance tickets and same-day tickets were sold. The total amount paid for the tickets was . What was the price of each kind of ticket

Answers

Answer 1

Answer:

Advance tickets=$25

Same-day tickets=$15

Step-by-step explanation:

Complete question below:

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?

Let

advance tickets=x

Same-day tickets=y

Combined cost of advance and same-day tickets=$40

It means,

x+y=40 Equ (1)

25 advance tickets and 30 same-day tickets=$1075

It means,

25x+30y=1075 Equ(2)

From (1)

x+y=40

x=40-y

Substitute x=40-y into (2)

25x+30y=1075

25(40-y)+30y=1075

1000-25y+30y=1075

5y=1075-1000

5y=75

Divide both sides by 5

5y/5=75/5

y=15

Recall,

x+y=40

x+15=40

x=40-15

=25

x=25

Advance tickets=$25

Same-day tickets=$15

Check

25x+30y=1075

25(25)+30(15)=1075

625+450=1075

1075=1075

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How do I simplify this?

Answers

Don't get too involved in the 'simplify' part just yet.
It doesn't mean make the problem easier.
It means that when you have the answer, make sure it's in simplest form.
That's why it says "Simplify your answer".
Notice that that's the 2nd instruction.
There's nothing to simplify until you have an answer.

The first thing you have to do here is find the area of a triangle.
Do you remember that formula ?
I'll bet you do.
The area of a triangle is (1/2) · (length of the base) · (height) .

The height and the length of the base are given, right there
in the picture. Take those, and use them to find the area.

Once you've multiplied the binomials, don't forget about the (1/2).

Finally, you have a trinomial for an answer.
Put the big sweet cherry on top: Factor it !
I think that's the 'simplify' part.

You may be surprised.
I was when I worked it out just now ... just for you.

Sin inverse[sin 6pi/7]. I'm suppose to find the exact value.

Answers

$sin^(-1) (sin (6 \pi )/(7) )= (6 \pi )/(7)$

6r+7=13+7r
how do you solve this?

Answers

Simplifying 6r + 7 = 13 + 7r Reorder the terms: 7 + 6r = 13 + 7r Solving 7 + 6r = 13 + 7r Solving for variable 'r'. Move all terms containing r to the left, all other terms to the right. Add '-7r' to each side of the equation. 7 + 6r + -7r = 13 + 7r + -7r Combine like terms: 6r + -7r = -1r 7 + -1r = 13 + 7r + -7r Combine like terms: 7r + -7r = 0 7 + -1r = 13 + 0 7 + -1r = 13 Add '-7' to each side of the equation. 7 + -7 + -1r = 13 + -7 Combine like terms: 7 + -7 = 0 0 + -1r = 13 + -7 -1r = 13 + -7 Combine like terms: 13 + -7 = 6 -1r = 6 Divide each side by '-1'.

the bill came to $136.40 The patrons decided to leave a 15% tip what was the total bill including the tip