PLEASE HELP: A particle contains 25 protons and 23 electrons. What type of electric charge does the particle have?
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Answer:In physics, a charged particle is a particle with an electric charge. It may be an ion, such as a molecule or atom with a surplus or deficit of electrons relative to protons. It can also be an electron or a proton, or another elementary particle, which are all believed to have the same charge (except antimatter).
Explanation:
Answer:
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Explanation:
Related Questions
Consider the car driving around a circular track. Once started, the driver maintains a speed of 45 m/h. Compare the driver's velocity with his acceleration in this case.A) The car is accelerating because it is changing direction but the velocity isconstant.B) The car is traveling at a constant rate of speed so it is not accelerating andthe velocity does not change.C) Acceleration is the change in velocity so the car is experiencing a changein velocity and it is accelerating.D) The car is traveling at a constant rate of speed so it is not accelerating butthe velocity changes because the direction the car travels is constantlychanging
what issues might arise in determining the latent heat of something that sublimes in comparison to something that melts
The earth takes 1 year to revolve around the sun at 1 A.U. distance (an astronomical unit = 93,000,000 miles). If a planet were 4 A.U. from the sun, how many years would it take to make 1 orbit?
What 2 events increase power output
-32.7° below the horizontal.
What is the normal force on the cart?
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Answer:
The "normal force" on the "cart" 63.893 N.
Explanation:
To find normal force on the cart, use the equation
Normal force = mg + F sinx,
“m” being the object's mass,
“g” being the acceleration of gravity,
“x” being the angle of the cart
Given values
M = 7.33 kg
F = 14.7 N
Substitute the values in above equation
Normal force = (7.33 × 9.8) + 14.7 sin(-32.7°)
Normal force = 71.834 + 14.7 × (-0.5402)
Normal force = 71.834 - 7.94094
Normal force = 63.893 N
The "normal force" on "the cart" 63.893 N.
The normal force on the cart is 79.7 N
Explanation:
In order to find the normal force, we have to analyze the forces acting on the cart on the vertical direction.
In the vertical direction, we have the following forces:
The weight of the cart, downward, of magnitude , where m is the mass of the cart and g is the acceleration of gravity
The normal force on the cart, upward, we indicate it with N
The component of the pushing force acting in the vertical direction, downward, of magnitude , where F is the magnitude of the force and is the angle of the force with the horizontal
Therefore, the equation of the forces on the cart in the vertical direction is:
where the net force is zero since the cart is balanced in the vertical direction. We have:
We take the angle as positive since we are already considering the downward direction in the equation.
Substituting and solving for N, we find the normal force:
Learn more about forces:
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Answer:
A) equal to
In a closed system, the total energy prior to an energy transformation is equal to the total energy after.
Explanation:
A closed system is defined as an isolated region surrounded by a boundary across which no transfer of matter or energy can take place.
Hence, even if there is an energy transformation in a closed system, the overall energy of the closed system remains constant.
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Answer:
126 kmh⁻¹
Explanation:
We can simply solve this by applying motion equations
where
v - final velocity
u - initial velocity
a-acceleration
t - time
v = u + at
= 25 + 5×2 = 35 ms⁻¹
= (35/1000)×3600 = 126 kmh⁻¹
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A golfer hits a 45 g golf ball during 2.0 × 10⁻³ s causing its final speed to be 38 m/s. The impulse of the golf ball is 1.7 kg.m/s. The average force that the club exerts on the golf ball is 850 N and the average force that the golf ball exerts on the club is -850 N.
A golfer hits a 45 g (m) golf ball resting on a tee so that the golf ball leaves the tee at the horizontal speed of 38 m/s (v). To answer the questions, we need to consider the concepts of impulse and linear momentum.
What is impulse?
Impulse (I) equals the average net external force (F) multiplied by the time (t).
I = F × t [1]
What is linear momentum?
Linear momentum (p) is defined as the product of a system's mass (m) multiplied by its velocity (v).
p = m × v [2]
What is the relation between impulse and linear momentum?
The impulse experienced by the object equals the change in the linear momentum of the object.
I = F × t = m × Δv [3]
The impulse of the golf ball
We will use the equation [3], considering that Δv = v because it starts from the rest.
I = m × v = 0.045 kg × 38 m/s = 1.7 kg.m/s
The average force that the club exerts on the golf ball
The club and the golf ball are in contact for 2.0 × 10⁻³ s (t). We will calculate the average force that the club exerts on the golf ball (Fcg) using the equation [1].
I = Fcg × t
Fcg = I / t = (1.7 kg.m/s)/(2.0 × 10⁻³ s) = 850 N
The average force that the golf ball exerts on the club
According to Newton's third law of motion, action and reaction have the same value and opposite signs. Thus, the average force that the golf ball exerts on the club (Fgc) is -850 N.
A golfer hits a 45 g golf ball during 2.0 × 10⁻³ s causing its final speed to be 38 m/s. The impulse of the golf ball is 1.7 kg.m/s. The average force that the club exerts on the golf ball is 850 N and the average force that the golf ball exerts on the club is -850 N.
Learn more about impulse here: brainly.com/question/904448
Answer:
Correct answer: (1) I = 1.71 kg m/s, (2) F = 855 N
Explanation:
Given:
The mass of the ball m = 45 g = 45 · 10⁻³ kg
Initial velocity V = 38 m/s
Contact time t = 2 · 10⁻³ s
(1) I = ?
The impulse is calculated according to the formula:
I = m · V = 45 · 10⁻³ · 38 = 1,710 · 10⁻³ = 1.71 kg m/s
I = 1.71 kg m/s
(2) F = ?
The average force is calculated according to the formula:
F = ΔI / Δt = 1.71 / (2 · 10⁻³) = 855 N
F = ΔI / Δt = 1.71 / (2 · 10⁻³) = 855 N
F = 855 N
God is with you!!!
B. molecules move more rapidly
C. there is no change in molecular motion
D. temperature remains unchanged
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There would be a change in the kinetic motion of the objects.
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Answer: The entangled players would move with a speed of 0.2 m/s in the direction direction of the motion of second soccer player.
Explanation:
From law of conservation of momentum,
Initial momentum of the closed system = final momentum of the closed system
Since, no external force is acting on the players, total momentum would be conserved.
m₁u₁+m₂u₂=(m₁+m₂)v
where, m₁ is the mass of one soccer player = 40 kg
u₁ is its initial velocity before collision = 4 m/s
m₂ is the mass of the other soccer player = 60 kg
u₂ is the initial velocity before collision = - 3 m/s (∵opposite direction)
After collision, the two players get entangled and hence move with the same final velocity v.
40 kg × 4 m/s - 60 kg × 3 m/s = (40 kg + 60 kg ) v
160 kg m/s - 180 kg m/s = 100 kg v
v = -0.2 m/s
Hence, the entangled players would move with a speed of 0.2 m/s in the direction direction of the motion of second soccer player.