If x + 3 is a multiple of 3, which of thefollowing is not a multiple of 3?
(A) x
(B) x + 6
(C) 6x + 18
(D) 2x + 6
(E) 3x + 5

Answers

Answer 1
Answer: The answer is E because if x+3=0 then x=-1 which is the multiple of 3x-1
1)x
we have x so its -3
2)x+6
-3+6=3 its a multiple of 3 (3x1)
3)6x+18
6(-3)+18
0 is a multiple of 3 (3x0)
4)2x+6
2(-3)+6
0 is a multiple of 3
5)3x+5
3(-3)+5
-1 is not a multiple of 3


Answer 2
Answer:

Answer:

If integer m is not a multiple of 3, which of the following must be true? ... of 2 let m=3K+2, (m+1)(m-1) = (3K+3)X(3K+1) is a not a multiple of 2

Step-by-step explanation:

m=4 or 5 satisfies the equation (m+1)(m-1) is a multiple of 3. Hence true.

m=4, (m+1)(m-1) = (4+1)(4-1)=15, not multiple of 2.


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A charity fair raised $6,000 by selling 500 lottery tickets. There were two types of lottery tickets: A tickets cost $10 each, and B tickets cost $60 each. How many tickets of each type were sold?

Answers

Let a be the tickets that cost 10 each and b the tickets that cost 60 each. So therefore, a + b = 500 and 10a + 60b = 6000. By substituting the given numbers, a will be equals to 480. So the tickets sold are: 480 tickets for 10 each and 20 tickets for 60 each. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. 

Answer:

on plato E. 480,20

Step-by-step explanation:

Evaluate x0 + y0 for x = 3 and y = 2.

Answers

Answer:

The value of given expression is 2

Step-by-step explanation:

Given: Expression is x^0+y^0

To find : Value of expression when x = 3 and y = 2

Consider,

x^0+y^0

To find value we put value of x = 3 and y = 2

\implies 3^0+2^0

Now we know that value of expression whose power 0 is 1 irrespective of value of base .i.e, a^0=1 ∀ a ∈ any no.

3^0=1\:and\:2^0=1

\implies 3^0+2^0 = 1 + 1

⇒ 2

Therefore, The value of given expression is 2

Good evening


x^0+y^0 for x=3 and y=2

First thing we need to do is to replace their value

3^0+2^0

Remember: Any number that raised to the zero power equal 1

so now we have

3^0=1 and y^2=1

1+1

= 2


I hope that's help :0


Any Questions /

 

Prove the diagonal connecting these vertex angles is perpendicular to the diagonal connecting the non-vertex angles

Answers

Seg BA is congr to seg BC and seg DA is cong to seg DC by given Seg BD is congr to seg BD by reflexive Tr. BAD is congr to tr. BCD by SSS

A cold front changes the temperature by -3 F each day. If the temperature started at 0 F, what will the temperature be after 5 days?

Answers

-15 F bc -3 x 5 is -15

if Cory is at the elephant and he walks 8 units up and 4 units right, where would he land? What are his new coordinates?

Answers

Answer: The new coordinates are (-2, 7)

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Reasoning:

The elephant is at location (-6,-1)

Move 8 units up and we move to (-6,7). Add 8 to the y coordinate while keeping the x coordinate the same.

Then we move 4 units to the right to arrive at (-2, 7). I added 4 to the x coordinate and kept the y coordinate the same.

There are no animals at this location, but Cory is between the giraffe and the deer. In other words, if you draw a line segment from the giraffe to the deer, then Cory's new location is on this line segment. He is closest to the giraffe.

The mean weight of trucks traveling on a particular section of I-475 is not known. A state highway inspector needs an estimate of the population mean. He selects and weighs a random sample of 49 trucks and finds the mean weight is 15.8 tons. The population standard deviation is 3.8 tons. What is the 95% confidence interval for the population mean?

Answers

Answer:

(14.7 , 16.9)

Step-by-step explanation:

it is given that \bar{x}=15.8 tons

σ=3.8 tons

n=49

at 95% confidence level α=1-.95=0.05

z_(\alpha )/(2)=z_(0.05)/(2)=z_(0.025)\n

=1.96 ( from the standard table)

at 95% confidence level the coefficient interval for μ is

\bar{x}\pm z_(\alpha )/(2)* (\sigma )/(√(n))

15.8\pm 1.96* (3.8)/( √(49))

15.8\pm 1.1

(14.7, 16.9)