50.0ml each of 1.0M Hcl and 1.0M Naoh at room temperature (20.0c) are mixed the temperature of the resulting Nacl solutions increase to 27.5cthe density if the resulting Nacl solutuion 1.02 g/ml
the specific heat of the resulting Nacl solutions is 4.06j/gc
calculate the heat of neutralisation of hcl and naoh in kj/mol nacl products​

Answers

Answer 1
Answer:

Answer:

62.12kJ/mol

Explanation:

The neutralization reaction of HCl and NaOH is:

HCl + NaOH → NaCl + H₂O + HEAT

You can find the released heat of the reaction and heat of neutralization (Released heat per mole of reaction) using the formula:

Q = C×m×ΔT

Where Q is heat, C specific heat of the solution (4.06J/gºC), m its mass and ΔT change in temperature (27.5ºC-20.0ºC = 7.5ºC).

The mass of the solution can be finded with the volume of the solution (50.0mL of HCl solution + 50.0mL of NaOH solution = 100.0mL) and its density (1.02g/mL), thus:

100.0mL × (1.02g / mL) = 102g of solution.

Replacing, heat produced in the reaction was:

Q = C×m×ΔT

Q = 4.06J/gºC×102g×7.5ºC

Q = 3106J = 3.106kJ of heat are released.

There are 50.0mL ×1M = 50.0mmoles = 0.0500 moles of HCl and NaOH that are reacting releasing 3.106kJ of heat. That means heat of neutralization is:

3.106kJ / 0.0500mol of reaction =

62.12kJ/mol is heat of neutralization


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assume in a different experiment, you prepare a mixture containing 10.0 M FeSCN2+, 1.0 M H+, 0.1 MFe3+ and 0.1 M HSCN. Is the initial mixture at equilibrium? If not, in what direction must the reactionproceed to reach equilibrium? (Hint: You will need to use the value of Kc you determined in the lab

Answers

Answer:

The mixture is not in equilibrium, the reaction will shift to the left.

Explanation:

Based on the equilibrium:

Fe³⁺+ HSCN ⇄ FeSCN²⁺ + H⁺

kc = 30 = [FeSCN²⁺] [H⁺] / [Fe³⁺] [HSCN]

Where [] are concentrations at equilibrium. The reaction is in equilibrium when  the ratio of concentrations = kc

Q is the same expression than kc but with [] that are not in equilibrium

Replacing:

Q = [10.0M] [1.0M] / [0.1M] [0.1M]

Q = 1000

As Q > kc, the reaction will shift to the left in order to produce Fe³⁺ and HSCN untill Q = Kc

Final answer:

The mixture's equilibrium status can be determined by comparing the reaction quotient (Q) with the equilibrium constant (Kc). If Q < Kc, the reaction proceeds to the right (products) to achieve equilibrium. If Q > Kc, the reaction proceeds to the left (reactants) to achieve equilibrium.

Explanation:

To determine if the mixture is initially at equilibrium, we need to calculate and compare the reaction quotient (Q) and the equilibrium constant (Kc) of the reaction. The reaction quotient is a measure of the relative concentrations of products and reactants at any point in time, whereas Kc, is the measure of these concentrations only at equilibrium.

Assuming that the reaction in question is: Fe3+ + HSCN ↔ FeSCN2+ + H + . In this case,

Q = [FeSCN2+]/[Fe3+][HSCN] = 10 / (0.1 * 0.1) = 1000. If Kc is less than 1000, the reaction is not at equilibrium and will need to proceed to the left (reactants) to reach equilibrium. Conversely, if Kc is greater than 1000, the reaction is not at equilibrium and will need to proceed to the right (products).

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Define the following terms: acids, bases, oxoacids, oxoanions, and hydrates.

Answers

Explanation:

Acids are the species which furnish protons (hydrogen ions) when dissolved in the water.

Bases are the species which furnish hydroxide ions when dissolved in the water.

Oxoacid is the acid which contains with at least one hydrogen atom which is  bonded to the oxygen atom in the molecule which can dissociate in the solution to give proton and the corresponding anion.

Oxoanion is the anion which is derived from oxoacid by the loss of hydrogen atom which is bounded to the oxygen.

A hydrate is the specie which contains water molecule or it's constituents in its solid structure.

Is crumbling a cookie, a physical change? Explain why. My child is having problems with this question, and I'm not so sure how to explain it.

Answers

Sugar, flour, and eggs cannot be separated. The materials' properties have changed, resulting in a chemical change.Therefore, crumbling a cookie is not a physical change.

What is physical change ?

Physical changes affect a chemical substance's form but not its chemical composition. Physical changes can be used to separate mixtures into their component compounds, but not to separate compounds into chemical elements or simpler compounds.

A chemical change is the transformation of one material into another, the formation of new materials with different properties, and the formation of one or more new substances. It occurs when one substance reacts with another to form a new substance.

A physical change is characterized by a change in physical properties. Melting, transition to a gas, change in strength, change in durability, changes in crystal form, textural change, shape, size, colour, volume, and density are all examples of physical properties.

Thus, crumbling a cookie is not a physical change.

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Answer:

Because the sugar flour and eggs can no longer be separated. The properties of the materials have changed so it's a chemical change

What is the charge of the most stable ion of bromine?

Answers

The charge on the most stable ion of bromine is - 1.

What is an ion?

A charged atom or molecule is known as an ion. It has a charge because the atom or molecule's number of protons and electrons is not equal. Depending on whether an atom has more electrons than protons or fewer electrons than protons, an atom might become positively or negatively charged.

An atom is referred to be an ION when it is drawn to another atom due to an imbalance in its electron and proton numbers. A negative ion, or ANION, is an atom that contains more electrons than protons. A positive ion is one that has more protons than electrons.

Either there are too many or not enough electrons in a charged atom. Atoms in DS1 are heated to extremely high energy and unstable state. Then, a cathoderay in the thruster chamber discharges electrons, which strike the. Some of the electrons in the atoms in the chamber are stripped or knocked away when the electrons strike them. Plasma is created when a mass of charged, overheated atoms with free electrons.

Therefore, the charge on the most stable ion of bromine is - 1

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Br (Bromide)

-1 or Br- hope this helps

Object A has a molar heat of 31.2 J/mole∙°C and object B molar heat is 11.2 J/mole∙°C. Which object will heat up faster if they have the same mass and equal amount of heat is applied? Explain why.

Answers

Answer:

Substance B

Explanation:

Molar heat of A = 31.2J/mole.°C

Molar heat of B =  11.2 J/mole∙°C.

The molar heat of a substance is the amount of heat that must be added to a mole of a substance to raise the temperature by 1°C.

  • Substance B will heat up faster compared to A.
  • It has a smaller molar heat compared to A.
  • This suggests that it will require lesser heat to raise its temperature by  1°C.

Be sure to answer all parts. Industrially, hydrogen gas can be prepared by combining propane gas (c3h8) with steam at about 400°c. The products are carbon monoxide (co) and hydrogen gas (h2). (a) write a balanced equation for the reaction. Include phase abbreviations. (b) how many kilograms of h2 can be obtained from 8.31 × 103 kg of propane

Answers

Balanced chemical reaction:

C₃H₈(g) + 3H₂O(g) → 3CO(g) + 7H₂(g).

M(C₃H₈) = 44.1 g/mol; molar mass of propane.

M(H₂) = 2 g/mol; molar mass of hydrogen.

From balanced chemical reaction: n(C₃H₈) : n(H₂) = 1 : 7.

7m(C₃H₈) : M(C₃H₈) = m(H₂) : M(H₂).

7·8310 kg : 44.1 g/mol = m(H₂) : 2 g/mol.

m(H₂) = 2638.09 kg; mass of hydrogen.

Answer: a) C_3H_8(g)+3H_2O(g)\rightarrow 3CO(g)+7H_2(g)

b) 2.64* 10^3kg

Explanation:

a) According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

C_3H_8(g)+3H_2O(g)\rightarrow 3CO(g)+7H_2(g)

b)\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of propane}=(8.31* 10^6g)/(44.1g/mol)=0.188* 10^6moles

C_3H_8(g)+3H_2O(g)\rightarrow 3CO(g)+7H_2(g)

According to stoichiometry:

1 mole of C_3H_8 gives 7 moles of H_2

Thus 0.188* 10^6moles  moles of C_3H_8 will give =(7)/(1)* 0.188* 10^6=1.32* 10^6moles of H_2

Mass of H_2=moles* {\text {molar Mass}}=1.32* 10^6moles* 2g/mol=2.64* 10^6g=2.64* 10^3kg

Thus 2.64* 10^3kg of H_2 can be obtained from 8.31* 10^3 kg of propane