A living room is two times as long and one and one-half times as wide as a bedroom. The amount ofcarpet needed for the living room is how many times greater than the amount of carpet needed for the
bedroom?
1 1/2
2
3
3 1/2

Answers

Answer 1
Answer:

Answer:

3

Step-by-step explanation:

let's call X the length of the bedroom, Y the wide of the bedroom, A the length of the living room and B the wide of the living room

A living room is two times as long as the bedroom, so:

A = 2X

A living room is one and one-half times as wide as a bedroom, so:

B = 1.5Y

The amount of carpet needed for the living room is A*B and the amount of carpet needed by the bedroom is X*Y

So, AB in terms of XY is:

A*B = (2X)*(1.5Y) = 3(X*Y)

It means that the amount of carpet needed for the living room is 3 times greater than the amount of carpet needed for the  bedroom.


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Two scuba divers are swimming below sea level. The locations of the divers can be represented by -30 feet and -42 feet. Which measure represents the location that is closest to sea level.​

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Kenny worked 6.5 hours on Monday, and 5 hours on Tuesday. If he received a check for $143.75 for working those 2 days, how much does Kenny make per hour?

Answers

Answer:

Kevin makes $12.50 per hour.

Step-by-step explanation:

If Kevin works 6.5 hours on Monday and 5 hours on Tuesday, he works a total of 11.5 hours. Over 11.5 hours he makes $143.75. To find your answer, you have to divide your total earned, 143.765, by the total time worked, 11.5 hours. Your answer should then be 12.5, which is the amount per hour kevin earns.

Solve the equation for the value of x-6=x/-4

Please show your work, thank you.

Answers

Answer: x=24

x=-6*-4=24

An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What raw score corresponds to the 70th percentile?

Answers

Answer:

82.62

Step-by-step explanation:

Mean score (μ) = 80

Standard deviation (σ) = 5

The 70th percentile of a normal distribution has an equivalent z-score of roughly 0.525.

For any given score, X, the z-score can be determined by:

z=(X-\mu)/(\sigma)

For z = 0.525:

0.525=(X-80)/(5)\n X=82.62

A raw score of approximately 82.62 corresponds to the 70th percentile.

Answer: the raw score that corresponds to the 70th percentile is 82.625

Step-by-step explanation:

Since the population of scores in the aptitude test is normally distributed., we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = aptitude test scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 80

σ = 5

We want to find the raw score that corresponds to the 70th percentile.

70th percentile = 70/100 = 0.7

Looking at the normal distribution table, the z score corresponding to 0.7 is 0.525.

Therefore,

0.525 = (x - 80)/5

5 × 0.525 = x - 80

2.625 = x - 80

x = 2.625 + 80

x = 82.625

Mr.ward and mr. heskey are racing toy cars and Mr. heskey wants to give mr. ward an 8 ft head start because his car is 2 seconds slower. mr. ward's car travels 4 feet per second and mr. he's key's car travels 6 ft per second.which inequality could be used to determine after how many seconds, 's mr. heskey's car will be head of mr. ward's car?

please show how you got the answer.

Answers

Answer:

  F.  6s > 4s +8

Step-by-step explanation:

From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.

From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.

For Heskey's distance to exceed Ward's distance you want ...

  6s > 4s +8 . . . . . . matches choice F

I need help with math ​

Answers

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