When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are:P2O5 (s) + H2O (l) =H3PO4 (aq)
The balanced chemical equation for the reaction between hydrogen sulfide and oxygen is:
2H2S(g) + 3O2(g) =2H2O(l) + 2SO2(g)
We can interpret this to mean:
3moles of oxygen and_______moles of hydrogen sulfide react to produce______moles of water and_______ moles of sulfur dioxide.

Answers

Answer 1
Answer:

Answer:

1. The coefficients are: 1, 3, 2

2. From the balanced equation, we obtained the following:

3 moles oxygen, O2 reacted.

2 moles of Hydrogen sulfide, H2S reacted.

2 moles of water were produced.

2 moles of sulphur dioxide, SO2 were produced.

Explanation:

1. Determination of the coefficients of the equation.

This is illustrated below:

P2O5(s) + H2O(l) <==> H3PO4(aq)

There are 2 atoms of P on the left side and 1 atom on the right side. It can be balance by putting 2 in front of H3PO4 as shown below:

P2O5(s) + H2O(l) <==> 2H3PO4(aq)

There are 2 atoms of H on the left side and 6 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

P2O5(s) + 3H2O(l) <==> 2H3PO4(aq)

Now the equation is balanced.

The coefficients are: 1, 3, 2.

2. We'll begin by writing the balanced equation for the reaction. This is given below:

2H2S(g) + 3O2(g) => 2H2O(l) + 2SO2(g)

From the balanced equation above,

3 moles of oxygen, O2 reacted with 2 moles of Hydrogen sulfide, H2S to produce 2 moles of water, H2O and 2 moles of sulphur dioxide, SO2.

Answer 2
Answer:

Final answer:

In the balanced chemical equation provided, 3 moles of oxygen react with 2 moles of hydrogen sulfide to produce 2 moles of water and 2 moles of sulfur dioxide.

Explanation:

When the balanced chemical equation 2H2S(g) + 3O2(g) =2H2O(l) + 2SO2(g) is considered, we can deduce that 3 moles of oxygen and 2 moles of hydrogen sulfide react together in this reaction. The products of this chemical reaction are 2 moles of water and 2 moles of sulfur dioxide. Each of these quantities is directly inferred from the coefficients in front of each compound in the balanced chemical equation.

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The percent composition of nitrogen in sodium nitride is 16.86%

What is sodium nitride?

Sodium nitride is an inorganic compound that is used in preservatives and antidote for cyanide poisoning.

The molar mass of Na3N is 83 M

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% \;of \;N = (mass of N)/( molar mass of Na3N ) * 100

\% \;of \;N = (mass\; of \;N)/(molar\; mass\; of\; Na3N) * 100\n\n\n\% \;of \;N = (14)/(83) * 100 = 16.86\%

Thus, the  percent composition of nitrogen in sodium nitride is 16.86%.

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Explanation:

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