In65 - lnX = 39
What does X=?

Answers

Answer 1
Answer:

Answer:

The answer is 7.47

Step-by-step explanation:

In this problem we are going find the natural logarithmic of the numbers involved and solve for x

ln65-Ln x= 39\n

from tables

ln 65= 4.17

4.17-ln x= 39\4.17-39= lnx\n-34.83=lnx\n

taking the exponents of both sides we have

e^-^3^4^.^8^3= x\nx= 7.47


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An isosceles triangle is to be drawn with its two equal sides of length 10. What is the maximum possible area of the triangle?
during a basketball game, your team scored three times as many 2-point field goals than it did 3-point field goals, and scored a total of 90 points. How many field goals did your team score?
A football team loses 5 yards on one play and then loses 8 yards on the nezt play. Write an addition expression that represents the change in the position of the team for the two plays. Then find the sum
112 students are going on a field trip. If each bus can take 50 students, how many busses are needed?

Someone answer this for me please ..​

Answers

Answer: 9 times as large

Step-by-step explanation:

the original area: 15×15=225

the new area: (15×3)(15×3)=2025

2025/225=9

Hope this helps!! :)

Please let me know if you have any question

The weights (to the nearest pound) of some boxes to be shipped are found to be: Weight 65 68 69 70 71 72 90 95 frequency 1 2 5 8 7 3 2 2 Explain why or why not this could be represented by a bell curve (a normal distribution).

Answers

The given weights do not exhibit the characteristics of a bell curve or a normal distribution. The data is skewed, lacks a clear central tendency, and contains outliers. Therefore, it cannot be accurately represented by a normal distribution.

Here, we have,

To determine whether the given weights can be represented by a bell curve (normal distribution), we need to assess if the data exhibits the characteristics of a normal distribution.

Here are a few considerations:

Symmetry: A normal distribution is symmetric, meaning the data is equally distributed around the mean. In the given data, there are more observations on one side of the distribution (higher weights) than the other. This indicates a lack of symmetry, which is not characteristic of a bell curve.

Central tendency: A normal distribution typically has a single peak or mode at the center. In this case, there isn't a clear central tendency as the weights seem to be spread across different ranges without a dominant peak.

Outliers: Normal distributions tend to have minimal outliers or extreme values. The presence of weights like 90 and 95, which are noticeably higher than the other values, suggests the presence of outliers. This goes against the assumption of a bell curve.

Based on these considerations, it appears that the given weights do not exhibit the characteristics of a bell curve or a normal distribution. The data is skewed, lacks a clear central tendency, and contains outliers. Therefore, it cannot be accurately represented by a normal distribution.

learn more on normal distribution :

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because the data is not a normal distribution because the second half of the data is too far away from the first half i think its also called unproportional or something like that feel free to add me as a friend

In an examination it is required to get 40% of the aggregate marks to pass. A student gets 261 marks and is declared failed by 4% marks. What are the maximum aggregate makrs a student can get?

Answers

The solution to the problem is as follows:

→x− 4% (x) = 261

→x − 4x/100 = 261

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

How do I determine the radius of x^2+y^2=25 ?

Answers

Circles!!!

The general formula is:
x^2 + y^2 = r^2
where x and y form the circle while r is the radius.

You already have the problem set up in its general form and you don't want the radius squared... so square root everything.

If you do that then you'll get:
x + y = 5
where 5 is the radius and NOT the radius squared. If you have questions then leave a comment. Good luck!

A bag contains 16 green marbles, 12 red marbles, 15 white marbles, and 7 black marbles. What is the probability of drawing a green marble out of the bag?

A. 1/16


B. 1/4


C. 8/25


D. 8/17

Answers

Probability  = Number of outcomes / Total number of possible outcomes.

So, using this formula we can get our answer
To get total number of possible outcomes we have to add all the marbles
i.e. 16 + 15 + 12 + 7 = 50

And now plugging it in the formula
Probability (drawing a green marbles) = 16/50
                                                                  = 8/25

So, Correct option is C.

Hope this helps you...  :D
since there are 16 green marbles out of 50 marbles
It is simply:
(16)/(50) 
Simplified:
(8)/(25)
Answer is C. (8)/(25)

How do i solve and graph 5x- y \geq 5

Answers

one way is to make it into slope intercept form which is
y=mx+b
m=slope
b=y intercept or where the line will go though the y axis
treat the equal to or greater than sign as equals for now

5x-y=5
subtract y from both sides
5x=5+y
subtract 5
5x-5=y
put the sign back in
5x-5 ≥ y
reverse
y ≤ 5x-5

one way is to subsitute values and get values out so
if x=1 then
y≤5(1)-5
y≤0
(x,y)
(1,0)
(2,5)
(3,10)
(4,15)
(0,-5)

plot the points
then the ≤ sign
since ther is an underline, that means that the points are included so draw a solid line through the points

then figure out which side to shade on
the easy way is, is the point (0,0) a solution?
subsitute
0 ≤ 5(0)-5
0 ≤ -5
false so we shade the section that does not include the point (0,0) in it
the graph would look like this attachment


    (you have to put y alone {Ex: y = 12x + 3 (yis alone on one side)}



5x - y 
≥ 5       (subract 5x from each side)
-y ≥ -5x + 5   (divide - or -1 from each side)  Note: when you are dividing or multiplying anything negative the sign changes
≤ 5x - 5 <--- answer


As for graphing you take the equation and graph it normally, but with a slight change. since y is less than or equal to 5x - 5, you have to color on the spACE BELOW the graphed line.

see picture: