MATHEMATICS COLLEGE

Need Assitance
Show Work

Answers

Answer 1

Answer:

Answer:

66 2/3 %

Step-by-step explanation:

First find the students not in the 8th grade

24 - 8 = 16

16 students are not in the 8th grade

Take the fraction of the students not in the 8th grade over the total

16/24 = 2/3

Change to a decimal

.66666666666

Multiply by 100 to change to a percent

66.666666%

66 2/3 %

Answer 2

Answer:

Answer:

66.67% of students are not in eighth grade

Step-by-step explanation:

8/24=1/3

1/3=0.33333333333

1-0.33333333333=0.66666666667

0.66666666667=66.67%

Related Questions

hector works 12 hours a week at a part time job. His original pay rate was $8 per hour but he recently received a pay raise of x dollars an hour. his new total weekly pay, y, is represented by the equaiton y=12(8+x)
Is this one correct?
Skyler solved an equation incorrectly, as shown below:Step 1: 12 + x = 36Step 2: x = 36 + 12Step 3: x = 24Which statement best explains why Step 2 is incorrect in Skyler's solution?
What is the zero of f?-52-25
MZTRI = 3x - 5, mZIRB = x + 27,and mZTRB = 86. Find the mZTRI.

Which coordinates represent the plotted point? Check all that apply. (StartRoot 13 EndRoot, 146.3 degrees) (StartRoot 13 EndRoot, 213.7 degrees) (negative StartRoot 13 EndRoot, negative 33.7 degrees) (Negative StartRoot 13 EndRoot, negative 146.3 degrees) (−3, 2) (3, −2) (−2, 3)

Answers

Answer:

A, C, E.

Step-by-step explanation:

Just did it.

Answer:

A (square root 13, 146.3 degrees)

C (-squareroot13, -33.7 degrees)

E (-3,2)

This graph shows the distance that a robot walks. What is the robot’s speed?

Answers

Answer:

D. 30 feet per minute

Step-by-step explanation:

If you follow the x-axis (time) you see 1 minute as you go up the y-axis (distance) you see that 1 and 30 connect, therefore you get 30 feet per minute.

Answer:

30 feet per minute

Step-by-step explanation:

its very slow therefore it takes a lot of time

The figure below is a scale drawing of a garden. If the scale used 1/4 inch = 3 feet, then what is the perimeter of the actual garden?

Answers

Answer:

The answer is 2.25

Step-by-step explanation:

Steps:

1. 1/2 inch + 1 3/4 inch = 2.25 inch

Answer:

2.25

Step-by-step explanation:

Please help I don’t know what to do and I have a whole test on it

Answers

Answer:

Step-by-step explanation:

<dfh=<ehg
fh=hg
<dhf=<hgf

Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choices, We are interested in the flags that are chosen on Monday, Tuesday and Wednesday of next week.a) Describe a sample space \Omega and a probability measure P to model this experiment.

b) What is the probability that the class hangs Wisconsin's flag on Monday, Michigan's flag on Tuesday, and California's flag on Wednesday.?

c) What is the probability that Wisconsin's flag will be hung at least two of the three days?

Answers

Answer:

a.) P(x = X) = $(1)/(50)$

b.) $(1)/(50) *(1)/(50) *(1)/(50) = (1)/(125000)$

c.) 0.00118

Step-by-step explanation:

The sample space Ω = flags of all 50 states

a.) Any one of the flags is randomly chosen. Therefore we can write the

probability measure as P(x = X) = $(1)/(50)$ , for all the elements of the sample

space, that is for all x ∈ Ω.

b.) the probability that the class hangs Wisconsin's flag on Monday,

Michigan's flag on Tuesday, and California's flag on Wednesday

= $(1)/(50) *(1)/(50) *(1)/(50) = (1)/(125000)$

c.) the probability that Wisconsin's flag will be hung at least two of the three days

= Probability that Wisconsin's flag will be hung on two days + Probability that Wisconsin's flag will be hung on three days

= P(x = 2) + P(x = 3)

= $(\binom{3}{2}* (1)/(50) * (1)/(50)* (49)/(50)) + (\binom{3}{3}* (1)/(50) * (1)/(50)* (1)/(50))\n$

= $(147)/(125000) + (1)/(125000)$

= $(148)/(125000)$

= 0.00118

Final answer:

The sample space for this experiment is all the possible combinations of flags from the 50 U.S. states for the three days. The probability of hanging Wisconsin's flag on Monday, Michigan's on Tuesday, and California's on Wednesday is 1/125,000. The probability of hanging Wisconsin's flag at least two of the three days is 294/125,000.

Explanation:

a) The sample space Ω for this experiment comprises of all possible combinations of flags from the 50 U.S. states for the three days. Hence, the total number of outcomes in the sample space Ω would be 50*50*50 = 125,000. Every outcome in this space is equally likely, so the probability measure P would assign a probability of 1/125,000 to each outcome.

b) As each day's choice is independent of the others and each state's flag is equally likely to be chosen, the probability that Wisconsin's flag is hung on Monday, Michigan's flag is hung on Tuesday, and California's flag is hung on Wednesday would be (1/50) * (1/50) * (1/50) = 1/125,000.

c) To find the probability that Wisconsin's flag will be hung at least two of the three days, we have to add the probabilities for the three situations where Wisconsin's flag is hung exactly twice plus the situation where Wisconsin's flag is hung all three days. The final probability would be [(3 * (1/50)² * (49/50)) + (1/50)³] = 294/125,000.