MATHEMATICS HIGH SCHOOL

Whats the factored form of 6x 2 - 8x - 8 = 0

Answers

Answer 1

Answer:

Answer:

2(x -2)² = 0

Step-by-step explanation:

2(x² - 4x - 4) = 0

2(x -2)² = 0

x = 2

Answer 2

Answer:

Answer:

$2(3x-2)(x+2)=6x^2-8x-8$

The factored form of $6x^2-8x-8=0$ is $2(3x-2)(x+2)=0$

Step-by-step explanation:

$6x^2-8x-8=0$

The way the quadratic equation was given, we can't have a factored form in the format: $(ax-b)(cx+d)$

First, divide both sides by 2

$3x^2-4x-4=0$

Now, it is about thinking. From the equation, we will get something in the format: $(ax-b)(cx+d)$

Let's expand this: $(ax-b)(cx+d) = acx^2+adx-bcx-bd$

From here, we can give some values for those variables, based on the quadratic equation $3x^2-4x-4=0$ :

$(3x-b)(x+d) = 3\cdot 1\cdot x^2+3dx-b\cdot 1 \cdot x-bd= \boxed{3x^2+3dx-bx-bd}$

Once we want the middle term to be -4 and bd to be 4, we can easily evaluate the other variables.

$(3x-2)(x+2) = 3\cdot 1\cdot x^2+3(2)x-(2)\cdot 1 \cdot x-(2)(2)= \boxed{3x^2+6x-4x-4}$

Therefore,

$(3x-2)(x+2)=3x^2-4x-4$

But we are not ready yet!

This is the factored form of $3x^2-4x-4=0$ , to get the factored form of the problem equation, just multiply the factored form we got by 2.

$2(3x-2)(x+2)=6x^2-8x-8$

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Please explain the work behind the solution

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$(-7x^2-7x-7)-[(7x^3-9x^2-20)+(4x-11)]]=\n=-7x^2-7x-7-(7x^3-9x^2-20+4x-11)=\n=-7x^2-7x-7-7x^3+9x^2+20-4x+11=-7x^3+2x^2-11x+24\n\n (5x^4+8x^2+2)+7(5x^4-3x^2)=5x^4+8x^2+2+35x^4-21x^2=\n=39x^4-13x^2+2$

What is the dividend in this problem 52.05 = 5=? * A) 52.05 B) 5 C) 0.05 D) 0.01

Answers

Answer) your answer is A

The reason that is your answer is because, the others are not able to be your answers on the fact of there to small for it to work and another being the correct answer is the only logical and the only answer that makes sense...

I hope this helps you and is correct

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Answers

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Answers

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Answers

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