Find the measure of b.
Find the measure of b. - 1

Answers

Answer 1
Answer:

Answer:

b = 80°

Step-by-step explanation:

The inscribed angle measuring 100°, is supplementary to the angle opposite it in the inscribed quadrilateral.

Thus, the angle is = 80°

Therefore, b + 80° = 180° (angle on a straight line = 180°).

Thus, b = 180° - 80° = 100°.

The measure of b is 80°.


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What fraction of 1 minute is 47 seconds

Answers

47/60 because there are 60 seconds in one minute
1min=60s\ therefore\ 47s=(47)/(60)min

Flying against the wind a jet travels 7740 miles in 9 hours. Flying with the wind the same jet travels 4000 80 miles in 3 hours. What is the rate of the jet in still air and what is the rate of the wind?

Answers

j\ \rightarrow\ the\ rate\ of\ the\ jet\ in\ still\ air \nw\ \rightarrow\ the\ rate\ of\ the\ wind\n\nj-w= \frac{\big{7740\ miles}}{\big{9\ hours}}\ \ \ \Rightarrow\ \ \ j-w=860\ (miles)/( hour)\n\n j+w= \frac{\big{4080\ miles}}{\big{3\ hours}}\ \ \ \Rightarrow\ \ \ j+w=1360\ (miles)/( hour)\n----------\n\n2j=(860+1360)\ (miles)/( hour)\ \ \ \Rightarrow\ \ \ 2j=2220\ (miles)/( hour)\ \ \ \Rightarrow\ \ \ j=1110\ (miles)/( hour)

j+w=1360\ (miles)/( hour)\ \ \ \Rightarrow\ \ \ w=(1360}-1110)\ (miles)/( hour)=250\ (miles)/( hour)\n\n\nAns.\ the\ rate\ of\ the\ jet\ in\ still\ air\ is\ 1110\ (mi)/(hr) \ \ \ \n\n.\ \ \ \ \ \ and\ \ \ the\ rate\ of\ wind\ is\ 250\ (mi)/(hr)

Suppose ∠A and ∠B are complementary angles, m∠A = (3x + 5)°, andm∠B = (2x – 15)°. Solve for x and then find m∠A and m∠B.

Answers

         m∠A + m∠B = 90
(3x + 5) + (2x - 15) = 90
(3x + 2x) + (5 - 15) = 90
                  5x - 10 = 90
                      + 10  + 10
                         5x = 100
                          5      5
                           x = 20

m∠A = 3x + 5
m∠A = 3(20) + 5
m∠A = 60 + 5
m∠A = 65

m∠B = 2x - 15
m∠B = 2(20) - 15
m∠B = 40 - 15
m∠B = 25
m∠A + m∠B = 90

(3x + 5) + (2x - 15) = 90

(3x + 2x) + (5 - 15) = 90

5x - 10 = 90

5x - 10 +10 = 90+10

5x = 100

5x/5 = 100/5      Divide \ both \ sides \ by \ 5

x = 20                 Solutions

m∠A = 3x + 5     (x=20)

m∠A = 3(20) + 5          Substitute \ x \ for \ 20

m∠A = 60 + 5               Simplify

m∠A = 65


m∠B = 2x - 15

m∠B = 2(20) - 15

m∠B = 40 - 15

m∠B = 25

which of the expressions doe not contain any like terms?    a. 2x2+3x-4x+2     b. xy+yz-17     c. x2+x2-2x-x2   d. 4+8+y

Answers

b. does not contain any like terms, because xy, yz, and -17, do not share any common variables. 

Hope this helps!
The answer is B it does not have any of the other terms

Solve each system by elimination:
10x+8y= -18
8x+8y= -24

Answers

Answer:

Step-by-step explanation:

10x + 8y = -18

-8x - 8y = 24

2x = 6

x = 3

8(3) + 8y = -24

24 + 8y = -24

8y = -48

y = -6

(3, -6)

(3,-6) would be the answer to this question

14. Craig jogs 12 km in 1 h. If he jogs at thesame rate, how long will it take him to jog
18 km?

Answers

Answer: 1:30 (one hour and thirty minutes)

Step-by-step explanation:

If he jogs 12 km in an hour, and he wants to jog 18 km, you divide 12 km from when he jogged for and hour by 2 and get 6. Add 12 km to 6 km, and get 18 km in one hour and thirty minutes. So, basically 6 km every 30 minutes.

Answer:

1.5 hours

Step-by-step explanation:

12/1 = 18/x

X = 18/12 = 1.5 hours