A farm yard contains some pigs and some chickens. Altogether there are 60 heads and 200 legs. How many pigs are there in the yard?

Answers

Answer 1
Answer:

Answer:

40 pigs.

Step-by-step explanation:

p=pigs c=chickens.

4p=pigs have 4 legs.

2c=chickens have 2 legs.

4p+2c=200

p+c=60

Do the elimination method:

4p+2c=200

(-4)p+c=60

4p+2c=200

-4p-4c=-240

-2c=-40

c=20

p+20=60

p=60-20

p=40

Hope this helps!

BRAINLIEST would help me a lot:)


Related Questions

I'm struggling on this, please can someone help me?
The temperature T in degrees Celsius of a liquid t minutes after heating is given by the formula T=8√t. When is the temperature 48 degrees celsius?
Hi! Can somebody pls explain to me how to do one of these problems pls......will give brainliest lol
If n is the average of three numbers x, 12, and 15, what is the value of x?
Simplify this step by step

Please help with question 8 and explain steps

Answers

2 -> 7; but 7 = 2 * 2 + 3;
3 -> 9; but, 9 = 3 *2 + 3;
4 -> 11; but, 11 = 4 * 2 + 3;
5 -> 13; but, 13 = 5 * 2 + 3;

The rule is : ( your number ) * 2 + 3;

The function rule is f( x ) = 2x + 3.

A student constructs the angle bisectors of a triangle and then uses their intersection point as the center of a circle. The student has constructed which of the following?A. Concentric circles of a triangle
B. A circumscribed circle of a triangle
C. An inscribed circle of a triangle
D. The perpendicular bisector of the triangle

Answers

"An inscribed circle of a triangle" is the one among the following choices given in the question that the student has constructed. The correct option among all the options that are given in the question is the penultimate option or option "C". I hope that this is the answer that you were looking for and it has come to your help.

The answer is C. An inscribed circle of a triangle APEX 2018

What is x2 -6x-23=0 using square roots

Answers

-4x - 23 = 0
     +23 = +23
-4x = 23
-4.   -4x
Answer:5.75

13 is to 8 as x + 4 is to x

Answers

(13)/(8) = (x+4)/(x) \n 13 * x = 8(x+4) \n 13x = 8x + 32 \n 5x = 32 \n x = 6.4

you have 160 yards of fencing to enclose a rectangular region. find the maximum area of the rectangular region

Answers


I know that for a fixed perimeter, the shape that encloses the greatest area
is a circle, and the rectangle that encloses the greatest area is a square. 
Sadly, I don't know how to prove it to you without Calculus.

If you'll take my assertion that the greatest rectangle is a square, and accept
it on faith, then you should use your 160-yd of fence to enclose a square with
40-yd sides.  The area inside it is (40 x 40) = 1600 square yards.

Here are some other choices. 
Each one has the same perimeter ... 160 yards.
This table kind of suggests to you that a square is the rectangle
       with the greatest area.  (But it doesn't prove it.)

Length         Width         Area
  35-yd           45-yd         1,575 square yards              
  30                50              1,500
  25                55              1,375
  20                60              1,200
  15                65                 975
  10                70                 700
    5                75                 375
    3                77                 231
    2                78                 156
    1                79                   79
  2-ft           79-yd 1-ft           52.89
  1-ft           79-yd 2-ft           26.56
  1-inch      79-yd 35-in          2.19 square yards

With the same 160-yd of fence, you could have squeezed in some more
area by setting the fence down in a circle with circumference = 160-yd.
The area inside the circle would be

       Area = (pi) (radius)² = (circumference)² / (4 pi) = 2,037.2 square yards

The area of a circle is always (4 / pi) times the area of the square with the
same perimeter.  That's about 27.3% more area than the square.

To optimize the area, the shape should be a square.  Clearly, with 160 yards of fencing, the square will have side-length 160/4=40 yards.  Therefore, the area will be 40*40=1600 yards.

The product of two integers is 50. one integer is twice the other. find the integers.

Answers

(1) -5*(-10)=50
(2) 5*10=50
use what they are telling. 

a*b=50 (one integer times the other give you a product of 50. we're randomly calling these integers "a" and "b")

2a=b (one integer is twice the amount of the other. we're randomly selecting "b" to be twice the amount of "a")

plug in what we know 

a*(2a)=50 (we replaced "b" with "2a" because we know from the info they gave us that b=2a)

now solve for "a"

a*2a=50
2a²=50
a²=50/2
a²=25
√a²=√25
a=5

which because 2a=b we know that b=10