Find the perimeter of the following rectilinear figure.

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation

You can't find the other sides, it may seem impossible, but you have to look at this problem in a different way. To find the perimeter of any figure you just need to know the top base, bottom base, right side, and left side.

We see that the top base equals to the bottom base as it is a rectilinear figure. You have to treat the side with 8 and side with 5 as one base. So they equal 13. Now do the same for the bottom.

So, 13 + 13 = 26

The right side is equal to the left side as it is a rectilinear figure, so the right side is 4 + 10 = 14. The left side is also 14.

So 14 + 14 = 28

26 + 28 = 54 units

Sorry, if I couldn't explain properly. I tried my best. As it is hard for me to explain in words. If I could draw it out, I could do better.

Answer 2

Answer:

Answer:

Step-by-step explanation:

I broke the sections apart and then added:

14+14=28

13+13=26

26+28=54

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Can the graph of a function be a horizontal line? A vertical line? Explain.

Answers

It can be a function if it's horizontal because it's only touching each point once, it can't be a function for a vertical line because it's straight up and down and it'll hit every point

The graph of a function can be a horizontal line because the x-value at each point on the line is unique, and a horizontal line passes the vertical line test. The graph of a function cannot be a vertical line because the x-value remains the same at all points, and a vertical line fails the vertical line test.

Three fifths is__________pieces of the whole

Answers

60 pieces of the whole
3/5 = x/100
5*20 = 100
3*20 = 60

What is the slope of a line perpendicular to the line whose equation is y = 2x + 5?A. slope = -1
B. slope = -1/2
C. slope = -2

Answers

B = -1/2
I hope that helps

Answer:

-1/2

I hope that helps

Step-by-step explanation:

Evaluate the limit as x approaches 0 of (1 - x^(sin(x)))/(x*log(x))aka: $(1-x^(sin(x)))/(x*log(x))$

Please include steps/explanation.

Answers

$sin~ x \approx x ~ ~\sf{as}~~ x \rightarrow 0$

We can replace sin x with x anywhere in the limit as long as x approaches 0.

Also,

$\large \lim_( x \to 0 ) ~ x^x = 1$

I will make the assumption that log(x)=ln(x).

The limit result can be proven if the base of log(x) is 10.

$\large \lim_(x \to 0^(+)) (1- x^(\sin x) )/(x \log x ) \n~\n \large = \lim_(x \to 0^(+)) (1- x^(\sin x) )/( \log( x^x) ) \n~\n \large = \lim_(x \to 0^(+)) (1- x^(x) )/( \log( x^x) ) ~~ \normalsize{\text{ substituting x for sin x } } \n~\n \large = (\lim_(x \to 0^(+)) (1) - \lim_(x \to 0^(+)) \left( x^(x)\right) )/( \log( \lim_(x \to 0^(+))x^x) ) = (1-1)/(\log(1)) = (0)/(0)$

We get the indeterminate form 0/0, so we have to use Lhopitals rule

$\large \lim_(x \to 0^(+)) (1- x^(x) )/( \log( x^x) ) =_(LH) \lim_(x \to 0^(+)) (0 -x^x( 1 + \log (x)) )/(1 + \log (x) ) \n = \large \lim_(x \to 0^(+)) (-x^x) = \large - \lim_(x \to 0^(+)) (x^x) = -1$

Therefore,

$\large \lim_(x \to 0^(+)) (1- x^(\sin x) )/(x \log x ) =\boxed{ -1}$

The Mill Valley Brewery produces 32 ounce bottles of beer. The Bureau of Weights and Measures randomly selects 50 of these bottles, measures their contents, and obtains a sample mean of 31.8 oz and a sample standard deviation of 0.75 oz. At the 5% level, is there evidence that Mill Valley Brewery is cheating customers by under-filling their bottles?

Answers

Answer:

Since the calculated Z= -1.886 lies within the Z∝ = ± 1.96 we fail to reject our null hypothesis that population mean is 31.8 oz. and not 32 ounces. There is evidence that Mill Valley Brewery is cheating customers by under-filling their bottles.

Step-by-step explanation:

Let the null hypothesis be

H0 : u = 31.8 oz against Ha: u ≠ 31.8 oz two tailed test

For a two tailed test and alpha = 0.05 the z∝ = ± 1.96

The rejection region is Z ≥ ± 1.96

Here n = 50

sample mean = x= 31.8 oz

and sample standard deviation= s= 0.75

Population mean= u= 32

Test statistics to be used is

Z= x- u / s/ √n which is approximately normal

Z= 31.8-32/0.75/ √50