Tierra's THR zone is 135-185 bpm (beats per minute). What might Tierra's heart rate be toindicate that she was working too hard?
A. 145 bpm
B. 195 bpm
C. 175 bpm
D. 130 bpm

Answers

Answer 1

Answer:

The correct answer is B. 195 bpm

Explanation:

In health and related areas, THR or Target Heart Rate zone refers to the range of heart rate an individual should have including the maximum heart rate. In the case of Tierra, her THR zone indicates her maximum heart rate should be 185 beats per minute.

In this context, a heart rate above this number shows Tierra is working too hard or that his heart is doing too much effort, which is dangerous for her health. Thus, the heart rate that shows she is doing too hard is 195 bmp as this is the only one that is above the ideal rate.

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Find a generating function for the sequence of squares: g(x) = P∞ n=0 n 2x n . Then for fun, as above evaluate your expression g(1/100) or g(1/1000) to get a fraction that contains the squares in its decimal expansion.

Answers

The sequence of squares, $\{n^2\}_(n\ge0)$ , has generating function

$g(x)=\displaystyle\sum_(n=0)^\infty n^2x^n$

Recall that for $|x|<1$ ,

$f(x)=\frac1{1-x}=\displaystyle\sum_(n=0)^\infty x^n$

Taking the derivative, we have

$f'(x)=\frac1{(1-x)^2}=\displaystyle\sum_(n=0)^\infty nx^(n-1)=\frac1x\sum_(n=0)^\infty nx^n$

and taking the derivative again, we have

$f''(x)=\frac2{(1-x)^3}=\displaystyle\frac1x\sum_(n=0)^\infty n^2x^(n-1)-\frac1{x^2}\sum_(n=0)^\infty nx^n$

$f''(x)=\frac2{(1-x)^3}=\displaystyle\frac1{x^2}\left(\sum_(n=0)^\infty n^2x^n-\sum_(n=0)^\infty nx^n\right)$

From this we can get an expression for $g(x)$ in terms of the derivatives of $f(x)$ :

$f''(x)=(g(x)-xf'(x))/(x^2)$

$\implies g(x)=x^2f''(x)+xf'(x)$

$\implies g(x)=(2x^2)/((1-x)^3)+\frac x{(1-x)^2}$

$\implies\boxed{g(x)=(x^2+x)/((1-x)^3)}$

Then

$g\left(\frac1{100}\right)=(10,100)/(970,299)\approx0.\underline{01}\,\underline{04}\,\underline{09}\,\underline{16}\ldots$

$g\left(\frac1{1000}\right)=(1,001,000)/(997,002,999)\approx0.\underline{001}\,\underline{004}\,\underline{009}\,\underline{016}\ldots$

Length 21cm area 315cm2 find the breath

Answers

___________________________________

Symbols of:

$\quad\quad\quad\quad\tt{A = A rea}$

$\quad\quad\quad\quad\tt{ l = length}$

$\quad\quad\quad\quad\tt{ b \: = breadth}$

Given that:

$\quad\quad\quad\quad\tt{A = 315 {cm}^(2) }$

$\quad\quad\quad\quad\tt{l = 21cm}$

$\quad\quad\quad\quad\tt{b = \: ? }$

Formula for breadth (b):

$\quad\quad\quad\quad\tt{breadth = (Area)/(length) }$

Solution:

$\quad\quad\quad\quad\tt{b = \frac{315 {cm}^(2) }{21cm} }$

$\quad\quad\quad\tt{\:\:b = {15cm}}$

So, the breadth (b) is:

$\quad\quad\quad\quad\tt \boxed{ \boxed{ \color{magenta}{b = 15cm }}}$

___________________________________

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✍︎ C.Rose❀

Answer:

Breadth = 15 cm

Step-by-step explanation:

Area = length x breadth

315 = 21 x breadth

$(315)/(21) = (21)/(21) * breadth$ [ dividing both sides by 21 ]

$15 = 1 * breadth\n\nbreadth = 15 \ cm$

The principal is Rs.30,000 the interest rate is 12%. Calculate the total value after 2 yearusing compound interest.

Answers

Total value=
112/100 x 112/100 x 30,000
= 37632 Rs

Answer:

37632

Step-by-step explanation:

An=A(1+12%)²

State whether the following function is a linear function f(x)=x-4

Answers

Yes it is a linear function

The edge of a cube was found to be 30 cm with a possible error in measurement of 0.5 cm. Use differentials to estimate the maximum possible error, relative error, and percentage error in computing the volume of the cube and the surface area of the cube. (Round your answers to four decimal places.) My Notes Ask Your Teacher (a) the volume of the cube maximum possible error relative error percentage error cm
(b) the surface area of the cube maximum possible error relative error percentage error cm Need Help? ReadTalk to Tuter

Answers

Answer with Step-by-step explanation:

We are given that

Side of cube, x=30 cm

Error in measurement of edge, $\delta x=0.5$ cm

(a)

Volume of cube, $V=x^3$

Using differential

$dV=3x^2dx$

Substitute the values

$dV=3(30)^2(0.5)$

$dV=1350 cm^3$

Hence, the maximum possible error in computing the volume of the cube

= $1350 cm^3$

Volume of cube, $V=(30)^3=27000 cm^3$

Relative error= $(dV)/(V)=(1350)/(2700)$

Relative error=0.05

Percentage error= $0.05* 100=5$ %

Hence, relative error in computing the volume of the cube=0.05 and

percentage error in computing the volume of the cube=5%

(b)

Surface area of cube, $A=6x^2$

$dA=12xdx$

$dA=12(30)(0.5)$

$dA=180cm^2$

The maximum possible error in computing the volume of the cube= $180cm^2$

$A=6(30)^2=5400cm^2$

Relative error= $(dA)/(A)=(180)/(5400)$

Relative error in computing the volume of the cube=0.033

The percentage error in computing the volume of the cube= $0.033* 100=3.3$ %

The following figures are similar, find the value of x

Answers

Answer:

x=143

Step-by-step explanation:

scale factor (if that is the correct term) is 13. you find that by matching sides to side. this means that 91/7=13, therefore you know that 4*13 is 52 and 11*13 is 143

The answer is x =143 I’m pretty sure

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