Solve 14n2+32n=−34 by using the quadratic formula. Simplify any fractions. If there are multiple answers, list them separated by a comma, e.g. 1,2. If there is no solution, enter ∅.

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

Hello, first of all we can divide by 2.

7n^2+16n+17=0\n\n\Delta=b^2-4ac= 16^2-4*7*17=-220 < 0 \ \ !!

The discriminant is negative so there is no real solutions.

Thank you.


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Jack bought a sweater at a sale price of $15. The original cost of the sweater was $50. What percent represents the discount that Jack received when buying the sweater? *

Answers

Answer:

The sweater was 30% off

Step-by-step explanation:

To find this answer you need to simply dived 15  ÷ 50 to get the answer of 0.3 and 0.3 as a percent would be 30 making the sweater 30% off

Subject: writing equations
Fake answers-reported cuz I’m rly tryna pass this shi.

Answers

Answer:

1) Y-6=-3/2(X-0)     2) Y= -3/2x+6   3) 3x+2y=12

Step-by-step explanation:

In a large university, 20% of the students are business majors. A random sample of 100 students is selected, and their majors are recorded. a) Compute the standard error of the proportion. b) What is the probability that the sample contains at least 12 business majors

Answers

Answer:

a. 0.04

b. 0.9772

Step-by-step explanation:

Please check attachment for complete solution and step by step explanation

Final answer:

The standard error of the proportion is 0.04. The probability of having at least 12 business students in a sample of 100 can be found by using the binomial distribution formula, though precise calculation would require the use of statistical software.

Explanation:

In a large university, 20% of students are business majors. The question is asking about the standard error and the probability of having at least 12 business students in a random sample of 100 students.

a) The standard error (SE) of the proportion is calculated as the square root of [p(1-p)/n], where 'p' is the proportion of business majors (0.2 in this case)and 'n' is the sample size (100 in this case). So, the SE = sqrt[(0.2)(0.8)/100] = sqrt[0.0016] = 0.04.

b) In order to calculate the probability that there are at least 12 business students, we would use the binomial distribution. Using the binomial distribution formula P(X >= x) = 1 - P(X < x), where 'X' is a random variable representing the number of business majors, and 'x' is 12. Since the calculation is tedious, one would use statistical software or a calculator to find this probability. Typically, the result would be greater than 0.

Learn more about Probability and Standard Error here:

brainly.com/question/33667940

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A practice law exam has 100 questions, each with 5 possible choices. A student took the exam and received 13 out of 100.If the student guesses the whole test, the expected number of correct answers is 20 with a standard error of .Compute the z-test statistic for the observed value 13.Find the observed significance level or P-value of the statistic.

Answers

Answer:

z=(13-20)/(4)=-1.75

Assuming:

H0: \mu \geq 20

H1: \mu <20

p_v = P(Z<-1.75) = 0.0401

Step-by-step explanation:

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest (number of correct answers in the test), on this case we now that:

X \sim Binom(n=100, p=0.2)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^(n-x)

Where (nCx) means combinatory and it's given by this formula:

nCx=(n!)/((n-x)! x!)

We need to check the conditions in order to use the normal approximation.

np=100*0.2=20 \geq 10

n(1-p)=20*(1-0.2)=16 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=100*0.2=20

\sigma=√(np(1-p))=√(100*0.2(1-0.2))=4

So we can approximate the random variable X like this:

X\sim N(\mu =20, \sigma=4)

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  The letter \phi(b) is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: \phi(b)=P(z<b)

The z score is given by this formula:

z=(x-\mu)/(\sigma)

If we replace we got:

z=(13-20)/(4)=-1.75

Let's assume that we conduct the following test:

H0: \mu \geq 20

H1: \mu <20

We want to check is the score for the student is significantly less than the expected value using random guessing.

So on this case since we have the statistic we can calculate the p value on this way:

p_v = P(Z<-1.75) = 0.0401

The sizes of houses in Kenton County are normally distributed with a mean of 1346square feet with a standard deviation of 191 square feet. For a randomly selected
house in Kenton County, what is the probability the house size is:
a. over 1371 square feet?
O Z=
o probability =
b. under 1296 square feet?
O Z=
o probability =
c. between 773 and 1637 square feet?
o zl =
o Z2 =
o probability =
Note: Z-scores should be rounded to 2 decimal places & probabilities should be
rounded to 4 decimal places.
License
Points possible: 8
This is attempt 1 of 3.

Answers

Answer:

(a) The probability that the house size is over 1371 square feet is 0.4483.

(b) The probability that the house size is under 1296 square feet is 0.3974.

(c) The probability that the house size is between 773 and 1637 square feet is 0.9344.

Step-by-step explanation:

We are given that the sizes of houses in Kenton County are normally distributed with a mean of 1346  square feet with a standard deviation of 191 square feet.

Let X = the sizes of houses in Kenton County

The z-score probability distribution for the normal distribution is given by;

                               Z  =  (X-\mu)/(\sigma)  ~ N(0,1)

where, \mu = mean size of houses = 1346 square feet

            \sigma = standard deviation = 191 square feet

(a) The probability that the house size is over 1371 square feet is given by = P(X > 1371 square feet)

        P(X > 1371) = P( (X-\mu)/(\sigma) > (1371-1346)/(191) ) = P(Z > 0.13) = 1 - P(Z \leq 0.13)

                                                             = 1 - 0.5517 = 0.4483

The above probability is calculated by looking at the value of x = 0.13 in the z table which has an area of 0.5517.

(b) The probability that the house size is under 1296 square feet is given by = P(X < 1296 square feet)

        P(X < 1296) = P( (X-\mu)/(\sigma) < (1296-1346)/(191) ) = P(Z < -0.26) = 1 - P(Z \leq 0.26)

                                                             = 1 - 0.6026 = 0.3974

The above probability is calculated by looking at the value of x = 0.26 in the z table which has an area of 0.6026.

(c) The probability that the house size is between 773 and 1637 square feet is given by = P(773 square feet < X < 1637 square feet)

       P(773 < X < 1637) = P(X < 1637) - P(X \leq 773)

 

      P(X < 1637) = P( (X-\mu)/(\sigma) < (1637-1346)/(191) ) = P(Z < 1.52) = 0.9357

       P(X \leq 773) = P( (X-\mu)/(\sigma)\leq(773-1346)/(191) ) = P(Z \leq -3) = 1 - P(Z \leq 3)

                                                             = 1 - 0.9987 = 0.0013

The above probabilities are calculated by looking at the value of x = 1.52 and x = 3 in the z table which has an area of 0.9357 and 0.9987 respectively.

Therefore, P(773 square feet < X < 1637 square feet)  = 0.9357 - 0.0013 = 0.9344.  

A group of students organized a car wash for a fundraiser. The students that rate how much money they could earn from washing cars for six hours? A. $12.00
B. $18.00
C. $216.00
D. $228.00


4. A company paid $45 for 2 cases of printer paper. Next month the company's office manager will need to order 15 cases of the same paper. If the price per case does not change, what will be the total cost of next month's order?
A. $22.50
B. $45
C. $337.50
D. $675


5. Ben's family is driving on a cross-country trip for their family vacation. The total mileage of the trip is 3,100 miles. After the first 3 days, they have driven a total of 1085 miles. What percent of the driving distance remains after the first 3 days?
A. 85%
B. 65%
C. 35%
D. 31%


Giving Brainly plzzz EXPLIAN

Answers

Number 3: need more info

Number 4: is 337.5.
- first we need i\to find how much one case costs. $45/2 = $22.5
- next multiply $22.5 x 15 which gets you $337.50

Number 5: is 65%
- 100% divided by 3,100 is .03225806
- then multiply .023225806 by 1085 which gets you 35%
- but because it is asking for the remaining it is 100% - 35% which is 65%