MATHEMATICS COLLEGE

What is the value of (–7 + 3i) + (2 – 6i)? a. –9 – 3i
b. –9 + 9i
c. –5 + 9i
d. –5 – 3i

Answers

Answer 1
Answer:

Answer:

d

Step-by-step explanation:

(-7 + 3i) + (2-6i)

=-7 + 3i + 2 -6i

=(-7+2) + (3i -6i)

=-5 -3i
Answer 2
Answer:

Answer:

(-7+3I)+(2-6I)

= -7+3i+2-6i

= -5-3I

so answer is d ie -5-3i

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Determine the level of measurement of the variable. an officer's rank in the military Group of answer choices

Answers

Answer:

Ordinal

Step-by-step explanation:

Level of measurement used in statistics summarizes what statistical analysis that is possible. There exist three types of level of measurement. The nominal, ordinal and Interval/Ratio level of measurement. Here, our primary focus will be the Ordinal level of measurement.

Ordinal level of measurement indicates the position in a sequence. In the military sector, the officer's rank is said to be Ordinal. This implies that the ordinal level of measurement categorizes variables according to hierarchy or ranks with a meaningful order. Still, the intervals and differences between the variables may not be equal.

Final answer:

The level of measurement for an officer's rank in the military, is classified as ordinal because there's a distinct order but not a measurable difference between ranks.

Explanation:

The level of measurement for an officer's rank in the military is ordinal. This is because it contains a set order or ranking, without a measurable difference between each rank. For instance, a Colonel is above a Captain, but there's no defined 'numeric difference' you can attribute between the two ranks since it's not a sequence of numbers. This is distinct from levels like interval or ratio, where a specific measurable difference could be discerned between the ranks.

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You have a 1 kilogram bag of sugar You use 435 grams to fill the sugar bowls
How much sugar is left in the bag

Answers

The answer is 565g. Unless if there are more bowls, you just minus 435 from 565.
There is 1,000 grams in a kilogram. I just took away 435 from 1,000.
1,000 - 435 = 565 grams left in the bag.

The triangles are congruent by the SSS congruence theorem. Triangles B C D and W X Y are shown. Triangle B C D is shifted up and to the right and then rotates about point D to form triangle W X Y. Which transformation(s) can map TriangleBCD onto TriangleWXY?

Answers

Answer:

C

Step-by-step explanation:

just trust me I didn't finish the test but I'm 99% sure this is correct

Answer:

C. Translation, then rotation

Step-by-step explanation:

May I have brainliest please? :)

Factor each perfect square trinomial. Then, solve the equation by taking the square root of each side.Q1) x^2+14x+49=9



Q2) x^2-16x+64=144



3Q) x^2-2x+1=81

Answers

Answer:

Q2 :) hope this helps!

Step-by-step explanation:

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that Rn(x) ? 0.]f(x) = 10/x , a= -2f(x) = \sum_{n=0}^{\infty } ______Find the associated radius of convergence R.R = ______

Answers

Rewrite f as

f(x)=\frac{10}x=-\frac5{1-\frac{x+2}2}

and recall that for |x|<1, we have

\displaystyle\frac1{1-x}=\sum_(n=0)^\infty x^n

so that for \left|\frac{x+2}2\right|<1, or |x+2|<2,

f(x)=-5\displaystyle\sum_(n=0)^\infty\left(\frac{x+2}2\right)^n

Then the radius of convergence is 2.

Final answer:

The Taylor series for the function f(x) = 10/x, centered at a = -2, is given by the formula  ∑(10(-1)^n*n!(x + 2)^n)/n! from n=0 to ∞. The radius of convergence (R) for the series is ∞, which means the series converges for all real numbers x.

Explanation:

Given the function f(x) = 10/x, we're asked to find the Taylor series centered at a = -2. A Taylor series of a function is a series representation which can be found using the formula f(a) + f'(a)(x-a)/1! + f''(a)(x-a)^2/2! + .... For f(x) = 10/x, the Taylor series centered at a = -2 will be ∑(10(-1)^n*n!(x + 2)^n)/n! from n=0 to ∞. The radius of convergence R is determined by the limit as n approaches infinity of the absolute value of the ratio of the nth term and the (n+1)th term. This results in R = ∞, indicating the series converges for all real numbers x.

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Suppose you are an elementary school teacher. You want to order a rectangular bulletin board to mount on a classroom wall that has an area of 90 square feet. Suppose fire code requirements allow for no more than 30% of a classroom wall to be covered by a bulletin board. If the length of the board is three times as long as the width, what are the dimensions of the largest bulletin board that meets fire code?

Answers

Answer:

3 feet wide and 9 feet long.

Step-by-step explanation:

The classroom wall has an area of 90ft^2.

The fire code requirements allow a bulletin board with an area of at most 30% of 90ft^2. This means that the maximum area of the bulletin board is 27ft^2

Let L and W be the length and wide of the bulletin board.  

If the length of the board is three times as long as the width, then L=3W, and the area of the board is LW=3WW=3W^2

For the largest board we have, 3W^2=27 \Rightarrow W^2=(27)/(3)=9 \Rightarrow W=√(9)=3ft

So, the largest bulletin board that meets the fire code is 3 ft. wide and 9 ft. long.
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