the cube of the sum of 4 and 9 times x divided by the product of 5 times x and the difference of x and 1​

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

(4 + 9x)^3 represents "the cube of the sum of 4 and 9 times x"

and if we divide by "the product of 5 times x and the difference of x and 1," we get

    (4 + 9x)^3

-----------------------

       5x(x - 1)

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How to estimate the quotient of 49.3 divided by 6

Answers

that would be 8 because the answer is 8.21 and you round down to 8

6th grade math! hehe (:

Answers

Answer:

Answer is 8 hours

Step-by-step explanation:

Answer:

8 hours

Step-by-step explanation:

The price of a technology stock has risen to $9.82 today. Yesterday's price was $9.71. Find the percentage increase. Round your answer to the nearest tenth of a percent.​

Answers

The percentage increase is 1.1% to the nearest tenth

The calculation can be done as follows

Original price= $9.82

increase= $9.71

Change in price= 9.82-9.71

= 0.11

percent increase= 0.11/9.82 × 100

= 1.12

= 1.1 (to the nearest tenth)

Hence the percent increase is 1.1%

Please see the link below for more information

brainly.com/question/10613149?referrer=searchResults

Answer:

9.71 ÷ 9.82 = .9987 or 1% .

A local BBQ restaurants offers 2 side dishes with a lunch plate. There are 7 side dishes. How many choices of side dishes does a customer have

Answers

Step-by-step explanation:

This is a question that bothers combination. Combination has to do with selection.

When selecting r objects out of a pool of n objects, the number of ways this can be done is:

nCr = n!/(n-r)!r!

If a local BBQ restaurants offers 2 side dishes with a lunch plate, and there are 7 side dishes, the number of choices that the customer have is expressed as:

7C2 = 7!/(7-2)!2!

7C2 = 7!/(5)!2!

7C2 = 7*6*5!/5! * 2

7C2 = 7*6/2

7C2 = 42/2

7C2 = 21 choices

Hence the customer has 21 choices of side dishes to make

You are on the market for a new car. You want to check whether there is a significant difference between the fuel economy of mid-size domestic cars and mid-size import cars. You sample 17 domestic car makes and find an average fuel economy of 34.904 MPG with a standard deviation of 4.6729 MPG. For imports, you sample 15 cars and find an average MPG of 28.563 MPG with a standard deviation of 8.4988. Construct a 90% confidence interval for the difference between the true average fuel economies in question. Assume the difference will represent (domestic - import). You can also assume that the standard deviations are statistically the same between the two populations.

Answers

Answer:

Step-by-step explanation:

Hello!

The objective is to test if there is a difference between the fuel economy of mid-size domestic cars and mid-size import cars.

For this there are two samples taken:

X₁: Fuel economy of a domestic car.

Sample 1

n₁= 17 domestic cars

X[bar]₁= 34.904 MPG

S₁= 4.6729 MPG

X₂: Fuel economy of an import car.

Sample 2

n₂= 15 import cars

X[bar]₂= 28.563 MPG

S₂= 8.4988 MPG

To estimate the difference between the average economic fuel of domestic cars and import cars, assuming both variables have a normal distribution and both population variances are unknown but equal, the statistic to use is a t-test for two independent samples with pooled sample variance:

(X[bar]₁-X[bar]₂)±t_(n_1+n_2-2;1-\alpha /2) * (Sa*\sqrt{(1)/(n_1) +(1)/(n_2) } )

Sa^2= ((n_1-1)S_1^2+(n_2-1)S^2_2)/(n_1+n_2-2)

Sa^2= (16*(4.6729)^2+14*(8.4988)^2_2)/(17+15-2)= 45.35

Sa= 6.73

t_(n_1+n_2-2;1-\alpha /2) = t_(30; 0.95)= 1.697

(34.904-28.563)±1.697* (6.73*\sqrt{(1)/(17) +(1)/(15) } )

6.341±1.697*2.38

[2.30;10.38]

With a confidence level of 90%, you'd expect that the difference between the average economic fuel of domestic cars and import cars will be contained in the interval [2.30;10.38].

I hope it helps!

calculate the variance and standard deviation for the following samples set of data. 83.6,92.3,56.5,43.8,77.1,66.7. (Do not round intermediate calculation. Round your final answers and the nearest tenth.)​

Answers

Answer:

Variance: 322.4479999999996

Standard Deviation: 17.956837137981722

Final answer:

To calculate the variance and standard deviation for the given sample set of data, find the sample mean, calculate the squared differences, and then find the sample variance and standard deviation.

Explanation:

To calculate the variance and standard deviation for the given sample set of data (83.6, 92.3, 56.5, 43.8, 77.1, 66.7), follow these steps:

  1. Calculate the sample mean by adding all the values together and dividing by the total number of values: (83.6 + 92.3 + 56.5 + 43.8 + 77.1 + 66.7) / 6 = 69.8.
  2. Calculate the squared differences between each value and the sample mean: (83.6 - 69.8)^2, (92.3 - 69.8)^2, (56.5 - 69.8)^2, (43.8 - 69.8)^2, (77.1 - 69.8)^2, (66.7 - 69.8)^2.
  3. Calculate the sample variance by summing up the squared differences and dividing by (n-1), where n is the total number of values: (83.6 - 69.8)^2 + (92.3 - 69.8)^2 + (56.5 - 69.8)^2 + (43.8 - 69.8)^2 + (77.1 - 69.8)^2 + (66.7 - 69.8)^2 = 300.46. Sample variance = 300.46 / 5 = 60.1.
  4. Calculate the sample standard deviation by taking the square root of the sample variance: √60.1 = 7.79. Rounded to the nearest tenth, the sample standard deviation = 7.8.

Learn more about Calculating Variance and Standard Deviation here:

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