Over the past several months, the water level of a lake has been decreasing by 3% each week. If the highest water level before the decrease started was 520 ft, what was the level at the end of 8 weeks?

Answers

Answer 1
Answer:

Answer:

y= 407.54654 ft

Step-by-step explanation:

This is an exponential decay functions

y = ab^x  where a is the initial value and b is ( 1 - rate of decay)

a = 520

b = 1- 3%

y = 520 ( 1- .3) ^x

y = 520 ( .97) ^x

We want x to be 8 weeks

y = 520 ( .97) ^8

y= 407.54654 ft


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2344x24553 math question please answer

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Answer:

57552232

Step-by-step explanation:

Answer and I will give you brainiliest

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Answer: You can buy 5 shirts if you buy 2 pair of pants.

Step-by-step explanation: Just out of curiosity, where do you live? I’m just wondering because I’ve never heard of the AED as a money unit... lol

Answer:

Step-by-step explanation:

Why are you so mean to me

"The municipal transportation authority determined that 58% of all drivers were speeding along a busy street. In an attempt to reduce this percentage, the city put up electronic speed monitors so that drivers would be warned if they were driving over the speed limit. A follow-up study is now planned to see if the speed monitors were effective. The null and alternative hypotheses of the test are H0 : π = 0.58 versus Ha : π < 0.58. It is planned to use a sample of 150 drivers taken at random times of the week and the test will be conducted at the 5% significance level. (a) What is the most number of drivers in the sample that can be speeding and still have them conclude that the alternative hypothesis is true? (b) Suppose the true value of π is 0.52. What is the power of the test? (c) How could the researchers modify the test in order to increase its power without increasing the probability of a Type I Error?"

Answers

Answer:

a) X=77 drivers

b) Power of the test = 0.404

c) Increasing the sample size.

Step-by-step explanation:

This is a hypothesis test of proportions. As the claim is that the speed monitors were effective in reducing the speeding, this is a left-tail test.

For a left-tail test at a 5% significance level, we have a critical value of z that is zc=-1.645. This value is the limit of the rejection region. That means that if the test statistic z is smaller than zc=-1.645, the null hypothesis is rejected.

The proportion that would have a test statistic equal to this critical value can be expressed as:

p_c=\pi+z_c\cdot\sigma_p

The standard error of the proportion is:

\sigma_p=\sqrt{(\pi(1-\pi))/(n)}=\sqrt{(0.58*0.42)/(150)}\n\n\n \sigma_p=√(0.001624)=0.04

Then, the proportion is:

p_c=\pi+z_c\cdot\sigma_p=0.58-1.645*0.04=0.58-0.0658=0.5142

This proportion, with a sample size of n=150, correspond to

x=n\cdot p=150\cdot0.5142=77.13\approx 77

The power of the test is the probability of correctly rejecting the null hypothesis.

The true proportion is 0.52, but we don't know at the time of the test, so the critical value to make a decision about rejecting the null hypothesis is still zc=-1.645 corresponding to a critical proportion of 0.51.

Then, we can say that the probability of rejecting the null hypothesis is still the probability of getting a sample of size n=150 with a proportion of 0.51 or smaller, but within a population with a proportion of 0.52.

The standard error has to be re-calculated for the new true proportion:

\sigma_p=\sqrt{(\pi(1-\pi))/(n)}=\sqrt{(0.52*0.48)/(150)}\n\n\n \sigma_p=√(0.001664)=0.041

Then, we calculate the z-value for this proportion with the true proportion:

z=(p-\pi')/(\sigma_p)=(0.51-0.52)/(0.041)=(-0.01)/(0.041)=-0.244

The probability of getting a sample of size n=150 with a proportion of 0.51 or lower is:

P(p<0.51)=P(z<-0.244)=0.404

Then, the power of the test is β=0.404.

The only variable left to change in the test in order to increase the power of the test is the sample size, as the significance level can not be changed (it is related to the probability of a Type I error).

It the sample size is increased, the standard error of the proprotion decreases. As the standard error tends to zero, the critical proportion tend to 0.58, as we can see in its equation:

\lim_(\sigma_p \to 0) p_c=\pi+ \lim_(\sigma_p \to 0)(z_c\cdot\sigma_p)=\pi=0.58

Then, if the critical proportion increases, the z-score increases, and also the probability of rejecting the null hypothesis.

A plant cell has a length of 0.000085 meters. Which is this length written in scientific notation?

Answers

Answer: The answer would be 8.5 times 10^-5

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  

10  If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Answer:

8.5 x 10^-5

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

10

. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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Answers

Answer:

Argument A: a. strong

Argument B: b. weak

Argument C: a. strong

Argument D: a. Strong

Step-by-step explanation:

Dolphins and whales are mammals. They do not have gills like other fishes for breathing. They have to come to surface of water to breathe. The whales can store oxygen and can stay alive without breathing for more than an hour while dolphins can stay without breathing for few minutes. Harry has struggles with physics and mathematics therefore he cannot be top scorer in this subject based on his past track record.

Find the median of the data of 10, 15 , 6​

Answers

Answer:

10 is the median of the given data....

Answer:

10 is the answers for the question

Step-by-step explanation:

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