The daily high temperatures, in degrees Celsius, for two weeks were recorded. The first week had a mean high temperature of 8 degrees Celsius and a mean absolute deviation (MAD) of 1 degree Celsius. The second week had a mean high temperature of 4.86 degrees Celsius and a mean absolute deviation (MAD) of 1.91 degrees Celsius. Which week had greater variability in high temperature? Explain your reasoning.

Answers

Answer 1

Answer:

The required week that had greater variability in high temperature is week 2.

Given that,
The first week had a mean high temperature of 8 degrees Celsius and a mean absolute deviation (MAD) of 1 degree Celsius.
The second week had a mean high temperature of 4.86 degrees Celsius and a mean absolute deviation (MAD) of 1.91 degrees Celsius.

What is Statistic?

Statistics is the study of mathematics that deals with relations between comprehensive data.

Here,
The system of observation that has a higher mean absolute deviation, will have the chance of greater variability in high temperature. So,
mean absolute deviation of week 1 = 1
mean absolute deviation of week 2 = 1.91
MAD of week 2 > MAD of week 1

Thus, the required week that had greater variability in high temperature is week 2.

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Answer 2

Answer:

Answer:

mean 4.86

MAD = 1.91

Step-by-step explanation:

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What is a 2c − 5b − c a − b simplified?

Answers

All you have to do is combine like terms. 2c and (-c) are like terms (-5b) and (-b) are like terms and a is a term. So, 2c combined with (-c) is C. (-5b) and (-b) combined is (-6b). Since a doesnt need to be combined with anything, you leave it as it is so your answer will then be c - 6b + a (this is the answer assuming that there is a + in front of the a. If there is a - sign, then just change your +a to -a at the end

What is the length of a side of a cube with a volume of 2197 ft3?

Answers

Vloume = (Length)^3
so, Length = (2197)^(1/3)
Length = 13 ft

Point P(3, 9) in the coordinate plane is rotated 90 degrees counterclockwise about the origin. What are the coordinates of its image?Please show all work and not just the answers.

Answers

Answer:

P'(-9, 3)

Step-by-step explanation:

The transformation for rotation counterclockwise about the origin by some angle α will be ...

(x, y) ⇒ (x·cos(α) -y·sin(α), x·sin(α) +y·cos(α))

When the angle is α = 90°, this reduces to ...

(x, y) ⇒ (-y, x)

You have (x, y) = (3, 9), so the image point is P'(-9, 3).

Additional comment

The "work" is applying the right sign and choosing the right coordinate to fill in the values (-y, x). I find it easier to look up the transformations for ±90° and 180°, rather than try to derive them from first principles every time. Your text may have a list:

90° CCW or 270° CW: (x, y) ⇒ (-y, x)
90° CW or 270° CCW: (x, y) ⇒ (y, -x)
180°: (x, y) ⇒ (-x, -y)

Let f(x)=−2x−7. Write a function g whose graph is a translation 6 units to the right of the graph of f

Answers

Answer:

$y=-2x+5$

Step-by-step explanation:

Translation of a Graph

If the graph of y=f(x) is translated a units horizontally and b units vertically, then the equation of the translated graph is:

$y -b=f(x - a)$

The function given in the question is

$f(x)=-2x-7$

We are required to translate it 6 units to the right, or a=6. No vertical translation is required, thus, the function whose graph is 6 units translated to the right is:

$y=-2(x-6)-7$