MATHEMATICS HIGH SCHOOL

In a certain county, the number of charter schools is 6 less than twice the number of alternative schools. We know that there are 52 charter schools in the county. How many alternative schools are in the county?

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

Answer 2

Answer:

Answer:

Step-by-step explanation:

So, 52 charter schools and the number is 6 less than the alternative schools doubled. In order to find the number of alternative schools, we need to reverse the equation. 52+6=58. That means 58 is twice the amount of alternative schools. 58/2 equals 29, therefore the answer is 29

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Find (f - g)(x) if f(x) = x2 - x - 6 and g(x) = 2x2 - 3x + 4a. -x2 + 2x - 10 b. x2 - 4x - 2 c. 3x2 - 4x - 2 d. x2 + 2x - 10

Which number is larger, .8 or .1?

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This is a statement that is ALWAYS true, forwards and backwards.

Answers

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PLEASE HELP!!!The probability of drawing a green marble from a marble bag is 20%. What are the odds in favor of drawing a green marble?
1:5
4:1
5:1
1:4

Answers

there is a 1:5 chance you will draw a greed marble

Solve –5√ x = –15.

A. x = –7
B. x = –9
C. x = 7
D. x = 9

Answers

Answer:

Option (d) is correct.

$x=9$

Step-by-step explanation:

Given : expression $-5√(x)=-15$

We have to solve for x.

Consider the given expression $-5√(x)=-15$

Divide both side by -5, we have,

$√(x)=(-15)/(-5)$

Simplify, we have,

$√(x)=3$

Squaring both side, we get,

$(√(x))^2=3^2$

Simplify, we get,

$x=9$

Thus, Option (d) is correct.

-5√x = -15
-5 -5
√x = 3
x = 9

The answer is D.

Solve rational inequality x²+x-6/x²-3x-4≤0?

Answers

Applying division signal rules, from the graphs of both functions, it is found that the solution of the inequality is:

$x \in [-3,-1) \cup [2,4)$

------------------

A fraction, which represents a division, is negative if the numerator and the denominator have different signals. Thus, to solve this inequality, we have to study the signals of the numerator and the denominator.

The numerator is: $f(x) = x^2 + x - 6$

It is the first graph appended at the end of this answer.
From the graph, we have that it is negative or zero on [-3,2], and positive on the rest of the interval.

The denominator is: $g(x) = x^2 - 3x - 4$

It is the second graph appended at the end of this answer.
The denominator cannot be zero, so we consider only the interval (-1,4), in which it is negative.

Numerator positive, denominator negative: On interval [2,4).
Denominator positive, numerator negative. On interval [-3,-1).

Thus, the solution is:

$x \in [-3,-1) \cup [2,4)$

A similar problem is given at brainly.com/question/14361489

Answer:

x ∈ [-3;-1) ∪ [2;4)

Step-by-step explanation:

$(x^(2)+x-6 )/(x^(2)-3x-4 )\leq 0\n=> ((x-2)(x+3))/((x+1)(x-4)) \leq 0\n$

we have this board:

x -3 -1 2 4

x - 2 - - - 0 + +

x+3 - 0 + + + +

x+1 - - 0 + + +

x-4 - - - - 0 +

$((x-2)(x+3))/((x+1)(x-4))$ + 0 - || + 0 - || +

from the board

=> x ∈ [-3;-1) ∪ [2;4)

What mathematical operation applies (addition, subtraction, multiplication or division) and write your equation in the box below.

Answers

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