If $8 = 3/5 of the bill how much was the bill

Answers

Answer 1

Answer: $8=3/5b

3b=$40

b=$40/3

b=$13.33

Answer 2

Answer: $13.33 or $33 1/3 ^^

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Simplify 19 - 1.67 + (2.4)

Answers

Answer:

19.73.

Step-by-step explanation:

Given : 19 - 1.67 + (2.4).

To find : simplify.

Solution : We have given 19 - 1.67 + (2.4).

By the BODMAS rule :

First we open the parenthesis

19 - 1.67 + 2.4

Now we solve the addition operation

19+2.4 -1.67

21.4 -1.67.

Now we will solve the subtraction operation :

19.73.

Therefore, 19.73.

The answer is 19.73 because 19 minus 1.67 is 17.33 and 17.33 plus 2.4 is 19.73

I need help on 2 and 3 please

Answers

2. A
3. A
2 times x is 2x, 2 times y is 2y; therefore it is 2y +2x
2 times 3x is 6x, there is no possible way for the answer to be 5x

if you multiply the outside number by all the terms in the parenthesis you'll get;
2(x + y) = 2(x) + 2(y)= 2x + 2y giving you A as your answer in Q.#2.
And for Q.#3 the its the same steps;
2(3x) = 2(3)(x) = 6x Giving you A as your answer cause; 5x is not equivalent and the others are equivalent to 6x by multiplying as I explained you.
hope that helps :D

The length of a classroom is 34 feet in yard and frets

Answers

There are 3 feet in 1 yard

divide 34/3 = 11 with a remainder of 1

The remainder 1 is the remaining foot ,

Answer : 34 feet is 11 yards and 1 foot

I hope that's help !

the answer is 1156. I'm positive it is the answer.

What is the value of the 2 in 13721 compared to the value of the 2 in 11259

Answers

We need to find the place value of 2 in the digit 13721.

In the digit 13721, 2 is at tens place therefore, the place value of 2 in 13721 is 20.

Now, we will find the place value of 2 in the digit 11259.

In the digit 11259, 2 is at hundreds place, so the place value of 2 in 11259 is 200.

We can see that the difference between the place values of 2s in two different digits that is 13721 and 11259 is of 10 folds.

A red string of lights blinks once every 3 seconds while a string of blue lights blink once every 4 seconds. How many times will both sets of lights blink at the same time in 60 seconds?

Answers

the string of red lights will blink 20 times and the blue lights will be 15 60 divided by 4 is 15 and 60 divided by 3 is 20

Solution to this inequality. 72≥b+95

Answers

Answer:

b≤-23

Step-by-step explanation:

72≥b+95 Move terms

-b≥95-72 subtract

-b≥23

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