The front of a box is a square with an area of 175 square units. What would be the best represents S, the length of the edge of the front of the box in units? Round your answer to the nearest tenth.

Answers

Answer 1
Answer:

Answer:

  13.2

Step-by-step explanation:

√175 ≈ 13.2 . . . units

The area of a square is the square of the edge length. Hence, the edge length is the square root of the area.


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The graph of y=f(x) is shown below. What are all of the read solutions of f(x) = 0?

Answers

Answer:

0, -1, -3

Step-by-step explanation:

f(x) = y = height of the line plotted

if you treat the x axis as the "ground" or "floor"....you're looking for the point when the graph "hits" the "floor", meaning zero height.

The answers are 0,-1,-3

Which equation represents the line that passes through the point (1, 5) and has a slope of -2?

Answers

Answer:

y=-2x+7

Step-by-step explanation:

y-y1=m(x-x1)

y-5=-2(x-1)

y=-2x+2+5

y=-2x+7

John is playing a game of darts. The probability that he throws a dart into the center of the dart board (the Bull’s eye) is 1/10. The probability that he throws the dart into the 10-point ring is 3/10.What is the probability that he either hits a Bull’s eye or scores 10 points?
a. 1/3
b. 2/3
c. 3/5
d. 2/5
e. 1/4

Answers

The correct answer for the question that is being presented above is this one: "d. 2/5." John is playing a game of darts. The probability that he throws a dart into the center of the dart board (the Bull’s eye) is 1/10. The probability that he throws the dart into the 10-point ring is 3/10. The probability that he either hits a Bull's eye or scores 10 points is 2/5

Answer: The correct option is (d). (2)/(5).

Step-by-step explanation: Given that John is playing a game of darts. The probability that he throws a dart into the centre of the dart board (the Bull’s eye) is (1)/(10) and the probability that he throws the dart into the 10-point ring is (3)/(10).

We are to find the probability that he either hits a Bull’s eye or scores 10 points.

Let, 'A' and 'B' represents the events that John throws the dart into a Bull's eye and 10-point ring respectively.

Then, according to the given information, we have

P(A)=(1)/(10),~~P(B)=(3)/(10),~~~P(A\cup B)=?

Since John cannot throw the dart into the Bull's eye and 10 point ring together, both the events are independent of each other.

Therefore,

P(A\cap B)=0

From the theorems of probability, we have

P(A\cup B)=P(A)+P(B)-P(A\cap B)=(1)/(10)+(3)/(10)-0=(4)/(10)=(2)/(5).

Therefore, the probability that John either hits a Bull’s eye or scores 10 points is (2)/(5).

Thus, (d) is the correct option.

Please help! Hi, I'm stuck on a part of this question, we have to solve using Gauss Jordan Elimination: A corporation wants to lease a fleet of 12 airplanes with a combined carrying capacity of 220 passengers. The three available types of planes carry 10,15,20 passengers. How many of each type of plane should be leased?

Answers

Do common sense has anything to do with this question? Because 
corporation might forget the arbitrary 12 airplane rule 
and have 11 times 20 = 220. 
But perhaps they get a discount if all 12 hangars are used! 

Playing by the rules of the question:- 
Let a, b, c be the aeroplanes that carry 
10, 15, and 20 passengers, respectively, 

a + b + c = 12 
10a +15b +20c = 220 

We may rearrange these as 
4a + 4b + 4c = 48 
2a + 3b + 4c = 44 
Now subtract 
2a + b = 4 

There appear to be 3 options 
a = 0, b = 4 which means 220 = 0*10 + 4*15 + 8*20 
a = 1, b = 2 which means 220 = 1*10 + 2*15 + 9*20 
a = 2, b = 0 which means 220 = 2*10 + 0*15 + 7*20 

If you dismiss the ones with zeros it may be that 
the expected answer to "How many of each plane" is 

One that carries 10, 2 that carries 15, and 9 that carries 20 

Faye owned 1,300 shares of Wonderband Corp. Last week, a 2-for-1 split was executed. The pre-split price per share was w dollars. a. Determine the number of shares Faye owned after the split. b. Write an algebraic expression for the price per share after the split. c. Express the total value of the Wonderband stock Faye owned algebraically after the split.

Answers

Answer:

A = 1/2 1300 = 2600

Step-by-step explanation:

B 1/2 w = 1/2w

c = 1300w before  2600 1/2w = 1300 after

If a plane travels 300 mph, how many miles will it travel in 18 min?

Answers

The plane travelling at a speed of 300 mph will travel 90 miles in 18 minutes.

What is unit rate?

A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate.

Given that, a plane travels 300 mph,

That means, its unit rate is 300 mph

Therefore, in 60 minutes it will travel 300 miles

Therefore, in 1 minute it will travel = 300 / 60 = 5 miles

Thus, in 18 minutes it will travel = 5 x 18 = 90 miles

Hence, the plane travelling at a speed of 300 mph will travel 90 miles in 18 minutes.

Learn more about unit rates, click;

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Answer:

6 hours.

Step-by-step explanation:

1800/300. time =distance / rate