imagine an investigation in which 40 students were asked to determine their chronotype by choosing from among four chronotypes instead of three: morning person, night person, neither, or both. If there is no relationship between chronotype and birth month, about what fraction of the students would you expect to pick the chronotype that matches their birth month? why do you think this?

Answers

Answer 1

Answer:

Step-by-step explanation:

A chronotype is a behavioral manifestation of an underlying circadian rhythms of the myriad physical processes.

The chronotype word may be defined as an individual's natural tendency to remain active mostly at certain times of the day. Some people remain active and alert in the early time of the day and some are alert and active in the late night.

The chronotypes are : Morning person, night person, neither/both.

It is assume that the birth month and year of a person influences his or her chronotype. But if birth month is not related to theses personality traits of a person, then it can be expected that nearly 1/3rd of the fraction of the students in class picks the chronotype which corresponds to their birth type.

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Answers

Answer:

They played 4 games and paid $19

Step-by-step explanation:

4x + 3 = 2x + 11 (You basically have to solve for X)

4x - 2x = 11 - 3 (move like terms together)

2x = 8

x = (8/2)

x = 4

This means they had to play 4 games.

To get how much they paid, just plug 4 into any one of those given equations (They will both give the same answer).

4x + 3 ⇒ 4(4) + 3 = $19

To check if this is true,

2x + 11 ⇒ 2(4) + 11 = $19

Therefore, they paid $19

Answer:

$19 and played 4 games

Given the function f(x) = 5x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.Part A: Find the average rate of change of each section. (4 points)
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

Answers

Average rate of change from x = 0 to x = 1 is $(f(1)-f(0))/(1-0)= (5(1)-5(0))/(1)=5$
Average rate of change from x = 2 to x = 3 is $(f(3)-f(2))/(3-2)= (5(3)-5(2))/(1)=15-10=5$
The average rate of change of both sections are equal.

Solve for x. Leave your answer in simplest radical form.

Answers

There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be "y "

According to Pythagoras theorem,

$\boxed{ \large \boxed{h {}^(2) = {b}^(2) + p{}^(2) }}$

note :

p = perpendicular / opposite side
b = base / adjacent side
h = hypotenuse

let's solve for " y² " first ( square of other missing side )

$➢ \: \: {y}^(2) = {8}^(2) + 3 {}^(2)$

$➢ \: \: {y}^(2) = 64 + 9$

$➢ \: \: {y}^(2) = 73$

now let's solve for "x " , by using pythagorous theorem

$➢ \: \: {x}^(2) = {y}^(2) + {6}^(2)$

$➢ \: \: {x}^(2) = 73 + 36$

$➢ \: \:x {}^(2) = 109$

$➢ \: \: x = √(109)$

Approximate :

$➢ \: \: 10.44 \: \: units$

$\mathrm{✌TeeNForeveR✌}$

A soccer player boasts that he is able to kick a ball past 100 yards on 5 consecutive tries. You know that he's usually able to kick that distance 20% ofthe time. You create a model of how he kicks and run a simulation based on it, using (0 - 1) to represent his successes at kicking past 100 yards.

56421 88976 54893 20015 46504 98746 13210 77410

How many consecutive kicks past yards does the model show for the player?
A. 3 B. 2 C. 0 D. 1

Answers

Let 0-1 be successes and 2-9 be failures. Using the simulation, we get:

5642188976548932[001]546504987461321077410

The most consecutive kicks he gets past one hundred yards is A. three.

Answer: 3

Step-by-step explanation:

The price of a pair of trousers was decreased by 22% to $30. What was the original price of the trousers?