Ashley Traveled 10 miles north, then 8 miles east, then 9 miles south on her boat

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Answer 1
Answer: what’s the rest of the question...?

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A study published in 1993 found that babies born at different times of the year may develop the ability to crawl at different ages! The author of the study suggested that these differences may be related to the temperature at the time the infant is 6 months old. (Benson and Janette, Infant Behavior and Development [1993]. The study found that 32 babies born in January crawled at an average age of 29.84 weeks, with a standard deviation of 7.08 weeks. Among 21 July babies, crawling ages averaged 33.64 weeks, with a standard deviation of 6.91 weeks. Is this difference significant?

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Answer:

t=\frac{(29.84-33.64)-0}{\sqrt{(7.08^2)/(32)+(6.91^2)/(21)}}}=-1.939  

p_v =2*P(t_(51)<-1.939)=0.0580  

Comparing the p value with the significance assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the difference between the two groups is NOT significantly different at 1% of significance.  

Step-by-step explanation:

Data given

\bar X_(1)=29.84 represent the mean for sample January

\bar X_(2)=33.64 represent the mean for sample July

s_(1)=7.08 represent the sample standard deviation for 1  

s_(2)=6.91 represent the sample standard deviation for 2  

n_(1)=32 sample size for the group 2  

n_(2)=21 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_(1)-\mu_(2)=0  

Alternative hypothesis:\mu_(1) - \mu_(2)\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_(1)-\bar X_(2))-\Delta}{\sqrt{(\sigma^2_(1))/(n_(1))+(\sigma^2_(2))/(n_(2))}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=32+21-2=51  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(29.84-33.64)-0}{\sqrt{(7.08^2)/(32)+(6.91^2)/(21)}}}=-1.939  

P value  

Since is a bilateral test the p value would be:  

p_v =2*P(t_(51)<-1.939)=0.0580  

Comparing the p value with the significance assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the difference between the two groups is NOT significantly different at 1% of significance.  

What is 0945987123987634678 divided by 67899876543444445678

Answers

Answer:35652846437467

Step-by-step explanation:simple math

Step-by-step explanation:

1.23

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Tony worked 9 hours Monday, 9.5 hours Tuesday, 8.75 hours Wednesday,9.25 hours Thursday 8 hours Friday and 6 hours Sunday. How many hours
did he work?

Answers

The answer is 50.5 hours

all you have to do is add all the hours up to get the grand total.

Hope this helps

have a great day!

3x+7x−28+31−8x for x=2043
Simplified expression-?
Value-?

Answers

The expression 3x + 7x - 28 + 31 - 8x simplifies to 2x + 3. When x equals 2043, the value of the Simplifying Expression is 4089.

The given expression is 3x + 7x - 28 + 31 - 8x.

To simplify the expression, we first group together the like terms.

Thus, the expression becomes (3x + 7x - 8x) + (31 - 28).

This simplifies further to 2x + 3.

Next, to find the value of the expression for x = 2043, we substitute 2043 for x into the simplified expression, resulting in 2*2043 + 3 = 4089.

Therefore, the simplified version of the expression is 2x + 3 and the value of the expression for x = 2043 is 4089.

Learn more about Simplifying Expression here:

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The answer is 16347 hope this helps

Mr. Ruiz drove 205 miles in 5 hours on Saturday and 180 miles in 4 hours on Sunday. What was his average speed, in miles per hour, for the two days

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Answer:

In miles per hour was 34 mph

Step-by-step explanation:

205/5 = 41

180/4 = 27

to find the average you add both speeds then divide by how many there are.

41 + 27 = 68

68/2 = 34

Help math math math

Answers

Answer:

Yes

Step-by-step explanation:

Answer:

The answer is Yes. Hope this helps :)

Step-by-step explanation: