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Both the galapagos Islands and the island of naura are on the equator, but the galapagos Islands are at 90.30 degree West whereas the island of naura is at 166.56 degree east. How far is it from galapagos Islands to naura travelling over the pacific ocean along the equator, correct to the nearest km

Answers

Answer 1

Answer:

11481.4875 km

Step-by-step explanation:

Given the that :

Galapagos island and Island of Naura are on the equator

Galapagos = 90.30°W

Island of Naura = 166.56°E

Ensuring same bearing is used for both :

Island of Naura = 166.56°E = (360° - 166.56°) = 193.44°W

Hence, we can calculate the difference in the bearing of both locations :

(193.44 - 90.30)°W = 103.14°

Hence the distance between Galapagos and Island of Naura along the equator is :

(Difference in bearing / total bearing) * earth's Circumference

Earth's Circumference = 40,075km

(103.14 / 360) × 40,075

0.2865 × 40,075

= 11481.4875 km

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Answers

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An entrepreneur is considering the purchase of a coin-operated laundry. The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75. A sample of 30 days reveals a daily average revenue of $625. If you were to test the null hypothesis that the daily average revenue was $675, which test would you use?

a. Z-test of a population mean

b. Z-test of a population proportion

c. t-test of population mean

d. t-test of a population proportion

Answers

The Z-test of a population mean is used here because it is given that the population standard deviation is $75. The correct option is a).

Given :

The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75.
A sample of 30 days reveals a daily average revenue of $625.

Let $\mu$ is the daily average revenue. So:

Null Hypothesis is, $\rm H_0:\mu=$675$

The Alternate Hypothesis is, $\rm H_a : \mu\neq $675$

Here, the Z-test of a population mean is used because it is given that the population standard deviation is $75.

$\rm Test \;Statistics = \frac{\bar{X}-\mu}{(\sigma)/(√(n) )}$

where $\rm \bar {X}$ is the sampleaverage revenue, $\sigma$ is the standard deviation and n is the sample size.

Therefore, the correct option is a).

For more information, refer to the link given below:

brainly.com/question/13245779

Answer:

We would use Z-test of a population mean.

Step-by-step explanation:

We are given that an entrepreneur is considering the purchase of a coin-operated laundry. The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75. A sample of 30 days reveals a daily average revenue of $625.

And we have to test the hypothesis that the daily average revenue was $675.

Firstly, as we know that testing is always done on the population parameter.

So, let $\mu$ = daily average revenue over the pat 5 years

So, Null Hypothesis, $H_0$ : $\mu$ = $675

Alternate Hypothesis, $H_a$ : $\mu \neq$ $675

Here, null hypothesis states that the owner's claim of average daily revenue was $675 over the past 5 years is correct.

And alternate hypothesis states that the owner's claim of average daily revenue was $675 over the past 5 years is not correct.

The test statistics that will be used here is Z-test of a population mean because here we have knowledge of population standard deviation of $75.

Test statistics = $(\bar X-\mu)/((\sigma)/(√(n) ) )$ ~ N(0,1)

where, $\bar X$ = sample average revenue = $625

$\sigma$ = population standard deviation = $75

n = sample of days = 30

Therefore, to test the null hypothesis that the daily average revenue was $675, we should use Z-test of a population mean.

A Triangle has an angle that measures 137.3 degrees. The other two angles are in a ratio of 3:4. What are the measures of those two angles?

Answers

so we start off by subtracting 137.3 from 180 getting 42.5. If you add the ratios up (3+4) you get 7 and 7 should equal 42.5. thus,

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The following data give the prices of seven textbooks randomly selected from a university bookstore. $93 $173 $107 $125 $56 $163 $144 a. Find the mean for these data. Calculate the deviations of the data values from the mean. Is the sum of these deviations zero? Mean = $ 123 Deviation from the mean for $173 = $ 0 Sum of these deviations = $ -433 b. Calculate the range, variance, and standard deviation. [Round your answers to 2 decimal places.] Range = $ Variance = Standard deviation = $ Click if you would like to Show Work for this question: Open Show Work LINK TO TEXT

Answers

Answer:

Mean = $123

Standard deviation = 10190

Variance = 1698

Step-by-step explanation:

Mean=?

= sum of all numbers/ Total numbers

a = 93+173+107+125+56+163+144 / 7 = 861/7 = $123

Standard deviation=?

we know that = Sqareroot [ Sum (y)²] / N

we need deviation:

= x-a = y ; y²

= 93-123 = -30 ; 900

=173-123 = 50 ; 2500

=107-123 = -16 ; 256

=125-123 = 2 ; 4

=56-123 = -67 ; 4489

=163-123 = 40 ; 1600

=144-123 = 21 ; 441

Sum of y² = 10190.

= Square root [ 10190 / 7 ]

= 38.1

Variance = ?

= Sum ( y)² / N-1

= 10190 / ( 7-1)

= 10190 /6

= 1698

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Answers

Answer:

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Step-by-step explanation:

Answer:

((−5)(−3))(−3)

=−45

hope this was helpful!

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Answers

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