How can a mixture be separated into pure substances?

Answers

Answer 1
Answer:

A mixture can be separated into pure substances with the utilization of several techniques of physical methods like simple distillation, centrifugation, sedimentation, etc.

What is the function of simple distillation?

Simple distillation may be defined as a type of separation technique that involves the separation of solvent from a solution. This technique is utilized for purifying the liquids that comprise either nonvolatile impurities such as sand, salt, and other very small amounts of particles.

Apart from simple distillation, evaporation is also used to eliminate water or any liquid substance from a mixture. It makes the solution or mixture dry with the absolute absence of water.

The Centrifugation technique is used to separate the particles on the basis of their size, shape, density, viscosity, and rotor speed.

Therefore, with the utilization of separation techniques, one can easily separate a mixture into pure substances.

To learn more about Separation techniques, refer to the link:

brainly.com/question/14482995

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Answer 2
Answer:

Answer:

mixture can be separated into pure substances by simple distillation


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Scientific notation for 5,098,000

Answers

When you do not see the decimal just put it at the very end of the problem! 
So now 5,098,000.
Now we need to move the decimal over to make this problem greater than 1 and less than 10. So if we but the decimal Right after 5 we have 5.098 which is greater than 1 and less than 10.
So now we write it out like this
5.098*10^x
let's find x.
X is how many times we moved the decmal over, in this case 6.So now
5.098*10^6
Does this help?

5.098*10^6    , this is the correct answer
                                                         

What are three types of blood vessels?capsules
arteries
veins
capillaries
lung

Answers

Arteries, Veins, and Capillaries

Then there will be an increase in the demand for most goods.If there is an increase in
А consumer price
B. production cost
C. quantity supply
D. consumer income
Please select the best answer from the choices provided
OA
OB
С
&
D

Answers

Answer:

d)consumer income

Explanation:

Answer:

D. consumer income

Explanation:

Edge 2020

A substance that can be separated into two or more substances only by a chemical change is

Answers

A substance that can be separated into two or more substances only by a chemical change is known as a heterogeneous mixture

What is the difference in a transverse and a longitudinal wave?Group of answer choices

Transverse waves are bigger than longitudinal waves

A transverse wave has crests and troughs and a longitudinal has compressions and rarefactions.

Transverse waves are sound waves and longitudinal waves are light waves.

Answers

Answer:

A transverse wave has crests and troughs and a longitudinal has compressions and rarefactions.

A closed system initially containing 1×10^-3M H2 and 2×10^-3 at 448°C is allowed to reach equilibrium. Analysis of the equilibrium mixture show s that the concentration of HI is 1.87×10^ -3. Calculate Kc at 448°C for the reaction.

Answers

Answer:

1.74845

Explanation:

We have the following reaction:

I2 + H2 => 2 HI

Now, the constant Kc, has the following formula:

Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b

In this case I2 is A, H2 is B and C is HI

We know that the values are:

 H2 = 1 × 10 ^ -3 at 448 ° C

I2 = 2 × 10 ^ -3 at 448 ° C

HI = 1.87 × 10 ^ -3 at 448 ° C

Replacing:

Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}

Kc = 1.87 ^ 2/2 * 1

Kc = 1.74845

Which means that at 448 ° C, Kc is equal to 1.74845

Answer:

K_c = 51

Explanation:

[H2] = 10^-3

[I2] = 2*10^-3

[HI] = 0

in equilbiirum

[H2] = 10^-3 - x

[I2] = 2*10^-3 -x

[HI] = 0 + 2x

and we know

[HI] = 0 + 2x = 1.87*10^-3

x = ( 1.87*10^-3)/2 =  0.000935

then

[H2] = 10^-3 - 0.000935 = 0.000065

[I2] = 2*10^-3 -0.000935 = 0.001065

                        H₂                +          I              ⇄              2 HI

Initially     1 × 10⁻³                       2 × 10⁻³

Change  -9.35 × 10⁻⁴               -9.35 × 10⁻⁴                +1.87 × 10⁻³

At equil   6.5 × 10⁻⁵                  1.06 5 × 10⁻³               1.87 × 10⁻³

HI increase by 1.87 × 10⁻³M

K_c = ([HI]^2)/([H_2][I_2]) \n\n= ((1.87*10^-^3)^2)/((6.5*10^-^5)(1.065*10^-3)) \n\nK_c = 51