MATHEMATICS COLLEGE

Shipping box that is length=3 3/4ft width=3ft height=3 1/4 what is the volume and how to work it out

Answers

Answer 1

Answer:

Answer:

36 9/16 ft^3

Step-by-step explanation:

volume = length * width * height

volume = 3 3/4 ft * 3 ft * 3 1/4 ft

Change all mixed numerals to fractions.

volume = 15/4 * 3/1 * 13/4 ft^3

volume = 585/16 ft^3

volume = 36 9/16 ft^3

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What is the height of a
triangle with area 893 square
inches and base 38 inches?

Answers

Here is the answer.

Answer:

Step-by-step explanation:

Start by drawing the figure and labeling it with the given information. We are looking for the height of a triangle. The formula for the area of a triangle is A=12bh, where b is the length of the base and h is the height of the triangle. Substituting in the given information and solving for h, we find

A8938931947=12bh=12(38)(h)=h=h

The height is 47 inches.

The principles of probability help bridge the worlds of _____________ statistics and _____________ statistics.

Answers

(a) Descriptive

(b) Inferential

Descriptive statistics uses the data to provide descriptions of the population, either through numerical calculations or graphs or tables.

Inferential statistics makes inferences and predictions about a population based on a sample of data taken from the population in question

A company is giving gifts to its employees. Employees can choose a gift card, hat, or candy. The table shows the gift chosen by 150 employees. Type of Gift Number of EmployeesGift Card
90

Hat
10

Candy
50

Based on this data, about how many employees will choose a gift card if there are 600 employees choosing gifts?

Enter your answer in the box.

Answers

Answer:

360 Employees

Step-by-step explanation:

Number of employees who chose gift card / Number of total employees

= 90 / 150

Now, we have to figure out in x / 600 when the x represents the number of employees choosing gift card when there are 600 employees in total.

90 / 150, x / 600

-> cross multiply

54,000 = 150x

Therefore 360 = x.

another way:

(multiply the total number of employees in both ratios) 600 / 150 = 4

Now we multiply 4 by 90 (number of employees choosing gift card)

4*90 = 360

Final answer:

Based on the proportion of employees who chose a gift card in the provided data (60%), you could expect about 360 out of 600 employees to choose a gift card if the same proportion holds.

Explanation:

The given data details that out of 150 employees, 90 have chosen a gift card as a gift. This means that around 60% of the employees have chosen a gift card (90/150 = 0.6 or 60%). To determine how many out of 600 employees might choose a gift card, given the same proportion, one would need to multiply 600 by 60%.

Step 1: Calculate the proportion of employees that chose a gift card. This is 90 out of 150, or 90/150 = 0.6 (60%).

Step 2: Multiply the total number of employees by the proportion who chose a gift card. This is 600 * 0.6 = 360.

Therefore, you could reasonably expect that about 360 out of 600 employees might choose a gift card as their gift if the same proportion holds.

Learn more about Proportion Calculation here:

brainly.com/question/31010676

#SPJ12

Graph the following function and then find the specified limits. When necessary, state that the limit does not exist.f(x)equals=left brace Start 3 By 2 Matrix 1st Row 1st Column x minus 3 2nd Column if x less than 5 2nd Row 1st Column 2 2nd Column if 5 less than or equals x less than or equals 6 3rd Row 1st Column x plus 4 2nd Column if x greater than 6 EndMatrixx−3 if x<52 if 5≤x≤6x+4 if x>6;findModifyingBelow lim With x right arrow 5limx→5 f(x)andModifyingBelow lim With x right arrow 6limx→6 f(x)

Answers

If I'm reading the question right, you have

$f(x)=\begin{cases}x-3&\text{for }x<5\n2&\text{for }5\le x\le6\nx+4&\text{for }x>6\end{cases}$

and you have to find

$\displaystyle\lim_(x\to5)f(x)\text{ and }\lim_(x\to6)f(x)$

The limits exist if the limits from either side exist. We have

$\displaystyle\lim_(x\to5^-)f(x)=\lim_(x\to5)(x-3)=2$

$\displaystyle\lim_(x\to5^+)f(x)=\lim_(x\to5)2=2$

$\implies\displaystyle\lim_(x\to5)f(x)=2$

and

$\displaystyle\lim_(x\to6^-)f(x)=\lim_(x\to6)2=2$

$\displaystyle\lim_(x\to6^+)f(x)=\lim_(x\to6)(x+4)=10$

$\implies\displaystyle\lim_(x\to6)f(x)\text{ does not exist}$

Final answer:

The function f(x) is a piecewise function. The limit as x approaches 5 equals 2 and the limit as x approaches 6 does not exist as the values from both sides are not the same.

Explanation:

The function f(x) given is a piecewise function which is defined differently on different intervals of x.

First let's graph these three conditions:

For x < 5, f(x) = x - 3. It is a straight line that crosses the Y-axis at -3.
For 5 ≤ x ≤ 6, f(x) = 2. It is a horizontal line along the height of 2 from x=5 to x=6.
For x > 6, f(x) = x + 4. It is a straight line that crosses the Y-axis at 4.

Next, we'll find the specified limits:

limx→5 f(x): As x approaches 5, we will look at values from both sides. From the left (x < 5), it would be 5 - 3 = 2. From the right (5 ≤ x ≤ 6), f(x) = 2. The value is the same from both sides, so the limit as x approaches 5 equals 2.
limx→6 f(x): As x approaches 6, from the left (5 ≤ x ≤ 6), f(x) = 2. From the right (x > 6), it would be 6 + 4 = 10. The values are not the same from both sides, so the limit as x approaches 6 does not exist.