3 2/5 times 4/7 times 1/2 equals

Answers

Answer 1

Answer:

3 2/5×4/7×1/2=68/35×1/2=34/35

Therefore, the answer is 34/35

HOPE THIS HELPS!!!!!!!!

Answer 2

Answer: Ok so first you would have to do this...1. Turn 3 2/5 into a improper fraction: 3x5=15+2=17/52. Do 17/5 x 4/7: 17x4=68 and 5x7=35 so that would be 68/353. Then do 68/35 x 1/2: 68x1=68 and 35x2=70 so that would be 68/704. Finnaly you would reduce which means 68/70: 34/35So your answer would be 34/35

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Find x and y of this triangle.

Answers

Question

Find x and y of this triangle.

Answer:

x = 52°

y = 23°

Step-by-step explanation:

the sum of the interior angles of a triangle is 180°

from the picture you have 90°, 67° and y in one triangle

and 90°, 38° and x in the other.

triangle with y:

180 - 90 - 67 = 23°

triangle with x

180 - 90 - 38 = 52°

What is an increasing or decreasing interval of a parabola? Is it like the vertex or turning point of the parabola? I don't remember. :(

Answers

Well first, an interval is a set of real numbers, usually x values. For example 0 ≤ x ≤ 1 is an interval. If the y values for the x values of the set increase as the x values increase, then the interval is increasing. If the y values for the x values of the set decrease as the x values increase, then the interval is decreasing. I hope that wasn't confusing, if you have questions, ask.

Three workers arrive at work 15 minutes late, at a cost of $11/hour how will it cost company?

Answers

$1h=60min\n\n\begin{array}{ccc}60min&-&\$11\n\n15min&-&\$x\end{array}\n\n\ncross\ multiply:\n\n60x=11\cdot15\ \ \ /:60\n\nx=(11\cdot15)/(60)\n\nx=(11)/(4)\n\nx=2.75\ (\$)\leftarrow Answer$

$other\ method:\n\n\$11\ -\ 60min\ \ \ \ /:4\n\n\$11:4\ -\ 60min:4\n\n\$2.75\ -\ 15min$

$Answer:a\ cost\ (\$2.75)/(15min)$

I am writing this question only to see how smart the community on Brainly is.What is the 3rd derivative of $f(x)=sin(x)x^3+x^2tan(x)$

Answers

I am very confused as to why you posed this question in the way you did. People would have answered your question regardless.

First derivative:
f'(x) = 3x^2sin(x) + x^3cos(x) + 2xtan(x) + x^2sec^2(x)

Second derivative:
f''(x) = 6xsin(x) + 3x^2cos(X) + 3x^2cos(x) - x^3sin(x) + 2tan(x) + 2xsec^2(x) + 2xsec^2(x) + 2x^2sec^2(x)tan(x)

f''(x) = 6xsin(x) + 6x^2cos(x) - x^3sin(x) + 2tan(x) + 4xsec^2(x) +

Third Derivative:
f'''(x) = 6sin(x) + 6xcos(x) + 12xcos(x) - 6x^2sin(x) - 3x^2sin(x) - x^3cos(x) + 2sec^2(x) + 8xsec^2(x)tan(x) + 4sec^2(x) + 4x^2sec^2(x)tan^2(x) + 4xsec^2(x)tan(x) + 2x^2sec^4(x)

f'''(x) = 6sin(x) + 18xcos(x) - 9x^2sin(x) - x^3cos(x) + 12xsec^2(x)tan(x) + 6sec^2(x) + 4x^2sec^2(x)tan^2(x) + 2x^2sec^4(x)

f'''(x) = (6 - 9x^2)sin(x) + (18x - x^3)cos(x) + 12xsec^2(x)tan(x) + 6sec^2(x) + 4x^2sec^2(x)tan^2(x) + 2x^2sec^4(x)

There are many more ways this can be factored, but if this is just to test whether someone knows the basics of calculus, this should be sufficient.

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Answers

No, because in a set of data with outliers, the median would not be affected by the mean would be.

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