PHYSICS COLLEGE

A toy car that is 0.12 m long is used to model the actions of an actual car thatis 6 m long. Which ratio shows the relationship between the sizes of the
model and the actual car?
A: 5:1
B: 1:50
C: 50:1
D: 1:5

Answers

Answer 1

Answer:

Answer:

it is B 1:50

Explanation:

just did it on apex

Answer 2

Answer:

Final answer:

The ratio that shows the relationship between the sizes of the model car and the actual car is 1:50. This is because the actual car is 50 times longer than the model car.

Explanation:

The relationship between the sizes of the model car and the actual car is represented by a ratio. To find this ratio, we can divide the length of the actual car by the length of the model car. So, 6 m / 0.12 m = 50. This means that the actual car is 50 times longer than the model car, or in other words, the model car is 1/50th the size of the actual car. Therefore, the correct ratio is 1:50.

Learn more about Ratios here:

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The best rebounders in basketball have a vertical leap (that is, the vertical movement of a fixed point on their body) of about 100 cm . a) What is their initial "launch" speed off the ground?b)How long are they in the air?

Answers

Answer:

a) 4.45 m/s

b) 0.9 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$v^2-u^2=2as\n\Rightarrow -u^2=2as-v^2\n\Rightarrow u=√(v^2-2as)\n\Rightarrow u=√(0^2-2* -9.81* 1)\n\Rightarrow u=4.45\ m/s$

a) The vertical speed when the player leaves the ground is 4.45 m/s

$v=u+at\n\Rightarrow t=(v-u)/(a)\n\Rightarrow t=(0-4.45)/(-9.81)\n\Rightarrow t=0.45\ s$

Time taken to reach the maximum height is 0.45 seconds

$s=ut+(1)/(2)at^2\n\Rightarrow 1=0t+(1)/(2)* 9.81* t^2\n\Rightarrow t=\sqrt{(1* 2)/(9.81)}\n\Rightarrow t=0.45\ s$

Time taken to reach the ground from the maximum height is 0.45 seconds

b) Time the player stayed in the air is 0.45+0.45 = 0.9 seconds

Two bullets of the same size, mass and horizontal velocity are fired at identical blocks, only one is made of steel and the other is made of rubber. The steel bullet has a perfectly inelastic collision with the block, while the rubber bullet has an elastic collision. Which bullet is more likely to knock over the block, or are both equally likely to do so? Justify your choice based on physics principles.

Answers

Answer and Explanation:

Since we're discussing shots, the significant thing is the way the energy is changed over as there is deceleration of the bullet to a halt when it hits something.

Kinetic Energy is relative to mass times speed squared, so in reality, the 2 cases given have practically indistinguishable Kinetic energy. The measure of energy is authoritative, so the two cases will do generally a similar harm given, obviously we look at situations when all the kinetic energy is spent.

One contrast that will be effectively obvious is that the weapon in the case of heavy bullet will recoil more.
One can consider energy assimilation as force times separation distance, and energy ingestion as a product of force and time.
Henceforth, the heavier yet more slow bullet with a similar energy will venture to every part of a similar separation in the engrossing material, but since of bigger force, will take a more drawn out time doing it.
It will along these lines, additionally, give a more noteworthy "kick" to the object that absorbs.

The switch in the circuit has been in the left position for a long time. At t=0 it moves to the right position and stays there.a. Write the expression for the capacitor voltage v(t), fort≥0. b. Write the expression for the current through the 2.4kΩ resistor, i(t), fort≥0+.

Answers

Answer:

Pls refer to attached file

Explanation:

Analysis of the relationship between the fuel economy (mpg) and engine size (liters) for 35 models of cars produces the regression model ModifyingAbove mpg with caret equals 36.44 minus 3.829 times Engine size. If a car has a 5 liter engine, what does this model suggest the gas mileage would be?

Answers

Answer:

Gas mileage is 17.29

Explanation:

Given data:

The total number of the model is 35

The total size of the engine is 5 ltr

The regression model is given as

$36.44 - 3.829* engine\ size$

From the information given in question we have

Regression equation is : model- mpg $= 36.44 - 3.829* engine\ size$

Therefore for engine capacity of 5 liters;

Gas mileage $= 36.44 - 3.829* 5 = 17.29$

Gas mileage is 17.29

Answer:16.

Explanation:

a mass of .4 kg is raised by a vertical distance of .450 m in the earth's gravitational field. what is the change in its gravitational potential energy

Answers

Answer:

E = 1.76 J

Explanation:

Given that,

Mass of an object, m = 0.4 kg

It moves by a vertical distance of 0.45 m in the Earth's gravitational field.

We need to find the change in its gravitational potential energy. It can be given by the formula as follow :

$E=mgh\n\nE=0.4* 9.8* 0.45\n\nE=1.76\ J$

So, the change in its gravitational potential energy is 1.76 J.

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