A football team gained 9 yards on the first play, lost 5 on the second play, lost 7 on the third play and gained 4 on the last play. What integer represents the total yards

Answers

Answer 1
Answer:

Answer:

1

Step-by-step explanation:

First play=9

Second play=5

Third pla=7

Fourth play=4

9-5-7+4

=1


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Prove: sin θ - sin θ•cos2 θ = sin3 θ. You must show all work.

Answers

sin²α+сos²α=1            sin²α=1-cos²α

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The expression b/c=b/c is an example of a(n)?

Answers

Answer:

(b)/(c) =(b)/(c)

bc=cb

It is an example of commutative property.

Step-by-step explanation:

The given expression

(b)/(c) =(b)/(c)

By cross multiplying we can write given expression as

b* c=c* b

Commutative property: commutative property states that order does not matter.

In addition , commutative property

  a+b=b+a

In multiplication , commutative property

a* b = b* a

We can write commutative property in multiplication

        ab=ba

Therefore, by using commutative property  then we get

         bc=cb

Hence, the given expression is an example of commutative property.

it is a example of commutative property is commutative property you change the order not the result

Lcm of 120,5200 and 40​

Answers

Ok because what does this even mean

Harry's rectangular side yard is 2 yards by 14 yards with an area of 28 square yards. Which dimensions have the same area

Answers

4 yards by 7 yards. 2 multiplied by 14 is 28, and 4 multiplied by 7 is also 28.

Isaiah determined that 5a^2 is the GCF of the polynomial a^3 - 25a^2b^5 - 35b^4. Is he correct? Explain

Answers

The answer is no, he did not arrive with the correct answer. With Isaiah claiming that 5a^2 is the GCF of the polynomial a^3 - 25a^2b^5 - 35b^4, he is incorrect because the constant '5' does not apply to the first factor of the equation which is 'a^3'. 

Answer:

No, Isiah is not correct. The GCF of the coefficients is 1, and there are no common variables among all three terms of the polynomial. 5b4 is a factor of -25a2b5 and -35b4, but not a3. Additionally, a2 is a factor of a3 and -25a2b5, but not -35b4.

Rewrite without rational exponents, and simplify, if possible.. (x^4y^4) ^1/3








Answers

\left(x^4y^4\right)^(1)/(3)=x^{4\cdot(1)/(3)}y^{4\cdot(1)/(3)}=x^(4)/(3)y^(4)/(3)=x^{1(1)/(3)}y^{1(1)/(3)}=x^{1+(1)/(3)}y^{1+(1)/(3)}=x^1x^(1)/(3)y^1y^(1)/(3)\n\n=x\sqrt[3]{x}\cdot y\sqrt[3]y=xy\sqrt[3]{xy}
That would become (XY)^4/3 . The exponent is still rational. Sorry.