MATHEMATICS HIGH SCHOOL

Domain of root(3-2x)+root(1-x)

Answers

Answer 1

Answer:

Answer:

x≤1

Step-by-step explanation:

sqrt( 3-2x) ≥ zero

3-2x ≥ zero

3 ≥ 2x

3/2 ≥ x

x ≤ 3/2

sqrt( 1-x) ≥ zero

1-x ≥ zero

1 ≥ x

x ≤ 1

We need the more restrictive domain since we are adding the two functions

x≤1

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A bowl contains 8 blue marbles and 5 green marbles. Elizabeth randomly draws 4 marbles form the bowl. she does not replace the marbles after each draw. what is the probability that she draws 1 blue marble and 3 green marbles?A. 4/13
B. 13/143
C. 4/143
D. 16/143

Answers

since she puts the marbles back, these events are dependent on each other
so
probability=(desired outcomes)/(total possilbe)
8+5=13=total
probailigy of blue=8/13
gree=5/13
so if she draws theem in that order then
8/13 times (since there is one less, -1 of 13) 5/12 times (assume 1 grreen was drawn from previus drawing) 4/11 times (assume as previus) 3/10

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the answer is C 4/143

Somebody answer this for me please

Answers

X // Y, Y // Z,

By inference X // Z

The third option.

5 hundreds + 4 tens= ____ tens

Answers

Oh ok!

How many tens are in 100? =10

so, 10 * 5 = 50

Now, 50 + 4 = 54!

Hope so now i get it correct!

What is the GCF of the numerator and denominator in the following fraction? - 99/176

Answers

The GCF is 11 because 99/11=9 and 176/11=16

what does gcf means as u only put abbrev

What is a situation in which you might locate points on a coordinate grid?

Answers

A situation could be when you have a y=axsquared+bx+c equation. You'd find the X, or vertex, by doing x=-b divided by 2•a. Then you'd plug in x and find y. Now you have a point you can plot. To find another, you can find the y-intercept by plughing in 0 for x and finding another y.

Derivative of R=(100+50/lnx)

Answers

Answer:

$\displaystyle R' = (-50)/(x(\ln x)^2)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle (d)/(dx)[f(x) + g(x)] = (d)/(dx)[f(x)] + (d)/(dx)[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle (d)/(dx) [(f(x))/(g(x)) ]=(g(x)f'(x)-g'(x)f(x))/(g^2(x))$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle R = 100 + (50)/(\ln x)$

Step 2: Differentiate

Derivative Property [Addition/Subtraction]: $\displaystyle R' = (d)/(dx)[100] + (d)/(dx) \bigg[ (50)/(\ln x) \bigg]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle R' = (d)/(dx)[100] + 50 (d)/(dx) \bigg[ (1)/(\ln x) \bigg]$
Basic Power Rule: $\displaystyle R' = 50 (d)/(dx) \bigg[ (1)/(\ln x) \bigg]$
Derivative Rule [Quotient Rule]: $\displaystyle R' = 50 \bigg(((1)' \ln x - (\ln x)')/((\ln x)^2) \bigg)$
Basic Power Rule: $\displaystyle R' = 50 \bigg( (-(\ln x)')/((\ln x)^2) \bigg)$
Logarithmic Differentiation: $\displaystyle R' = 50 \bigg( ((-1)/(x))/((\ln x)^2) \bigg)$
Simplify: $\displaystyle R' = (-50)/(x(\ln x)^2)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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