MATHEMATICS HIGH SCHOOL

Calculate the size of side x to 1 decimal
place. Show your working.
Calculate the size of side x to 1 decimal place. - 1

Answers

Answer 1
Answer:

Answer:

x=7.4 m and x=11.2 m

Step-by-step explanation:

To do these problems, we will need to use the Pythagorean Theorem.

Recall that it states a^2+b^2=c^2, where c is the longest side, the hypotenuse, of the triangle.

a) We have a triangle with side lengths 4.2 m and 6.1 m. These two sides correspond to a and b in this equation.

Now, we can plug these values into the equation and solve for c, which is x.

(4.2)^2+(6.1)^2=x^2\n\n17.64+37.21=x^2\n\nx=√(54.85)\n\nx=7.406\n\nx=7.4

b) We have a triangle with side lengths 5.1 m and 12.3 m. These sides correspond to a and c, so b will be x.

Now, we can plug these values into the equation and solve for x.

(5.1)^2+x^2=(12.3)^2\n\n26.01+x^2=151.29\n\nx=√(151.29-26.01)\n\nx=√(125.28)\n\nx=11.193\n\nx=11.2
Answer 2
Answer:

Answer:

Step-by-step explanation:

Formula: A squared + B squared = C squared

For the first question:

4.2 squared = 17.64

6.1 squared = 37.21

17.64+37.21 = 54.85

C squared = 54.85

The square root of 54.85 = 7.4

So, x = 7.4 m

For the second question:

5.1 squared = 26.01

12.3 squared = 151.29

26.01 + 151.29 = 177.3

C squared = 177.3

The square root of 177.3 = 13.3

So, x = 13.3 m

Hope this helps!

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Wright a trinomial that has 9 x squared as the GCF of its terms

Answers

9x^4+9x^3+9x^2 is a possible wnswer

Answer:

36x^4 + 27x^3 + 18x^2

or 81x^4 + 63x^3 + 27x^2

Step-by-step explanation:

Normal line to the curve y=ln(2x+a) at x=1 is perpendicular to x-4y+2 = 4ln3. Find the value of a.

Answers

Hello,

The normal perpendicular to x-4y+2=4ln(3) or y=(x+2-4ln(3))/4
has as slope -4

So y'=(ln(2x+a))'=1/(2x+a) *2 if x=1 , y'=1/(2+a)
Thus
1/(2+a)=-4 ==>2+a=-1/4==>a=-1/4-2==>a=-9/4

How to factor completely:  15x²-40x-15

Answers

15x^2-40x-15 =0\ \ /:5\n \n3x^2-8x-3 =0 \n \na=3, \ b=-8 , \ c= -3 \n \n\Delta =b^2-4ac =(-8)^2 -4\cdot 3\cdot (-3)=64+36=100 \n \nx_(1)=(-b-\Delta )/(2a)=(8-√(100))/(2 \cdot 3)=(8-10)/(6)=-(2)/(6)=-(1)/(3)

x_(2)=(-b+\Delta )/(2a)=(8+√(100))/(2 \cdot 3)=(8+10)/(6)= (18)/(6)=3\n \n 3x^2-8x-3 = 3(x+(1)/(3))(x-3)=(3x+1)(x-3) \n \n \nAnswer : \ 15x^2-40x-15 = 3x^2-8x-3 =(3x+1)(x-3)

According to the rules of significant figures, the number of digits that are estimated in a measurement is:a. one.
b. two.
c. three.
d. none.

Answers

According to the rules of significant figures in counting the number of significant figures when dealing with the measurement, especially when it is scientifically measured, you must consider 2 zeros at the right of the period. For example, in 98.00 there are 4 significant figures 

To solve the problem using these steps, what are thdimensions of the rectangle he should draw?
2 units by 4 units
3 units by 2 units
4 units by 4 units
5 units by 6 units

Answers

Answer:

It’s c 4 units by 4 units

Step-by-step explanation:

Final answer:

The dimensions of the rectangle should be 2 units by 4 units.

Explanation:

The correlation coefficient between x and y is 0.0491, which is very low. This means that there is no linear relationship between x and y. Therefore, it is not possible to use the linear regression model to fit the data.

The other models that you can try are the quadratic, logarithmic, exponential, and power models. To find the best-fitting model, you can calculate the R-squared value for each model. The R-squared value is a measure of how well the model fits the data. The closer the R-squared value is to 1, the better the model fits the data.

Based on the R-squared values, the quadratic model is the best-fitting model. The quadratic model is:

y = -477.38 + 237.66 ln x

The dimensions of the rectangle that the student should draw are 2 units by 4 units.

Graph the functions and approximate an x-value in which the exponential function surpasses the polynomial function. f(x) = 4x
g(x) = 4x2

The 2 in the 2nd equation is supposed to be an exponent btw

Answers

Answer:

Hi,

The answer is (-0.383,1) and (2,∞).

Step-by-step explanation:

See the attachment.

g(x) is a parabolic function, and the Image is always ≥ 0.

f(x) is a exponential function, and the Image is always ≥ 0.

At x = -0.383 , g(x) = 0.588 and f(x) = 0.588.

For x=(-0.383, 1), g(x) is greater than f(x).

At x = 1, g(x) = 1 and f(x) = 1.

For x=(1, 2), f(x) is greater than g(x).

At x= 2, g(x) = 16 and f(x) = 16

For x=(2,∞), g(x) is greater than f(x)
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