Hat is the kinetic energy of a 1.0-kg billiard ball that moves at 5.0 m/s? A.
5.0 J

B.
6.5 J

C.
10.0 J

D.
12.5 J

Answers

Answer 1

Answer: Kinetic energy is the energy that a body possesses by being in motion. It is calculated by the expression:

Kinetic Energy = 1/2 (mv²)
Kinetic Energy = 1/2 (1 kg) (5m/s)²
Kinetic Energy = 12.5 J

Therefore, the correct answer from the choices above is option D.

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5. Which of the following sets of conditions would result in the highest velocity for a sound wave traveling through air? A. A warm and humid day with a wind moving in the same direction as the sound B. A warm and dry day with a wind moving in the opposite direction as the sound C. A cold and dry day with a wind moving in the same direction as the sound D. A cold and humid day with no wind

How do charges move through an insulated wire connected across a battery? Use the terms potential difference, current, conductor, and insulator in answer.

Answers

The battery has both a positive side and a negative side. The potential difference will be the potential of the positive end of the battery minus the potential of the negative end, which will result in positive potential, or power. This potential is what gives the electrons the ability to flow from the positive end to the negative end, or to make a current. While the outside of the insulated wire is the insulator, the inside of the wire has copper, which is the conductor of the current. So, this current will go through the copper of the wire (and not the insulator) from the positive side to the negative.

Answer:

Battery is the source of electrical energy which will help the charge to flow through a medium.

Battery is a constant source of potential difference which will create constant potential difference across the ends of a conductor where it is connected.

When a charge is passed through the constant potential difference then the change in electrostatic potential energy will give kinetic energy to the charge.

It is given as

$q\Delta V = (1)/(2)mv^2$

so here charge will continuously flow through the conductor across which potential difference is applied by the battery. This constant motion or flow of charge is known as electric current.

Which equation would you need to rearrange to calculate the specific heat of an object

Answers

Heat = specific heat × mass × change in temperature
Specific heat = heat/ (mass×change in temperature)

If a force of 65 N is exerted on a 45 kg sofa and the sofa is moved 6.0 meters, how much work is done in moving the sofa? 17,550 J 171.990 J 390 J none of the above

Answers

Answer:

The answer to your question is: W = 390 J

Explanation:

Work is the transfer of energy when a body is moved from one place to another.

Data

Force = 65 N

mass = 45 kg

distance = 6 meters

work = ? J

Formula

W = F x d

Process

W = 65 N x 6 m

W = 390 J

Answer: 390 J

Explanation:

i got it right on my exam :D

suppose the mechanical advantage of a machine is 4 and the input force is 20 N. What is the output force?

Answers

Suppose the mechanical advantage of a machine is 4, and the input force is 20 N. What is the output force?

Answer is : 80 Newtons

Answer: The output force is 80 N.

Explanation :

It is given that,

Mechanical advantage of a machine is 4

Input force is 20 N

We know that the ratio of output force to the input force gives the mechanical advantage of a machine.

$m=(F')/(F)$

Where

F' is the output force

F is the input force

$F'=20\ N* 4$

F' = 80 N

So, magnitude of output force is 80 N.

A pendulum is swinging back and forth with a period of 2.0 seconds here on Earth. This pendulum is then brought to the Moon, where the acceleration due to gravity is much smaller. What will happen to the period of the pendulum, assuming everything else about it (mass, length, initial swing height, etc) remains exactly the same? Explain your answer.

Answers

Answer:

A greater period.

Explanation:

The period of a simple pendulum is given by the following formula:

$T = 2\pi \cdot \sqrt{(l)/(g) }$

Where:

$l$ - Length of the pendulum

$g$ - Gravity constant

Since acceleration due to gravity is smaller in the Moon, period will be greater.

A glass lens, n glass = 1.52 , has a 131 nm thick antireflective film coating one side, n film = 1.25. White light, moving through the air, is perpendicularly incident on the coated side of the lens. What is the largest wavelength of the reflected light that is totally removed by the coating?

Answers

Answer:

655 nm

Explanation:

When the intereference is destructive then the thickness, d of antireflective film coating one side is given by

2d=w/2n

Where w is wavelength and n is the reflective index of the film

Making w the subject of formula then

w=4nd

Substituting 1.25 for n and 131 nm for d then the wavelength will be

w=4*1.25*131=655 nm

Therefore, the wavelength is equivalent to 655 nm

The formula for calculating the wavelength in an antireflective film involves thickness (d) and refractive index (n). For n = 1.25 and d = 131 nm, the resulting wavelength is 655 nm.

When light waves encounter a thin film, some of the waves are reflected from the top surface of the film, and some pass through it. These waves can interfere with each other, leading to constructive or destructive interference. In the case of antireflective coatings, destructive interference is desired to minimize reflection.

The formula you mentioned is used to calculate the thickness (d) of an antireflective film that results in destructive interference for a specific wavelength (w) of light. The formula is:

2d = w / (2n)

Where:

d is the thickness of the film.

w is the wavelength of light.

n is the refractive index of the film.

To find the wavelength (w) when given the thickness (d) and refractive index (n), you can rearrange the formula:

w = 4 * n * d

Now, let's calculate the wavelength using the provided values:

n = 1.25 (refractive index)

d = 131 nm (thickness in nanometers)

Substitute these values into the formula:

w = 4 * 1.25 * 131 = 655 nm

Therefore, the calculated wavelength (w) is 655 nanometers (nm). This means that for a film with a refractive index of 1.25 and a thickness of 131 nm, destructive interference occurs at a wavelength of 655 nm.

For more such information on: wavelength

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