In the graph above, what's the distance between (0, 2) and (5, 2)?

Answers

Answer 1
Answer:

Answer:

The distance is 5

Step-by-step explanation:

Answer 2
Answer:

Answer:

where is the graph

Step-by-step explanation:


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F(x) =x + 3/2For the function f defined above, what is the value of f(-1)
F(2)=3x^2-6x+2I need help!!!

6(2x-5y)-2(x+9y) simplified

Answers

Answer:

10x-48y

Step-by-step explanation:

Bruce earns 14.45/h and works 40 hours a week. What is his gross annual income

Answers

Answer:

$30056

Step-by-step explanation:

First, you have to do $14.45 times 40 to get how much he makes in a week, and you get $578. Then do 578 x 52 as there are 52 weeks in a year. Then you would get the answer $30056 as his yearly income.

Answer:

$30,056.00

Step-by-step explanation:

Took the quiz

Please helpppp!!! it’s timed!!!! thank u for helping!!!!!

Answers

Answer:

ADMC

Step-by-step explanation:

The secant of a circle is a line that cuts the cuts two points of the circumference with one end point external to the circle;

Fro the given diagram, the two lines that cuts the circumference of the circle at two points are AEB and ADMC

Hence the one that contains diameter with point M is line ADMC

2Select the correct answer.
Which value is needed to determine a confidence interval for a sample mean?
OA
the margin of error for the proportion
ов.
the population size
OC.
the sample proportion
OD
the standard error of the mean

Answers

The value needed to determine a confidence interval for a sample mean is the standard error of the mean option (D) is correct.

What is a confidence interval for population standard deviation?

It is defined as the sampling distribution following an approximately normal distribution for known standard deviation.

The formula for finding the confidence interval for population standard deviation as follows:

\rm s\sqrt{(n-1)/(\chi^2_(\alpha/2, \ n-1))} < \sigma < s\sqrt{(n-1)/(\chi^2_(1-\alpha/2, \ n-1))}

Where s is the standard deviation.

n is the sample size.

\chi^2_(\alpha/2, \ n-1) and \chi^2_(1-\alpha/2, \ n-1) are the constant based on the Chi-Square distribution table:

α is the significance level.

σ is the confidence interval for population standard deviation.

Calculating the confidence interval for population standard deviation:

We know significance level = 1 - confidence level

 

It is given that:

The value needed to determine a confidence interval for a sample mean is the standard error of the mean.

CI = X + Z(s/√n)

Here CI is the confidence interval

Z is the confidence level

X is the sample mean

Thus, the value needed to determine a confidence interval for a sample mean is the standard error of the mean option (D) is correct.

Learn more about the confidence interval here:

brainly.com/question/6654139

#SPJ2

Answer:

D.thestandarderrorofthemean

Step-by-step explanation:

trust me i got it right Plato

How much pure alcohol must a pharmacist add to 10 cm of a 10% alcohol solution to strengthen it to a 70% solution? ASAP

Answers

20 cm³ of pure alcohol is added to 10 cm of a 10% alcohol solution to strengthen it to a 70% solution.

Let x represent the volume of pure alcohol (100%) in cm³ needed to be added. Hence:

x * 100% + 10 cm³ * 10% = 70% * (x + 10 cm³)

x * 1 + 10 * 0.1 = 0.7 * (x + 10)

x + 1 = 0.7x + 7

x - 0.7x = 7 - 1

0.3x = 6

x = 20 cm³

Therefore 20 cm³ of pure alcohol is added to 10 cm of a 10% alcohol solution to strengthen it to a 70% solution.

Find out more on equation at: brainly.com/question/13763238

Answer:

20 cm³

Step-by-step explanation:

The amount of cream sauce on the fettuccine at Al Fred-O's follows a Normal distribution, with a mean of 3.78 ounces and a standard deviation of 0.14 ounce. A random sample of 12 plates of fettuccine is selected every day and the sauce is measured. What is the probability that the mean weight will exceed 3.81 ounces

Answers

Answer:

22.66% probability that the mean weight will exceed 3.81 ounces

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = (\sigma)/(√(n))

In this problem, we have that:

\mu = 3.78, \sigma = 0.14, n = 12, s = (0.14)/(√(12)) = 0.04

What is the probability that the mean weight will exceed 3.81 ounces

This probability is 1 subtracted by the pvalue of Z when X = 3.81. So

Z = (X - \mu)/(\sigma)

By the Central Limit Theorem

Z = (X - \mu)/(s)

Z = (3.81 - 3.78)/(0.04)

Z = 0.75

Z = 0.75 has a pvalue of 0.7734

1 - 0.7734 = 0.2266

22.66% probability that the mean weight will exceed 3.81 ounces

Answer:

Correct answer is 0.2290

Step-by-step explanation: