10 POINTS : What are 4 things created from Big Bang?

Answers

Answer 1
Answer:

Answer:

:0

Explanation:

One second after the Big Bang, the universe was filled with neutrons, protons, electrons, anti-electrons, photons and neutrinos.Jun 17, 2017


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The [Fe(H₂O)₆]³⁺ complex requires a relatively small amount of energy to promote an electron from the t2g to the eg. Based on the UV data, predict the spin of this complex.
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If 4.0 mol aluminum and 7.0 mol hydrogen bromide react according to the following equation, how many moles of hydrogen are formed and what is the limiting reactant?

Which letter indicates the asthenosphere

Answers

Answer:

q

Explanation:

Most wine is prepared by the fermentation of the glucose in grape juice by yeast: C6H12O6(aq) --> 2C2H5OH(aq) + 2CO2(g) How many grams of glucose should there be in grape juice to produce 725 mLs of wine that is 11.0% ethyl alcohol, C2H5OH (d=0.789 g/cm3), by volume?

Answers

Answer:

123.41 g

Explanation:

Given that the ethyl alcohol produced is 11.0 % by volume.

It means that 1000 mL contains 110 mL of ethyl alcohol

Given that the volume is:- 725 mL

So,

Volume of ethyl alcohol = (110)/(1000)* 725\ mL = 79.75 mL

Given that:- Density = 0.789 g/cm³ = 0.789 g/mL

So, Mass = Density*Volume = 0.789* 79.75\ g = 62.92 g

Calculation of the moles of ethyl alcohol as:-

Molar mass of ethyl alcohol = 46.07 g/mol

The formula for the calculation of moles is shown below:

moles = (Mass\ taken)/(Molar\ mass)

Thus,

Moles= (62.92\ g)/(46.07\ g/mol)

Moles=1.37\ mol

According to the reaction:-

C_6H_(12)O_6_((aq))\rightarrow 2C_2H_5OH_((aq)) +2CO_2_((g))

2 moles of ethyl alcohol is produced when 1 mole of glucose reacts

Also,

1.37 moles of ethyl alcohol is produced when (1)/(2)* 1.37 mole of glucose reacts

Moles of glucose = 0.685 Moles

Molar mass of glucose = 180.156 g/mol

Mass = Moles*Molar mass = 0.685* 180.156\ g = 123.41 g

Ascorbic acid (vitaminc.Does not contain a traditional carboxylic acid group, but it is, nevertheless, still fairly acidic (pka = 4.2). Identify the acidic proton and explain your choice using resonance structures, if necessary:

Answers

Let us see the structure of ascorbic acid


As shown there is no COOH group however the OH group can lose a proton and forms conjugate base

The conjugate base formed is stabilized due to resonance

More the stability of conjugate base more the strength of acid

Hence ascorbic acid behaves as an acid

The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentration of 0.086 M, calculate the concentration of NOBr after 22 s. (b) Calculate the half-lives when [NOBr]0 5 0.072 M and [NOBr]0 5 0.054 M.

Answers

Explanation:

2NOBr(g) --> 2NO(g) 1 Br2(g)

Rate constant, k = 0.80

a) Initial concentration, Ao = 0.086 M

Final Concentration, A = ?

time = 22s

These parameters are connected with the equation given below;

1 / [A] = kt + 1 / [A]o

1 / [A] = 1 / 0.086 + (0.8 * 22)

1 / [A] = 11.628 + 17.6

1 / [A] = 29.228

[A] = 0.0342M

b) t1/2 = 1 / ([A]o * k)

when [NOBr]0 5 0.072 M

t1/2 = 1 / (0.072 * 0.80)

t1/2 = 1 / 0.0576 = 17.36 s

when [NOBr]0 5 0.054 M

t1/2 = 1 / (0.054 * 0.80)

t1/2 = 1 / 0.0432 = 23.15 s

Answer:

(a)

0.0342M

(b)

t_(1/2)=17.36s\nt_(1/2)=23.15s

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

(1)/([NOBr])=kt +(1)/([NOBr]_0)\n(1)/([NOBr])=(0.8)/(M*s)*22s+(1)/(0.086M)=(29.3)/(M)\n

[NOBr]=(1)/(29.2/M)=0.0342M

(b) Now, for a second-order reaction, the half-life is computed as shown below:

t_(1/2)=(1)/(k[NOBr]_0)

Therefore, for the given initial concentrations one obtains:

t_(1/2)=(1)/((0.80)/(M*s)*0.072M)=17.36s\nt_(1/2)=(1)/((0.80)/(M*s)*0.054M)=23.15s

Best regards.

5. As a sample of matter is heated, its particles *O A are unaffected
O B. move more quickly
O C. move more slowly
D. stop moving

Answers

Answer:

B. move more quickly

Explanation:

As a sample of matter is heated, we know that the particles begins to move more quickly.

This is because the temperature of a substance is directly proportional to the average kinetic energy of a system.

  • As the temperature increases, the body gains more kinetic energy
  • This is translated to the particles of the medium.
  • Then they begin to move quickly and very fast enough.

Final answer:

Upon heating a sample of matter, the particles tend to move more quickly. This is because the increase in temperature boosts the kinetic energy of the particles, thereby making them move faster.

Explanation:

When a sample of matter is heated, it causes the particles of the matter to move more quickly. This phenomenon is due to the increase in temperature, which leads to an increase in the kinetic energy of the particles. Kinetic energy refers to the energy that an object possesses due to its motion. Hence, as heat supplies energy, it causes atoms and molecules in a matter to move faster. As a result, solids expand and liquids and gases become less dense as their particles spread out to absorb the heat.

Learn more about Kinetic Energy here:

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What is the atomic number of an element containing 12 neutrons and having a mass number of 24

Answers

The element is magnesium, its atomic number is 12.