Why are chemical processes unable to produce the same amount of energy flowing out of the sun as nuclear fusion?

Answers

Answer 1

Answer:

Answer:

Explanation:

One of the major differences between nuclear reactions and chemical reactions is that nuclear reactions involve larger amount of energy than chemical energy. This is because the force between the protons and neutrons in the nucleus of an atom is much higher than the force of attraction between electrons and the positively charged nucleus, hence nuclear reactions involves/requires a larger amount of energy (because it's reactions involve the nucleus) than chemical reactions (because it's reactions involve the electrons).

Thus, during nuclear fusion, two light nuclei are bombarded against one another to produce a larger/heavier nuclei with the release of large amount of energy (because the forces between the protons and neutrons are much higher) unlike when two atoms/molecules are chemically combined together to form a new molecule with the rearrangement of electrons in the valence shells of the participating molecules.

Related Questions

1. A bicyclist starts at 2.5 m/s and accelerates along a straight path to a speed of 12.5 m/s ina time of 4.5 seconds. What is the bicyclist's acceleration to the nearest tenth of a m/s??
The left ventricle of a resting adult's heart pumps blood at a flow rate of 85.0 cm3/s, increasing its pressure by 110 mm Hg, its velocity from zero to 25.0 cm/s, and its height by 5.00 cm. (All numbers are averaged over the entire heartbeat.) Calculate the total power output (in W) of the left ventricle. Note that most of the power is used to increase blood pressure.
Which law does the following statement express? "In all cases of electromagnetic induction, the induced voltages have adirection such that the currents they produce oppose the effect that produces them."
On a day when the water is flowing relatively gently, water in the Niagara River is moving horizontally at 4.5 m/sm/s before shooting over Niagara Falls. After moving over the edge, the water drops 53 mm to the water below.a. If we ignore air resistance, how much time does it take for the water to go from the top of the falls to the bottom? b. Express your answer to two significant figures and include the appropriate units. c. How far does the water move horizontally during this time? d. Express your answer to two significant figures and include the appropriate units.
Suppose that we are designing a cardiac pacemaker circuit. The circuit is required to deliver pulses of 1ms duration to the heart, which can be modeled as a 500 ohm resistance. The peak amplitude of the pulses is required to be 5 V. However, the battery delivers only 2.5 V. Therefore, we decide to charge two equal value capacitors in parallel from the 2.5V battery and then switch the capacitors in series with the heart during the 1ms pulse. What is the minimum value of the capacitances required so the output pulse amplitude remains between 4.9 V and 5.0 V throughout its 1ms duration

Guitar string has an overall length of 1.22 m and a total mass of 3.5 g before being strung on a guitar. Once it is used on the guitar, there is a distance of 70 cm between fixed end points. The guitar string is tightened to a tension of 255 N.What is the frequency of the fundamental wave on the guitar string?

Answers

Answer:

Fundamental frequency= 174.5 hz

Explanation:

We know

fundamental frequency= $(velocity)/(2 *length)$

velocity = $\sqrt{(tension)/(mass per unit length) }$

mass per unit length= $(3.5)/(1000*1.22)$ =0.00427 $(kg)/(m)$

Now calculating velocity v= $\sqrt{(255)/(0.00427) }$

=244.3 $(m)/(sec)$

Distance between two nodes is 0.7 m.

Plugging these values into to calculate frequency

f = $(244.3)/(2 *0.7)$ =174.5 hz

A car is decelerating at the rate of 2 km/s square. If its initial speed is 66 km/s, how long will it take the car to come to a complete stop?

Answers

Answer:

It will take 33 seconds to stop the car.

Explanation:

Using the first equation of kinematics we have

$v=u+at$

where

'v' is final speed of object

'u' is initial speed of object

'a' is acceleration of object

't' is time of acceleration of object

Now since it is given that $a=-2km/s^(2)$ since acceleration is negative and $u=66km/s$

We know that the object will stop when it's velocity reduces to zero hence in the equation above setting v = 0 we get

$0=66-2* t\n\n\therefore t=(66)/(2)=33seconds$

What power lens is needed to correct for farsightednesswherethe uncorrrected near point is 75 cm?

Answers

To solve this problem we will apply the concept related to the lens power with which farsightedness can be corrected. Mathematically this value is given by the relationship,

$P = (1)/(f)$

Here,

f =focal length

In turn, said expression can be exposed in terms of the distance of the object and the image as:

$P = (1)/(p)+(1)/(q)$

Here,

p = Object Distance ( By convention is 25cm)

q = Image distance

Replacing we have,

$P = (1)/(0.25)+(1)/(-0.75)$

$P = +2.67D$

Therefore the power lens that is needed to correct for farsightedness is +2.67D

Which of the following are electromagnetic waves?a. Water wavesb. Radio wavesc. Sound wavesd. Seismic waves

Answers

Answer:

Radio waves

Explanation:

Radio wavs are electromagnetic waves.

Hope this helped!

The answer is Radio Waves because it is electromagnetic

Part 1) A cop car traveling at 25 m/s has a siren producing a frequency of 700 Hz. A felon jumps on his motorcycle and speed off in the opposite direction of 15 m/s. What frequency does the felon hear as he sped away (speed of sound is 343 m/s)?Part 2) The cop does a U-turn and speeds towards the felon at 30 m/s, while the felon speeds up to 20 m/s. What frequency does the felon hear as he sped away (speed of sound is 343 m/s)?
Part 3) What if the felon then sped up to 30 m/s and all other conditions remained the same?

Answers

1) 621.8 Hz

2) 719.3 Hz

3) 700 Hz

Explanation:

The Doppler effect occurs when there is a source of a wave in relative motion with respect to an observer.

When this happens, the frequency of the wave appears shifted to the observer, according to the equation:

$f'=(v\pm v_o)/(v \pm v_s)f$

where

f is the real frequency of the sound

f' is the apparent frequency of the sound

v is the speed of the sound wave

$v_o$ is the velocity of the observer, which is negative if the observer is moving away from the source, positive if the observer is moving towards the source

$v_s$ is the velocity of the source, which is negative if the source is moving towards the observer, positive if the source is moving away

In this problem we have:

f = 700 Hz is the frequency of the siren

v = 343 m/s is the speed of sound

$v_s=-25 m/s$ is the velocity of the car with the siren

$v_o = +15 m/s$ is the velocity of the felon (he's moving away from the siren)

So, the frequency heard by the felon is

$f=(343-25)/(343+15)(700)=621.8 Hz$

In this case, the cop does a U-turn and speeds towards the felon at 30 m/s.

This means that now the siren is moving towards the observer (so, $v_s$ becomes positive), while the sign of $v_o$ still remains positive.

So we have:

f = 700 Hz is the frequency of the siren

v = 343 m/s is the speed of sound

$v_s=+30 m/s$ is the velocity of the car with the siren

$v_o = +20 m/s$ is the velocity of the felon

So, the frequency heard by the felon is

$f=(343+30)/(343+20)(700)=719.3 Hz$

In this case, the felon speeds up to 30 m/s.

This means that now the felon and the siren are moving with the same relative velocity: so, it's like they are not moving relative to each other, so the frequency will not change.

In fact we have:

f = 700 Hz is the frequency of the siren

v = 343 m/s is the speed of sound

$v_s=+30 m/s$ is the velocity of the car with the siren

$v_o = +30 m/s$ is the velocity of the felon

So, the frequency heard by the felon is

$f=(343+30)/(343+30)(700)=700 Hz$

So, the frequency will not change.

A rock is thrown vertically upward from some height above the ground. It rises to some maximum height and falls back to the ground. What one of the following statements is true if air resistance is neglected? The acceleration of the rock is zero when it is at the highest point. The speed of the rock is negative while it falls toward the ground. As the rock rises, its acceleration vector points upward. At the highest point the velocity is zero, the acceleration is directed downward. The velocity and acceleration of the rock always point in the same direction.

Answers

Answer:

At the highest point the velocity is zero, the acceleration is directed downward.

Explanation:

This is a free-fall problem, in the case of something being thrown or dropped, the acceleration is equal to -gravity, so -9.80m/s^2. So, the acceleration is never 0 here.

I attached an image from my lecture today, I find it to be helpful. You can see that because of gravity the acceleration is pulled downwards.

At the highest point the velocity is 0, but it's changing direction and that's why there's still an acceleration there.

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A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 58.9 cm ( 0.589 m) and the flow speed of the petroleum is 12.1 m/s. At the refinery, the petroleum flows at 6.29 m/s. What is the volume flow rate of the petroleum along the pipe and what is the pipe's diameter at the refinery?

A 8.00-μF capacitor that is initially uncharged is connected in series with a 3.00-Ω resistor and an emf source with E = 70.0 V and negligible internal resistance. At the instant when the resistor is dissipating electrical energy at a rate of 300 W, how much energy has been stored in the capacitor?

A 0.320 kg ball approaches a bat horizontally with a speed of 14.0 m/s and after getting hit by the bat, the ball moves in the opposite direction with a speed of 22 m/s. If the ball is in contact with the bat for 0.0600 s, determine the magnitude of the average force exerted on the bat.