Gravitational pull must be measured in units of

Answers

Answer 1
Answer: Gravitational force must be measured in units of : meters per second squaredIn every Physics equation, usually the amount of Gravitational force is standardized and will be exactly the same as long as the event happens on the earth, which is 9.8 m/s^2.
Answer 2
Answer:

The direction of the pull is -70.93°, or approximately 71° South of West.

Given the vector as F= (−2980.0i^ + 8200.0j^)N

The magnitude of the pull is given by the formula below:

Magnitude of pull,  |F| = √(F_x^2 + F_y^2)

Here, F_x is the force in the x-direction and F_y is the force in the y-direction. We know that:

F_x = -2980.0 N and F_y = 8200.0 N

Therefore, the magnitude of the pull is:

|F| = √(F_x^2 + F_y^2)|F| = √((-2980.0)^2 + (8200.0)^2)|F| = √(88840000) |F| = 9425.89 N

The direction of the pull can be found as follows:

θ = tan⁻¹(F_y/F_x)θ = tan⁻¹(8200.0/-2980.0)θ = -70.93°

The direction of the pull is -70.93°, or approximately 71° South of West.

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on a high way a car is driven 80 km the first 1 he of travel, 50km during the next 0.5 he, and 40 km in the final 0.5 hr. What is the cars average speed for the entire trip?

Answers


Average speed = (total distance covered) / (total time to cover the distance) .

Total distance = (80 + 50 + 40) = 170 km

Total time = (1 + 0.5 + 0.5) = 2 hours

Average speed = (170 km) / (2 hrs)= 85 km/hr .
 

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It was a man named Johannes Kepler. 

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Which phenomenon is a result of the gravitational force of the Sun?O rotation of the planets on their axes
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Answers

Answer:

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What is speed of a particle?

Answers

The speed of a particle is the instantaneous rate at which its distance of travel
is changing.

Over any finite period of time, its speed is:

               (distance traveled) / (time to travel the distance).

The direction of travel is irrelevant to a description of speed.
SPEED = total DIST. traveled / total time taken

If anyone knows how to do any of these PLEASE help me....im am so confused rn and our teacher sucks at explaining this stuff......

Answers

take 68.2/60 = 1.137 hr
take 56.9/1.137 = 50.043 mi/hr

take 189/211 = 0.896

24.8/2 = 12.4 m
12.4/82.3 = 0.15s

Well, five answers for only five points is pretty slim.  But I've already got
a lot of points, and your plea for help sounds so desperate, that I think
I ought to jump in here and relieve some of your pain.

These aren't difficult problems.  The bummer is that whoever wrote them
got so interested in his dinosaur stories that he kind of hid the actual Math
and Physics under all kinds of stuff that doesn't matter.

1).     Speed  =  (distance covered) / (time to cover the distance)

                       =    (56.9 miles)  /  (68.2 minutes)

                       =      (56.9 / 68.2)  miles/minute

                       =          0.834  mile per minute.

BUT ... the question wants to know the speed in 'mph' ... miles per hour.

Well ... there are 60 minutes in an hour.  If 0.834 mile in covered in 1 minute,
then 60 times as much would be covered in 1 hour.

                    (0.834 mile/minute)  x  (60 minute/hour)  =  50.06 mile/hour

                     
            Rounded to no decimal places  =  50 mph


2).  Use the same formula:

         Speed  =  (distance covered) / (time to cover the distance)

                       =    (189 meters)  /  (211 seconds)

                       =      (189 / 211)  meters/seconds

                       =          0.8957 meters/second

     Round to 3 decimal places:      0.896  m/s


3).  The attacker jumped from 24.8 meters away.
       He already covered half of the distance.
       How far away is he now ?      1/2 of 24.8 m  =  12.4 m .
       He still has 12.4 meters left to go.

       He's moving at 82.3 meters per second.
       When will he arrive here ?

       Time  =  (distance)  /  (speed)

                  =      (12.4 meters)  /  (82.3 m/s)

                  =          (12.4 / 82.3)  seconds

                  =              0.1506 second

       Two decimal places:    0.15 second


4).    Distance  =  (speed) x (time)

                          =  ( 237 km/hr)  x (16.8 seconds) .

Do you see the problem here ?  We have the distance covered in an hour,
but we need to know how much distance is covered in only 16.8 seconds.
We really need to work out the speed in (meters per second).

OK.  237 km = 237,000 meters, so the speed is  237,000 meters/hour.

1 hour is 3,600 seconds. 
So the speed is only one 3600th of 237,000 meters in 1 second.

           (237,000 meters/hour) x (1 hour / 3600 seconds)  =  65.8333 m/s

           Distance  =  (speed)  x  (time)

                            =  (65.8333 meter/second)  x  (16.8 seconds)

                            =   (65.8333 x 16.8)  meters

                            =      1106 meters.     


5).  This is a nasty trick question.  The whole story is irrelevant,
and we don't even care how far Vinny dropped.

Anything that drops on Earth falls with the acceleration of gravity.
It doesn't matter how big or heavy or small or light it is.
Everything falls with the acceleration of gravity on Earth ...  about   9.8 m/s²  .