MATHEMATICS COLLEGE

One real world example of when we use rates and unit rates is _________.

Answers

Answer 1

Answer:

In Sporting Events

Step-by-step explanation:

When comparing quantities you simplify which is your change fr the money you gave or your Tip you gave.

Answer 2

Answer:

Answer:

Economics!

Step-by-step explanation:

I'll keep it brief, I'm in a class.

Say you're gain a certain amount of money, and losing some as well.

Find the difference, you got your rate, so you just graph it!

Stay Safe!

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g Determine the critical values for these tests of a population standard deviation. (a) A right-tailed test with 16 degrees of freedom at the alphaequals0.01 level of significance (b) A left-tailed test for a sample of size nequals23 at the alphaequals0.1 level of significance (c) A two-tailed test for a sample of size nequals31 at the alphaequals0.1 level of significance

Answers

Answer:

Step-by-step explanation:

We are to find critical values for the test given

a) df =16: Alpha = 0.01 and right tailed

Critical value= 2.583

b) df = 23-1 = 22: alpha = 0.1 and left tailed

critical= -1.717

c)df=31-1 =30: alpha =0.1: two tailed

t =1.697

Critical values can be obtained from critical t tables.

Left tailed will have negative sign and right tailed positive

Final answer:

The critical values for these tests of a population standard deviation can be found via looking up a chi-square distribution table at the specified degrees of freedom and alpha level. For a two-tail test, the alpha value needs to be divided equally in the two tails.

Explanation:

To determine the critical values for these tests of a population standard deviation, we first need to understand the critical values for a chi-squared test. The chi-square test is used when the degrees of freedom and the level of significance (alpha) are known.

(a) A right-tailed test with 16 degrees of freedom at the alpha equals 0.01 level of significance: To find this critical value, we would check a chi-square distribution table at 16 degrees of freedom and alpha equals 0.01. The value we find is the critical value.

(b) A left-tailed test for a sample of size n equals 23 at the alpha equals 0.1 level of significance: Similarly, we would check the chi-square distribution table but this time at 22 degrees of freedom and alpha equals 0.1. Please note that degrees of freedom is calculated as n-1 which gives us 22 in this case.

(c) A two-tailed test for a sample of size n equals 31 at the alpha equals 0.1 level of significance: For a two-tailed test, we distribute the alpha equally in the two tails of the distribution. That means, we lookup chi-square distribution table for 30 degrees of freedom and alpha equals 0.05 to get our critical value.

Learn more about Population Standard Deviation here:

brainly.com/question/29320183

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Please help me for a TEST review tomorrow!!

Answers

Answer:

Hope you understand my writing!

Anyone know this? that box is just when I get the answr

Answers

$\huge\textsf{Hey there!}$

$\mathsf{(1)/(5)*(1)/(2)}$

$= \mathsf{(1*1)/(5*2)}$

$\mathsf{1 * 1 = \boxed{\bold{1}} \leftarrow NUMERATOR\ (TOP\ number)}$

$\mathsf{5*2 = \boxed{\bold{10}} \leftarrow DENOMINATOR\ (BOTTOM \ number) }$

$\mathsf{= (1)/(10)}$

$\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf (1)/(10)}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

Answer:

1/10

Step-by-step explanation:

1/5 x 1/2

1/10

Bye , hope this helps!

Give brainliest !

The probability of finding a broken cookie in a bag of chocolate chip cookies is P = .03. Find the probability of getting at least 2 broken cookies in a bag containing 36 cookies

Answers

P(at least 2 broken cookies) = 1 - P(X = 0) - P(X = 1)

How to find the probability of getting at least 2 broken cookies in a bag containing 36 cookies

To find the probability of getting at least 2 broken cookies in a bag containing 36 cookies, we need to calculate the probability of getting 2, 3, 4, ..., up to 36 broken cookies and then sum up those probabilities.

The probability of getting exactly 2 broken cookies can be calculated using the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

Using the formula, we can calculate P(X = 2):

P(X = 2) = C(36, 2) * (0.03)^2 * (1 - 0.03)^(36 - 2)

Similarly, we can calculate P(X = 3), P(X = 4), and so on, up to P(X = 36).

Once we have calculated all these probabilities, we can sum them up to find the probability of getting at least 2 broken cookies:

P(at least 2 broken cookies) = P(X = 2) + P(X = 3) + P(X = 4) + ... + P(X = 36)

P(at least 2 broken cookies) = 1 - P(X = 0) - P(X = 1)

To calculate P(X = 0), we can use the binomial probability formula with k = 0, and for P(X = 1), we can use the formula with k = 1.

Once we have calculated P(X = 0) and P(X = 1), we can substitute them into the equation:

P(at least 2 broken cookies) = 1 - P(X = 0) - P(X = 1)

This will give us the probability of getting at least 2 broken cookies in a bag containing 36 cookies.

Learn more about probability at brainly.com/question/13604758

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the answer would be .06 bc its 2 broken cookies in a bag therefore it would be double so the answer is .06

Help APSPPP!!!!!!!!!!!!

Answers

Answer:

ok what u need help with

Step-by-step explanation:

One thousand tonnes (1000 t, one t equals 10 cubed kg) of sand contains about a trillion (10 super 12) grains of sand. How many tonnes of sand are needed to provide 1 mol of grains of sand? (b) Assuming the volume of a grain of sand is 1.0 mm3 and the land area of the continental United States is 3.6 multiplication 10 super six square miles, how deep would the sand pile over the United States be if this area were evenly covered with 1.0 mol of grains of sand?

Answers

Answer with Step-by-step explanation:

Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)

Thus we have

1 mole of sand = $6.022* 10^(23)$ sand particles

Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is

$(6.022* 10^(23))/(10^(12))=6.022* 10^(11)$

Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of $6.022* 10^(11)$ trillion sand particles is

$Mass=1000* 6.022* 10^(11)=6.022* 10^(14)tonnes$

Part 2)

Since it is given that volume of 1 sand particle is $1.0mm^(3)$ thus the volume of 1 mole of sand is volume of $6.022* 10^(23)$ sand particles

Thus volume of 1 mole is $V=1.00* 10^(-18)km^(3)* 6.022* 10^(23)=6.022* 10^(5)km^(3)$

Now since the Area of united states is $A=3.6* 10^(6)mile^(2)=5.8* 10^(6)km^(2)$

Thus the depth of the sand pile is

$Depth=(Volume)/(Area)=(6.022* 10^5)/(5.8* 10^6)=0.10387km=103.8meters$

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