Model the sum 0.5 + (-2.5)

Answers

Answer 1
Answer: -2 because adding a positive to a negative is really just taking the negative from the positive number

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A triangle has two sides of length 6 and 9. What could the length of the third side be? Check all that apply, A. 10
B. 7
C.4
D.2
E.15
F.12

Answers

a,b,c-lengths\ sides\ of\ a\ triangle,\ then:\n\na+b > c\na+c > b\nb+c > c\n\nif\ a\leq b\leq c\ then\ a+b > c\n------------------------\na=6;\ b=9\to a+b=6+9=15\ then\ c=10\ or\ c=12\n\na=6;\ c=9\to b=4\ because\ a+b=6+4=10 > 9\na=6;\ c=9\to b=7\ because\ a+b=6+7=15 > 9\n\nAnswer:A.10;\ B.7;\ C.4;\ F.12

Solve this problem using estimation.Melissa bought 18 cupcakes and 2 gallons of fruit punch for her Valentine party. If the cupcakes cost $.33 each and the punch costs $2.78 a gallon, estimate the cost of the cupcakes.

Answers

If she bought 18 cupcakes at $0.33 each, and 2 gallons of punch at $2.78 each, then Melissa have spent $11.50 overall for the cupcakes.

What percent of 61 is 152.5?

Answers

Steps:
1. Do a proportion
152.5/61 times x/100
2. Do 152.5 times 100 which equals 15,250
3. Divide 15,250 by 61 which equals 250
4. Your answer is 250%

The number 152.5 is 250 percent of 61.

To find the chance, we can use the following formula

(Percentage / 100) Whole = Part

In this case, we want to find the chance, which is the unknown value. Let's denote it as "x."

(x/ 100) 61 = 152.5

To break for x, we can rearrange the equation

x = (152.5/ 61) 100

x ≈ 250

Thus, 152.5 is roughly 250 of 61.

Learn more about Percentage here:

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Which best describes the area of a polygon

Answers

Answer:

The number of square units contained in the interior

Step-by-step explanation:

apex

well when answering this you have to realize that the area of a polygon is the number of square units in that polygon. it really does depend on what type of polygon you are talking about. Anything in specific?

Find the value of x.
A.48
B.56
C.68
D.76

Answers

Answer:

A

Step-by-step explanation:

The secant- tangent angle 78° is half the difference of the intercepted arcs

(1)/(2) (204 - x) = 78 ( multiply both sides by 2 )

204 - x = 156 ( subtract 204 from both sides )

- x = - 48 ( multiply both sides by - 1 )

x = 48

Answer:

A.) 48

Step-by-step explanation:

I got it correct on founders edtell

Abigail was skateboarding home when the wheel axle of her skateboard broke. She had already traveled two thirds of the way home and had to walk the rest of the way. Walking the rest of the way home took her twice as long as it took her to ride her skateboard. How many times faster is Abigail on her skateboard than she is walking?

Answers

Answer:

The number of times faster Abigail is on her skateboard than she is walking is 4 times

Step-by-step explanation:

The information given are;

Abigail was skateboarding home (let the distance home = D)

The distance Abigail had traveled when her skateboard broke = 2/3 of D

The distance of the rest (remaining) of the way home = 1 - 2/3 of D = 1/3 of D

The time Abigail took in walking the rest of the way home = 2 × t, Time it will take on the skateboard

Given that t is the time it takes Abigail to arrive home on skateboard alone, we have;

Speed = (Distnce)/(Time)

Speed on skate board, S_t = Distance/Time = D/t

Therefore, the time it took Abigail to travel two thirds (2/3) of D is given as follows;

Time= (Distnce \ covered)/(Speed ) = ((2)/(3) D)/(S_t)  =  ((2)/(3) D)/((D)/(t) )  = (2)/(3) D * (t)/(D)  =  (2)/(3) t

The total time it took Abigail to get to her home = Time of walking + Time on skateboard

The question also states that he total time it took Abigail to get to her home by walking and skateboarding because her skateboard broke = 2×t

Therefore, the total time it took Abigail to get to her home = 2×t = Time of walking + Time on skateboard = Time of walking + (2)/(3) t

Which gives;

2×t = Time of walking + (2)/(3) t

Time of walking = 2 * t -(2)/(3) t = (4)/(3) t

∴ The time Abigail walked 1/3·D = (4)/(3) t

Abigail walking speed is then

Walking \ speed= (Distnce \ covered \ walking)/(Time \walking) = ((1)/(3) D)/((4)/(3) t)  = ((D)/(3) )/((4 \cdot t)/(3) ) = (D)/(3) } * {(3)/(4 \cdot t) } = (D)/(4 \cdot t) }

To compare how many times faster is Abigail on her skateboard than she is walking, we divide the expression (formula) for the speed of skateboarding with the (formula) for the speed of walking as follows;

The \ number \ of \ times \ faster = ((D)/(t) )/((D)/(4 \cdot t) )} = (D)/(t)  * (4 \cdot t)/(D) } = 4

The number of times faster is 4 that is Abigail is four times faster on her skateboard than she is walking.