Robert's father is 4 years older than 3 times Robert's age. His father is 40 years old. Write the equation used to determine Robert's age.

Answers

Answer 1

Answer:

Robert is 12 years old. The equation 40 = 3R + 4 was used to determine Robert's age based on the given information about his father's age being 40 and the age relationship between them.

We can set up an equation to represent the given information. Let's denote Robert's age as "R" and his father's age as "F." According to the information provided, we have:

F = 3R + 4

Given that Robert's father is 40 years old (F = 40), we can substitute this value into the equation:

40 = 3R + 4

Now, solve for Robert's age (R):

3R = 40 - 4

3R = 36

R = 36 / 3

R = 12

Therefore, Robert is 12 years old. The equation 40 = 3R + 4 was used to determine Robert's age based on the given information about his father's age being 40 and the age relationship between them.

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Answer 2

Answer:

Answer:

robert is 12 years old

Step-by-step explanation:

robert's age=x

40=3x+4

that's the equation

40=3x+4

=36=3x

x=12

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If a regular polygon has one exterior angle measuring 1°, then it has_______ sides.

Answers

The measure of the exterior angle of a regular polygon is given by the formula $(360)/(n)$ where $n$ is the number of sides.
To find the number of sides of a polygon with the exterior angle measuring $1^(\circ)$ we have to solve the equation $(360)/(n)=1$ .

$(360)/(n)=1|\cdot n\nn=360$

It has 360 sides.

Need help with this problem

Answers

Answer:

39°

Step-by-step explanation:

Internal angles of the triangle are:

x, 60° and (180° -99°)

Angle x is:

x = 180° - (60° + 81°)
x = 180° - 141°
x = 39°

\dfrac{1}{3}(4\cdot3)+2^3=
3
1

(4⋅3)+2
3

Answers

I got 14 on Photomath

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Answers

Answer:

(-6,9,-3)

Step-by-step explanation:

-3x -y +z=6

-3x-y+3z =0

x-3z =3

Multiply the second equation by -1

-1 *(-3x-y+3z) =0*-1

3x +y -3z =0

Add this to the first equation

-3x -y +z=6

3x +y -3z =0

----------------------

0 + 0 + -2z = 6

Divide by -2

-2z/-2 = 6/-2

z = 6/-2

z=-3

Take the third equation to find x

x-3z=3

x-3(-3) = 3

x+9=3

Subtract 9 from each side

x+9-9 =3-9

x=-6

Now we need to find y

3x +y -3z =0

3(-6) +y -3(-3) =0

-18 +y +9=0

-9+y =0

Add 9 to each side

-9+9+y = 0+9

y=9

(-6,9,-3)

$\left\{\begin{array}{ccc}-3x-y+z=6\n-3x-y+3z=0\nx-3z=3&|\text{add 3z to both sides}\end{array}\right\n\nx=3+3z\n\n\text{Substitute it to the first and the second equation:}\n\n\left\{\begin{array}{ccc}-3(3+3z)-y+z=6\n-3(3+3z)-y+3z=0\end{array}\right\n\n\text{use distributive property}\n\n\left\{\begin{array}{ccc}-9-9z-y+z=6&|\text{add 9 to both sides}\n-9-9z-y+3z=0&|\text{add 9 to both sides}\end{array}\right\n\n\text{combine like terms}$

$\left\{\begin{array}{ccc}-8z-y=15\n-6z-y=9&|\text{change the signs}\end{array}\right\n\n\underline{+\left\{\begin{array}{ccc}-8z-y=15\n6z+y=-9\end{array}\right}\qquad\text{add both sides of the equations}\n.\qquad-2z=6\qquad\text{divide both sides by (-2)}\n.\qquad\boxed{z=-3}\n\n\text{Put the value of z to the second equation:}\n\n6(-3)+y=-9\n-18+y=-9\qquad\text{add 18 to both sides}\n\boxed{y=9}\n\n\text{Put the value of z to the equation}\ x=3+3z:\n\nx=3+3(-3)\nx=3-9\n\boxed{x=-6}$