What is the intersection of plane TUYX and plane VUYZ? (Image below. Multiple Choice)
Answers
Answer:
B) UY
Step-by-step explanation:
From the given figure, TUYX is one of the side of the rectangular prism and UVYZ is another side of the rectangular prism.
The both sides are intersecting perpendicular in one edge, that is the line segment UY.
You can see it on the figure.
Therefore, the intersecting line is UY.
Answer: B) UY
Step-by-step explanation:
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then Use the method of undetermined coefficients
Then you need to find x′p and x′′p and sub them into equation, that will help you to solve A and B.
And finally you will have this :
3x′′+3x′+7x=9sin(3t)[−27Asin(3t)−27Bcos(3t)]+[9Acos(3t)−9Bsin(3t)]+[7Asin(3t)+7Bcos(3t)]=9sin(3t)(−20A+9B)sin(3t)+(−20B+9A)cos(3t)=9sin(3t)
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Hope this Helped!
Answers
Answer:
y = - x +
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given the line with equation
y = - x + 7 ← in slope- intercept form
with slope m = -
• Parallel lines have equal slopes , then
y = - x + c ← is the partial equation of the parallel line
to find c, substitute the point (3, 3 ) for x/ y into the partial equation
3 = - (3) + c = -
+ c ( add
to both sides )
+
= c , that is
c =
y = - x +
← equation of parallel line
Final answer:
The equation of the line passing through point (3,3) and parallel to y = -(1/6)x + 7 is y = -(1/6)x + 3.5, which is achieved by knowing that parallel lines have the same slope and substituting the coordinates of the given point into the y = mx + b (slope-intercept form) and solving for the y-intercept 'b'.
Explanation:
The question asks for an equation of a line that is parallel to the equation y = -(1/6)x + 7 and also passes through the point (3,3). First, it's significant to understand that parallel lines share the same slope. Looking at the equation y = -(1/6)x + 7, we can see that the slope, or 'm' value, is -1/6. Therefore, the slope of our new line will also be -1/6. The conventional form of the equation for a line is y = mx + b where m is the slope and b is the y-intercept. Since we know the slope and have a point that lies on the line, we can substitute these values into this formula to solve for 'b'.
Here's how we do it:
First, substitute the point's coordinates into the equation for the line: 3 = (-1/6)*3 + b
This simplifies to: 3 = -1/2 + b
Then solving for 'b', we get: b = 3 + 1/2 = 3.5
Therefore, the equation of our new line that is parallel to the original line and passes through the point (3,3) is y = -(1/6)x + 3.5.
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