A ball is dropped off a bridge and it takes 5 seconds to hit the water below. About how fast is the ball traveling just before it hits the water?

Answers

Answer 1
Answer:

Explanation:distance between bridge and water as "x"meters

speed=distance * time

speed= x * 5

speed=5x m/s

Answer 2
Answer:

Final answer:

The speed of a ball dropped off a bridge that takes 5 seconds to reach the ground is calculated using the equation of motion v = gt. With the acceleration due to gravity approximately 9.8 m/s², the ball would be traveling about 49 m/s just before it hits the water.

Explanation:

This question relates to the physics concept of gravity. When an object is dropped off with no initial velocity, the only force acting upon it is gravity. The speed of the falling object can be found using the equation of motion: v = gt, where g is the acceleration due to gravity (approx. 9.8 m/s²) and t is the time the object is in motion. Therefore, for a ball being dropped off a bridge for 5 seconds, the speed just before hitting the water would be approximately 49 m/s (9.8 m/s² * 5s).

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What is the strength of the electric field 0.020 m from a 12 µC charge?

Answers

The electric field strength at a distance of 0.020 m from a 12 µC point charge is approximately 2.69 x 10⁸ N/C.

What is the electric field strength?

The electric field strength (E) at a point near a point charge is given by the equation:

E = k Q / r²

where:

k is Coulomb's constant, equal to 8.99 x 10⁹ Nm²/C²

Q is the magnitude of the point charge in coulombs

r is the distance from the point charge

Substituting the given values:

Q = 12 x 10⁻⁶ C

r = 0.020 m

E = k Q / r²

E = 8.99 x 10⁹ Nm²/C² x 12 x 10⁻⁶ C / (0.020 m)²

E = 2.69 x 10⁸ N/C

So the electric field strength at a distance of 0.020 m from a 12 µC point charge is approximately 2.69 x 10⁸ N/C.

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E = ko * C / d^2 = [9.0x10^9 N/m^2C^2 ]* [12x10^-6C]/[(0.020m)^2] = 2.7^10^8N/C

4. The density and strength of concrete are determined by the ratio of cement and aggregate. Suppose that a contractor has 480 cubic feet of a dry concrete mixture that is 70% sand by volume. How much pure sand must be added to form a new mixture that is 75% sand by volume?

Answers

Answer:

The answer is 96ft^3

Explanation:

T=initial concrete mixture

S1=initial amount of sand

S2=final amount of sand

T2=final amount concrete mixture

C=amount of cement

Data:

T=480Ft^3

 the quantities of the initial mixture are

S=0.7*480=336Ft^3

C=0.3*480=144 Ft^3

 we pose the following equations

144+S2=T2

T2*0.75=S2  

if we solve

S2=144/(1/0.75-1)=432ft^3

to know how much we should add we subtract it from the initial amount of sand

Answer=432ft^3-336ft^3=96ft^3

I need help on this, please tell me what it is.

Answers

Answer:

maria is right.

Explanation:

What much does the earth in tons

Answers

6.58 times 10 to the 21st power short tons

What is the molar mass, in grams, of a mole of an element equal to?A. The number of electrons
B. The atomic weight of the element
C. The atomic number of the element
D. The number of neutrons in the element

Answers

Answer : Molar mass is equal to the atomic weight of the element.

Explanation :

The ratio of the mass of a given substance to the amount of substance is called as the molar mass of that substance. It is denoted by M. Its SI unit is kg/mol but it is usually expressed in g/mol.

In simpler form it is equal to the atomic weight of the substance.

For example, the molar mass of water can be calculated as :

M=2* 1+2(8)=18\ g/mol

Hence, the correct option is (B) "The atomic weight of the element".

The correct answer is B. The atomic weight of the element 

1. The sponge is classified in the. kingdom.

Answers

Answer:

the sponge? huhh what