What is the least What is the least common multiple of four and 12

Answers

Answer 1
Answer:

Answer: LCM(4,12) = 12

Step-by-step explanation:

This of this as singing all the multiples of 4

4, 8, 12.

4 + 4 + 4.

Answer 2
Answer:

Answer:

2

Step-by-step explanation:


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Automobiles traveling on a road with a posted speed limit of 65 miles per hour are checked for speed by a state police radar system. The following is a frequency distribution of speeds. Speed (miles per hour) Frequency 45 up to 55 70 55 up to 65 360 65 up to 75 250 75 up to 85 110 (See the Excel Data File.) The mean speed of the automobiles traveling on this road is the closest to ________.

The length of a rectangle is 12 m.Its width is 15 m.
Find the area and perimeter of this rectangle.

Answers

Answer:

for perimeter you add all sides. so Lenth x2 + width x2 is 24+30 which would equal 54

for area it's Lenth times width so 12 times 15 equals 156

2. Solve the following problems involving simple interest. RecallSimple Interest-INT=PV*r*t
An investor decides to offer a business owner a $45,000 loan at simple interest of 3.5%
per year. Find the total amount in dollars, the investor will receive when the loan is
repaid after 7 years.

Answers

Answer:

A = $56025

Step-by-step explanation:

Given that,

An investor decides to offer a business owner a $45,000 loan at simple interest of 3.5%  per year.

Principal, P = 45,000

Rate of interest, R = 3.5%

We need to find the total amount the investor will receive when the loan is  repaid after 7 years.

The formula for the simple is given by :

I=(PRT)/(100)\n\n=(45000* 3.5* 7)/(100)\n\n=\$ 11025

We know that,

Amount = Principal + simple interest

So,

A = 45,000 + 11025

A = $56025

So, the required amount is equal to $56025.

The average sales per customer at a home improvement store during the past year is $75 with a standard deviation of $12. The probability that the average sales per customer from a sample of 36 customers, taken at random from this population, exceeds $78 is:

Answers

The probability that the average sales per customer from a sample of 36 customers, taken at random from this population, exceeds $78 is 0.0668.

Calculation of the probability:

Since The average sales per customer at a home improvement store during the past year is $75 with a standard deviation of $12.

Here  we need to find out the z score

= 78-75/ 12/ 36

= 1.5

Here we considered normal distribution table, we obtain the area that corresponds to 0.25 to be 0.9332

So,  the average is less or equal to 78.

Now

Subtract from 1 to get the complement.

So,

P(x>78)=1-0.9332

=0.0668

Learn more about probability here: brainly.com/question/24613748

Answer:

0.0668

Step-by-step explanation:

Assuming the distribution is normally distributed with a mean of $75,

with a standard deviation of $12.

We can find the z-score of 78 using;

z=(x-\mu)/((\sigma)/(√(n) ) )

\implies z=(78-75)/((12)/(36) ) =1.5

Using our normal distribution table, we obtain the area that corresponds to 0.25 to be 0.9332

This is the area corresponding to the probability that, the average is less or equal to 78.

Subtract from 1 to get the complement.

P(x>78)=1-0.9332=0.0668

7x(15+4) = (7x ) + (7+4)

Answers

Add the numbers inside the parentheses
7x(15+4)=(7x)+(7+4)
and you get
7x*19= 7x+11

Calculate the product
133x=7x+11

Move variable to the left hand side & change its sign
133x-7x=11

Collect like terms
126x=11

Divide both sides by 126 & you get
x=11/126


Answer: x= 11/126

Hope this helps ʕ•ᴥ•ʔ

Find the measure of 0. (to the nearest tenth).A) 36.9
B) 38.7
C) 51.3
D) 53.1

Answers

Answer:

A) 36.9

Step-by-step explanation:

took the test :)

Answer:

B) 38.7

Step-by-step explanation:

The distribution of the annual incomes of a group of middle management employees approximated a normal distribution with a mean of $37,200 and a standard deviation of $800. About 68% of the incomes lie between what two incomes

Answers

Answer:

68% of the incomes lie between $36,400 and $38,000.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  $37,200

Standard Deviation, σ = $800

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Empirical rule:

  • Almost all the data lies within three standard deviation of mean for a normally distributed data.
  • About 68% of data lies within one standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within three standard deviation of mean.

Thus, 68% of data lies within one standard deviation.

\mu \pm \sigma\n=37200 \pm 800\n=(36400,38000)

Thus, 68% of the incomes lie between $36,400 and $38,000.