The table shows the number of servings for different size cakes at Mimiy's bakery suppose a high school graduation expected 2,889guests how many X-large sheets Cakes should the school order? explain how you solved.

Answers

Answer 1

Answer:

Step-by-step explanation:

From the table given, at Mimi's Bakery, 1 X-Large sheet cake size will give us a number of servings of 120.

To find out how many X-Large cake size the school should order, simply divide the number of expected expected guests by the number of servings the X-Large cake will do.

Given that the score is expecting 2,889 guests, the school should order for:

2,889 ÷ 120 = 24.075 X-Large cakes.

Let's just say, an estimated 24 X-Large size cake should be ordered.

Answer 2

Answer:

Final answer:

To determine the number of X-large sheet cakes the school should order, divide the total number of guests by the number of servings per cake and round up to the nearest whole number.

Explanation:

To determine how many X-large sheet cakes the school should order for 2,889 guests, we need to consult the table provided. The table shows the number of servings for different size cakes. Let's look at the X-large sheet cake row to find out how many servings it provides.

According to the table, the X-large sheet cake serves 64 people. To find out the number of X-large sheet cakes needed for 2,889 guests, we divide the total number of guests by the number of servings per cake:

Total number of guests / Number of servings per X-large sheet cake = Number of X-large sheet cakes needed

Using this formula, we have: 2,889 guests / 64 servings per X-large sheet cake = 45.14 X-large sheet cakes. Since we can't have a fraction of a cake, we round up to 46 X-large sheet cakes. Therefore, the school should order 46 X-large sheet cakes for the high school graduation.

Learn more about Determining the number of X-large sheet cakes needed for a given number of guests here:

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A pool is being drained at a constant rate. The amount of water is a function of the number of minutes the pool has been draining, as shown in the table. Write an equation in slope-intercept form that represents the function. Then find the water in the pool after two and a half hours. Time (mi) 12--------20------50
Volumne (gal) 4962--4754--3974

Answers

The equation in the slope-intercept form is $y=-26x+5274$ and there will be $1374$ gallons of water in the pool after $2$ and a half hours.

The equation of a line that passes through two points $(x_1, y_1)$ and $(x_2, y_2)$ is $(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)$ .

Take points $(12, 4962)$ and $(20, 4754)$ .

Here, $x_1=12, y_1=4962, x_2=20, y_2=4754$ .

The equation is :

$(y-4962)=(4754-4962)/(20-12)(x-12)$

$(y-4962)=(-208)/(8)(x-12)$

$8(y-4962)=-208(x-12)$

$8y-39696=-208x+2496$

$208x+8y-39696-2496=0$

$208x+8y-42192=0$

$8y=-208x+42192$

$y=-(208)/(8)x+(42192)/(8)$

$y=-26x+5274.$

The slope intercept form is $y=mx+c$ , where $m$ is the slope and $c$ is the $y$ -intercept.

After $2$ and a half hours or $150$ minutes.

Put $x=150$ in the equation $y=-26x+5274.$

$y=-26* 150+5274$

$y=-3900+5274$

$y=1374$

So, there will be $1374$ gallons of water in the pool after $2$ and a half hours.

Learn more about slope-intercept form here:

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Answer:

Using the first two values in the table, we can first find the slope to write an equation of a line, so we have

[4754 - 4962 ] / [20 - 12 ] = -26

So we have

y - 4754 = -26(x - 20)

y - 4754 = -26x + 520

y = -26x + 5274

Let's confirm that the amount after 50 minutes is correct

y = -26(50) + 5274 = 3974

So after 2 + 1/2 hrs (150 min) we have

y = -26(150) + 5274 = 1374 gallons

Step-by-step explanation:

A gardener uses 1/3 of a liter of water to water 2/7 of a garden. Watering the entire garden at this rate will require 5/6 , 6/7, 1 1/6 , 1 4/7 liters of water.

Answers

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Answers

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He number of 90° angles formed by the intersections of and the two parallel lines and is .

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