Stefania pours 2 liters of orange juice and 1.5 liters of pineapple juice into a punch bowl. How many kiloliters are in thepunch bowl? Use the metric table to help answer the question
hecto-
100
deka-
10
Metric Table
unit
1
deci-
0.1
centi-
0.01
milli-
0.001
1,000
0.0035 kiloliters
0.035 kiloliters
O 0.35 kiloliters
3.5 kiloliters

Answers

Answer 1
Answer:

Answer:

the correct answer is A (0.0035 kiloliters)

Step-by-step explanation:

i  hope this helps

Answer 2
Answer:

Answer:

A us the correct answer

Step-by-step explanation:

I took the test earlier today and got it right


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ree heights: Cherry trees in a certain orchard have heights that are normally distributed with mean μ = 119 inches and standard deviation σ = 17 inches. Use the TI-84 PLUS calculator to answer the following. Round the answers to at least four decimal places. (a) What proportion of trees are more than 130 inches tall? (b) What proportion of trees are less than 90 inches tall? (c) What is the probability that a randomly chosen tree is between 95 and 105 inches tall? Part: 0 / 30 of 3 Parts Complete Part 1 of 3 What proportion of trees are more than 130 inches tall? The proportion of trees that are more than 130 inches tall is .

Answers

Answer:

a) 0.2588

b) 0.044015

c) 0.12609

Step-by-step explanation:

Using the TI-84 PLUS calculator

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

From the question, we know that:

μ = 119 inches

standard deviation σ = 17 inches

(a) What proportion of trees are more than 130 inches tall?

x = 130 inches

z = (130-119)/17

= 0.64706

Probabilty value from Z-Table:

P(x<130) = 0.7412

P(x>130) = 1 - P(x<130) = 0.2588

(b) What proportion of trees are less than 90 inches tall?

x = 90 inches

z = (90-119)/17

=-1.70588

Probability value from Z-Table:

P(x<90) = 0.044015

(c) What is the probability that a randomly chosen tree is between 95 and 105 inches tall?

For x = 95

z = (95-119)/17

= -1.41176

Probability value from Z-Table:

P(x = 95) = 0.07901

For x = 105

z = (105 -119)/17

=-0.82353

Probability value from Z-Table:

P(x<105) = 0.2051

The probability that a randomly chosen tree is between 95 and 105 inches tall

P(x = 105) - P(x = 95)

0.2051 - 0.07901

= 0.12609

Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)answer the following questions:

1. Obtain the expression in the Canonical Disjunctive Normal Form

2. Obtain the expression in the Canonical Conjunctive Normal Form

3. Derive the truth table for both the Minterms and Maxterms

4. Obtain the minimized SOP and POS

5. Draw the resultant circuit diagram for the minimized SOP

Answers

Answer:

Step-by-step explanation:

F (X, Y , Z)=Σm(0,1, 2 , 4 , 6) mixterms

= π M ( 3, 5, 7 ) maxterms

Please view the remaining part of the solution in the file attached below.

Which of the following is the equation of the line that is parallel toy= 3/5x+ 8 and goes through point (-10,4)?
Select one:
a. y = 5/3x + 20 2/3
b. y=-5/3x – 12 2/3
c.y= 3/5x + 10
d. y = -3/5x-2

Answers

Answer:

C

Step-by-step explanation:

We want to write the equation of a line that is parallel to:

y=(3)/(5)x+8

And also passes through (-10, 4).

Remember that parallel lines have the same slope.

The slope of our old line is 3/5.

Therefore, the slope of our new line is also 3/5.

We know that it passes through (-10, 4). So, we can use the point-slope form:

y-y_1=m(x-x_1)

Where m is the slope and (x₁, y₁) is a point.

So, let's substitute 3/5 for m and let (-10, 4) be our (x₁, y₁). This yields:

y-(4)=(3)/(5)(x-(-10))

Simplify:

y-(4)=(3)/(5)(x+10)

Distribute on the right:

y-4=(3)/(5)x+6

Add 4 to both sides:

y=(3)/(5)x+10

So, our answer is C.

And we're done!

Step-by-step explanation:

Hey there!

The equation of a st.line passing through point (-10,4) is ;

(y-y1)= m1(x-x1) [one point formula]

Put all values.

(y - 4) = m1( x + 10)..........(i)

Another equation is; y = 3/5 + 8.............(ii)

From equation (ii)

Slope (m2) = 3/5 [ By comparing equation with y = mx+c].

As per the condition of parallel lines,

Slope of equation (i) = slope of equation (ii)

(i.e m1 = m2 )

Therefore, the value of m1 is 3/5.

Putting value of slope in equation (i).

(y - 4) =  (3)/(5) (x + 10)

(y - 4) =  (3)/(5) x +  (3)/(5)  * 10

(y - 4) =  (3)/(5) x + 6

y =  (3)/(5) x + 10

Therefore the required equation is y = 3/5x + 10.

Hopeit helps...

Identify the initial amount a and the growth factor b in the exponential function. A(x) = 680 • 4.3x

Answers

A(x)=680\cdot4.3^x\n\na=680;\ b=4.3

At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a research paper and a final exam. Let F be the even that a course has a final exam. Let R be the event that a course requires a research paper. (a) Find the probability that a course has a final exam or a research paper. Your answer is : (b) Find the probability that a course has NEITHER of these two requirements. Your answer is :

Answers

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

An angle is one-fourth of a circle. How many one-degree angles can be made from this angle?

Answers

Answer:

Step-by-step explanation: Right Angle - 4 times around. Around the angle ( 90 ) You would need 90 angles or 4 to make 360.