Which would be heavier—A ball of lead with a diameter of 2.00 cm or a cylinder of iron with a diameter of 3.00 cm and height of 8.00 cm.

Answers

Answer 1

Answer:

Explanation:

i think a ball of lead with a diameter of 2.00 cm heavier

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An object of mass 2 kg has a linear momentum of magnitude 6 kg • m/s. What is this object’s kinetic energy?
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(a) What is the magnitude of the tangential acceleration of a bug on the rim of a 12.5-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 75.0 rev/min in 3.80 s
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Which of the following is not accurate when describing solids? A. Solids are better conductors of heat than liquids B. The amount of pressure exerted by a solid is solely dependent on its mass. C. Solids with many air pockets are good insulators. D. Molecules in solids are closer together than molecules in liquids.

What characteristics consider as consider as foundation of an effective officiating official?A competence
B compassion
C confidence
D courage

Answers

Answer:

Explanation:

What is the Earth's magnetic field is known asa. electrosphere
b. biosphere
c. asthenosphere
d. magnetosphere

Answers

The correct answer is magnetosphere.

hello

the earh's magnetic field is known as
magnetosphere

I hope it helps you

A 92.6 kg weight-watcher wishes to climb a mountain to work off the equivalent of a large piece of chocolate cake rated at 735 (food) Calories. How high must the person climb? The acceleration due to gravity is 9.8 m/s 2 and 1 food Calorie is 103 calories. Answer in units of km.

Answers

Answer:

349 m

Explanation:

Parameters given:

Mass of climber, m = 92.6 kg

Amount of food calories = 735

1 food calorie = 103 calories

735 food calories = 75705 calories

1 joule is equal to 0.239 calories. Therefore, 75705 calories will be 316749.72 joules.

Hence, this is the amount of work the climber must do work off the food he ate.

Work done is given as:

W = Force * distance

W = m * g * h

h = W/(m * g)

h = 316749.72/(92.6 * 9.8)

h = 349 m

The amoeba is a protozoan that moves with _____. flagella
cilia
pseudopodia
none of the above

Answers

The amoeba is a protozoan that moves with the pseudopodia. Pseudopodia is known as the false foot. Thus, the correct option is C.

What is Pseudopodia?

A pseudopod or pseudopodia is a temporary arm-like projection of a eukaryotic cell membrane such as algae that is emerged in the direction of movement of the organism. These are filled with cytoplasm. Pseudopodia primarily consist of the actin filaments and may also contain microtubules and other intermediate filaments.

Pseudopodia are responsible for the amoeboid movement, which includes sliding or crawling-like form of locomotion. This motion is visible in amoeba. The formation of cytoplasmic projections, or pseudopodia, on the cell surface, pulling the cell along in the direction of food, is a characteristic of the microscopic unicellular protozoans known as amoeba.

Therefore, the correct option is C.

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The amoeba is a protozoan that moves with pseudopodia.

Answer: Pseudopodia

At height h above the surface of Earth, the gravitational acceleration is What is h? Note: The radius of Earth is 6380 km.

Answers

The acceleration of gravity is inversely proportional to
the square of the distance from Earth's center.

The acceleration of gravity is 9.8 m/s² on the Earth's surface ...
6380 km from the center.

If the acceleration of gravity at 'h' is 4.9 m/s² ... 1/2 of what it is
on the surface, then the distance from the center is

(6380 x √2) = 9,023 km (rounded) ,

and 'h' is the distance above the surface

= (9,023 - 6,380) = 2,643 km (rounded) .

The function f(x)equalsnegative 0.25 (x minus 2 )squared plus 8 models the path of a volleyball when the player is 2 feet from the net. The height of the net is 7 ft comma 4 in. Will the ball go over the net? What if the player moves back so she is 4 feet from the net? Explain.

Answers

Answer:

The ball will go over the net when she's standing 2 feet away from the net, but not at 4 ft from the net

Explanation:

Suppose $f(x) = -0.25(x-2)^2 + 8$ then when the player is 2ft from the net, we can plug in x = 2:

$f(2) = -0.25(2-2)^2 + 8 = 0 + 8ft$

As 8 feet > 7 ft 4 in, the ball will go over the net

If the player moves back so that she's 4 feet from the net, plug in x = 4:

$f(4) = -0.25(4 - 2)^2 + 8 = -1 + 8 = 7 ft$

As 7 ft < 7 ft 4 in, this time the ball will NOT go over the net

Final answer:

The function models the path of a volleyball when the player is 2 feet from the net and will the ball go over the net at different distances.

Explanation:

The function f(x) = -0.25(x-2)^2 + 8 models the path of a volleyball when the player is 2 feet from the net. To determine if the ball will go over the net, we need to compare the height of the ball's path with the height of the net.

First, let's convert the height of the net to feet. The height, 7 ft 4 in, is equivalent to 7.33 feet. Now, substitute x = 2 into the function to find the height of the ball when the player is 2 feet from the net. f(2) = -0.25(2-2)^2 + 8 = 8 ft.

The ball will go over the net because the height of the ball, 8 feet, is greater than the height of the net, 7.33 feet.

If the player moves back so she is 4 feet from the net, substitute x = 4 into the function: f(4) = -0.25(4-2)^2 + 8 = 10 ft. The ball would still go over the net, as the height of the ball, 10 feet, is greater than the net's height.

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Other Questions

A child's toy consists of a spherical object of mass 50 g attached to a spring. One end of the spring is fixed to the side of the baby's crib so that when the baby pulls on the toy and lets go, the object oscillates horizontally with a simple harmonic motion. The amplitude of the oscillation is 6 cm and the maximum velocity achieved by the toy is 3.2 m/s . What is the kinetic energy K of the toy when the spring is compressed 5.1 cm from its equilibrium position?Problem-Solving Strategy: Simple Harmonic Motion II: EnergyThe energy equation, E=12mvx2+12kx2=12kA2, is a useful alternative relationship between velocity and position, especially when energy quantities are also required. If the problem involves a relationship among position, velocity, and acceleration without reference to time, it is usually easier to use the equation for simple harmonic motion, ax=d2xdt2=−kmx (from Newton’s second law) or the energy equation above (from energy conservation) than to use the general expressions for x, vx, and ax as functions of time. Because the energy equation involves x2 and vx2, it cannot tell you the sign of x or of vx; you have to infer the sign from the situation. For instance, if the body is moving from the equilibrium position toward the point of greatest positive displacement, then x is positive and vx is positive.IDENTIFY the relevant conceptsEnergy quantities are required in this problem, therefore it is appropriate to use the energy equation for simple harmonic motion.SET UP the problem using the following stepsPart AThe following is a list of quantities that describe specific properties of the toy. Identify which of these quantities are known in this problem.Select all that apply.Select all that apply.maximum velocity vmaxamplitude Aforce constant kmass mtotal energy Epotential energy U at xkinetic energy K at xposition x from equilibriumPart BWhat is the kinetic energy of the object on the spring when the spring is compressed 5.1 cm from its equilibrium position?Part CWhat is the potential energy U of the toy when the spring is compressed 5.1 cm from its equilibrium position?

The heat capacity of a sample should be divided by which quantity to find the specific heat capacity?

Johannes Kepler is known for which discovery in astronomy? discovering planets around other starsdetermining planetary laws of motionrecording 20 years of data about planetary motionproposing the heliocentric model of the solar system

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